Last visit was: 26 Apr 2024, 02:33 It is currently 26 Apr 2024, 02:33

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Retired Moderator
Joined: 19 Oct 2018
Posts: 1878
Own Kudos [?]: 6296 [30]
Given Kudos: 704
Location: India
Send PM
Most Helpful Reply
Tutor
Joined: 16 Oct 2010
Posts: 14823
Own Kudos [?]: 64928 [9]
Given Kudos: 426
Location: Pune, India
Send PM
Manager
Manager
Joined: 27 Apr 2009
Status:Not Applying
Posts: 122
Own Kudos [?]: 501 [5]
Given Kudos: 35
Location: India
Schools: HBS '14 (A)
GMAT 1: 730 Q51 V36
Send PM
General Discussion
SVP
SVP
Joined: 24 Nov 2016
Posts: 1720
Own Kudos [?]: 1344 [1]
Given Kudos: 607
Location: United States
Send PM
Re: A shopkeeper bought an article for Rs.1000 and marked its price as Rs. [#permalink]
1
Kudos
nick1816 wrote:
A shopkeeper bought an article for Rs.1000 and marked its price as Rs.2160. He gave three successive discounts of a%, b% and c%, where a + b + c = 50. If he made a profit of x% finally, then what is the difference between maximum value of x and minimum value of x ?

A. 10
B. 17
C. 24
D. 30
E. 33.33


maximum value: when successive discounts are equal, (a,b,c)=50/3%
minimum value: largest possible successive discount, (a,b,c)=50,0,0%

original net%=sale/cost-1=2160/1000-1=2.16-1=1.16=116%
min. net%=2160(1-50/100)/1000-1=1.08-1=0.08=8%
max. net%=2160(1-50/3/100)^3/1000-1=216(5/6)^3/100-1…
max. net%=216(125/216)/100-1=1.25-1=0.25=25%
max-min net%=25-8=17%

Ans (B)
Intern
Intern
Joined: 22 Oct 2019
Posts: 31
Own Kudos [?]: 19 [0]
Given Kudos: 70
Location: India
GMAT 1: 660 Q50 V30
Send PM
Re: A shopkeeper bought an article for Rs.1000 and marked its price as Rs. [#permalink]
Bunuel Please explain.
Manager
Manager
Joined: 12 Oct 2019
Posts: 76
Own Kudos [?]: 39 [0]
Given Kudos: 92
Location: India
Concentration: Marketing, General Management
GMAT 1: 720 Q48 V41
GMAT 2: 730 Q50 V39
GMAT 3: 760 Q50 V44
GPA: 4
WE:Information Technology (Computer Software)
Send PM
Re: A shopkeeper bought an article for Rs.1000 and marked its price as Rs. [#permalink]
VeritasKarishma Can u plz explain this? How to approach this problem?
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 18761
Own Kudos [?]: 22055 [0]
Given Kudos: 283
Location: United States (CA)
Send PM
Re: A shopkeeper bought an article for Rs.1000 and marked its price as Rs. [#permalink]
Expert Reply
nick1816 wrote:
A shopkeeper bought an article for Rs.1000 and marked its price as Rs.2160. He gave three successive discounts of a%, b% and c%, where a + b + c = 50. If he made a profit of x% finally, then what is the difference between maximum value of x and minimum value of x ?

A. 10
B. 17
C. 24
D. 30
E. 33.33


Recall that the order in which we apply the discount doesn’t matter (for example, a discount of 10% followed by a discount of 20% is same as a discount of 20% followed by a discount of 10%). Also, let’s assume that any values of a, b, and c can be 0 and they can also be decimals or fractions.

The minimum discounted price of the article after 3 discounts occurs when a, b, and c are as far apart as possible. That is, if we let a = 50, b = 0, and c = 0, then the minimum discounted price is 2160 x 0.5 x 1 x 1 = 1080.

The maximum discounted price of the article after 3 discounts occurs when a, b, and c are as close to each other as possible. That is, if we let a = b = c = 50/3 = 16⅔ (notice that 16⅔% = 1/6), then the maximum discounted price is 2160 x 5/6 x 5/6 x 5/6 = 2160 x 125/216 = 1250.

In the first case (minimum discounted price), the profit is 80, so the profit margin is 8%. In other words, the minimum value of x is 8. In the latter case (maximum discounted price), the profit is 250, so the profit margin is 25%. In other words, the maximum value of x is 25.

So the difference between the maximum and minimum values of x is 25 - 8 = 17.

Answer: B
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32678
Own Kudos [?]: 822 [0]
Given Kudos: 0
Send PM
Re: A shopkeeper bought an article for Rs.1000 and marked its price as Rs. [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: A shopkeeper bought an article for Rs.1000 and marked its price as Rs. [#permalink]
Moderators:
Math Expert
92929 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne