A and B are nonzero integers, is A < 5B?

Statement 1:
Doesn't tell about the sign of A or B,so we cannot answer the question.
INSUFFICIENT

Statement 2:
Doesn't tell anything about A.
INSUFFICIENT

Combining statements 1 and 2.
from statement 2 we know that B is positive and greater than 3.
If we combine this with statement 1, we know for sure that 5B is greater than A as A can only take values for which A/B<5
SUFFICIENT

Answer:- C

Statement (1) is insufficient for not considering any specific sign of A and B

Statement (2) is insufficient for not providing information/sign about A

Together ,Combining Two statements satisfy the condition A<5B,where B is always positive and values of A <20


So the Correct Answer is C

VERITAS PREP OFFICIAL SOLUTION:

The momentum is all toward answer choice A. Statement one can be rephrased as “A < 5B” which mirrors the question stem and seems to be sufficient. Statement 2 does not seem particularly relevant. Who cares if B > 3? Well you should actually. Statement 1 can only be rephrased as “A < 5B” provided that B is a positive number. If B is a negative number then the inequality gets flipped and the statement becomes “A > 5B .”

The GMAT uses your desire to try to be clever against you. Mirroring the question stem is a great strategy on test day and statement 1 appears to be perfect for this technique. Statement 2 is also very carefully crafted. If the statement had said “B > 0” it would be too obvious that “positive and negative” number property is in play on this question. So instead they use the seemingly random “B > 3” but of course if B is greater than 3 it must be positive as well. So we know that B cannot be negative and therefore it is safe to rephrase statement 1 as “A < 5B.” Since we relied on statement 2 the correct answer is C rather than A. In my experience at least twice as many students choose answer choice A than choose C.

Without number picking:

(1)A/B < 5

\(\frac{A}{B}-5<0\)

\(\frac{A-5B}{B}<0\)

So (A-5B) AND B have different signs
Case 1: B>0 then A-5b<0
Case 2: B<0 then A-5B>0
Insuff

(2)B>2.
Noting about a,insuff.

Using (1) and (2):
From (2) We know B>0 so A-5b<0
Hence A>5b