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Re: What is the value of x? |x+2|+|x3|=|2x+3| [#permalink]
On substituting options
3+2 = 5
C
But on removing bar and considering two cases could not match with options
Case 1 and 2
( x + 2 ) + ( x-3) = 2x + 3
2x - 1 = 2x + 3
2x - 2x = 4
?
Can anyone explain. Thanks
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Re: What is the value of x? |x+2|+|x3|=|2x+3| [#permalink]
@genxer123 Can you explain how you go 1 in case 4?? isn't

Case 4
|x+2|+|x−3|=|2x+3|

−x−2−x+3=−2x−3
-2x+1 = -2x-3
1=-3

which is invalid???
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Re: What is the value of x? |x+2|+|x3|=|2x+3| [#permalink]
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RashmiT wrote:
@genxer123 Can you explain how you go 1 in case 4?? isn't

Case 4
|x+2|+|x−3|=|2x+3|

−x−2−x+3=−2x−3
-2x+1 = -2x-3
1=-3

which is invalid???


Hi RashmiT

Yes you are correct in your observation. Case 4 by generis is incorrect.

This question is best solved through options. if you go for any other approach then you will have to work through multiple ranges.
Another option to remove mod is to square both sides but it will result in a complex polynomial equation.
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Re: What is the value of x? |x+2|+|x3|=|2x+3| [#permalink]
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RashmiT wrote:
@genxer123 Can you explain how you go 1 in case 4?? isn't

Case 4
|x+2|+|x−3|=|2x+3|

−x−2−x+3=−2x−3
-2x+1 = -2x-3
1=-3

which is invalid???

RashmiT , you are correct.
My brain clearly was not working well. :dazed :?
Nice catch, +1, thank you, and my apologies.

With two absolute value terms in an equation, you can open mods.

With more than two mods?

If, as here, the answers are before you, use them.

If answers are not before you, use

"Critical Method" see chetan2u, Absolute Modulus, A Better Understanding

and Bunuel , "3-steps approach for complex problems," Absolute Value Modulus, 3-steps approach

And "Graphical Method," chetan2u , Absolute Modulus, A Better Understanding

(You probably know what to do when there are more than two absolute value expressions. I post these links just in case you might need them, but mostly to help people who have not seen the excellent posts to which the links refer.)
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Re: What is the value of x? |x+2|+|x3|=|2x+3| [#permalink]
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broall wrote:
What is the value of x?

\(|x+2|+|x-3| = |2x+3|\)

A. -5
B. -2
C. 1
D. 4
E. 7


This is a very simple question should be solved in 1 min or else you can complete Quant session. You just write down the equation and start substituting values. Never ever think of solving by taking "x" greater than 3 , then x greater than -1.5, then x greater than -2.

So we start substituting ,

A . becomes 11 = 8 x is not equal to -5


B. Become 5 = 1. Not satisfies.

C. 5 = 5. So x =1 . Done.
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Re: What is the value of x? |x+2|+|x3|=|2x+3| [#permalink]
broall wrote:
What is the value of x?

\(|x+2|+|x-3| = |2x+3|\)

A. -5
B. -2
C. 1
D. 4
E. 7


Fastest way is to utilize the answer choices

(C) is the only choice that works.

|1+2| + |1-3| = |2(1)+3|
3+2=|2+3|
5=5
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Re: What is the value of x? |x+2|+|x3|=|2x+3| [#permalink]
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