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# Running at the same constant rate, 6 identical machines can

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Math Expert
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Running at the same constant rate, 6 identical machines can [#permalink]

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20 Aug 2012, 03:05
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93% (01:56) correct 7% (02:08) wrong based on 1081 sessions

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Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

Practice Questions
Question: 23
Page: 155
Difficulty: 600
[Reveal] Spoiler: OA

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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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12 Apr 2013, 10:11
1
KUDOS
Let's take the approach that uses the answer choices to eliminate wasted time.

270/6 is a little less than 300/60 = 50 bottles per minute per machine. 10 machines = 500 per minute. 4 minutes worth = 2000 bottles as being slightly HIGHER than the answer we need.

Looking at the answers it is clear...we can only choose (B) 1800 bottles starting with an upper bound of 2000.
Math Expert
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Kudos [?]: 105810 [0], given: 11581

Re: Running at the same constant rate, 6 identical machines can [#permalink]

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20 Aug 2012, 03:05
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SOLUTION

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

6 machines produce 270 bottles per minute;
1 machine produces 270/6=45 bottles per minute;
10 machines produce 45*10=450 bottles per minute;

In 4 minutes 10 machines produce 450*4=1,800 bottles.

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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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20 Aug 2012, 08:30
Ans=(270*10*4)/(6)
=1800

option B.
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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20 Aug 2012, 09:52
Each machine can produce (270/6) = 45 bottles per minute

45 * 10 = 450 bottles per minute

450 * 4 = 1800 bottles in 4 minutes.
Math Expert
Joined: 02 Sep 2009
Posts: 38798
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Kudos [?]: 105810 [0], given: 11581

Re: Running at the same constant rate, 6 identical machines can [#permalink]

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24 Aug 2012, 02:22
SOLUTION

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

6 machines produce 270 bottles per minute;
1 machine produces 270/6=45 bottles per minute;
10 machines produce 45*10=450 bottles per minute;

In 4 minutes 10 machines produce 450*4=1,800 bottles.

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Running at the same constant rate, 6 identical machines can prod [#permalink]

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22 Apr 2013, 18:33
270/6 = 45 BPM X 10 Machines = 450 BPM X 4 MIN = 1,800.

Kudos if this is easier!
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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10 Sep 2014, 01:08
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

Practice Questions
Question: 23
Page: 155
Difficulty: 600

6 identical machine produce 270bottles/min then 1machine - 45bottles/min

10 machine - 450 bottles/min

for 4 minutes--> 1800
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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15 Nov 2014, 21:52
better as fractions:

270*10/6*4/1=1800

B
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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20 Nov 2014, 01:59

Equation would be

$$= \frac{270}{6} * 10 * 4 = 1800$$
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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17 Dec 2015, 21:50
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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25 May 2016, 07:11
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

To solve this problem, we first want to determine the rate of each machine. Since each machine works at the same constant rate, each machine’s rate is 270/6 = 45 bottles per minute. Now since there are 10 such machines, the rate of the 10 machines together is 10 x 45 = 450 bottles per minute.

Finally, we are asked to determine the number of bottles these 10 machines can produce in 4 minutes. Thus:

rate x time = work

450 x 4 = 1,800 bottles

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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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25 May 2016, 08:55
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

Practice Questions
Question: 23
Page: 155
Difficulty: 600

6 machines can produce 270 bottles, so 10 machines can produce 270*10/6

This can be produced in 1 minute. Total bottles that can be produced in 4 minutes :-
270*10*4/6= 1800 bottles

B is the answer
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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05 Jul 2016, 05:04
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

Practice Questions
Question: 23
Page: 155
Difficulty: 600

r*t=w
we have 6 machine here so

6*(r*1)=270
r*1=45===> r=45

r*t=w

we got 10 machine
10*(r*t)=w
10*(45*4)=1800

t was 4 according to the question
B
Re: Running at the same constant rate, 6 identical machines can   [#permalink] 05 Jul 2016, 05:04
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# Running at the same constant rate, 6 identical machines can

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