Last visit was: 17 May 2024, 21:47 It is currently 17 May 2024, 21:47
Toolkit
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

# Sets A and B each consist of three terms selected from the 5

SORT BY:
Tags:
Show Tags
Hide Tags
Manager
Joined: 23 Aug 2012
Status:Never ever give up on yourself.Period.
Posts: 115
Own Kudos [?]: 1150 [21]
Given Kudos: 35
Location: India
Concentration: Finance, Human Resources
GMAT 1: 570 Q47 V21
GMAT 2: 690 Q50 V33
GPA: 3.5
WE:Information Technology (Investment Banking)
Math Expert
Joined: 02 Sep 2009
Posts: 93334
Own Kudos [?]: 624560 [4]
Given Kudos: 81898
Retired Moderator
Joined: 17 Sep 2013
Posts: 279
Own Kudos [?]: 1223 [0]
Given Kudos: 139
Concentration: Strategy, General Management
GMAT 1: 730 Q51 V38
WE:Analyst (Consulting)
Manager
Joined: 02 May 2014
Status:Applied
Posts: 95
Own Kudos [?]: 46 [0]
Given Kudos: 46
Location: India
Concentration: Operations, General Management
GMAT 1: 690 Q47 V38
GPA: 3.35
WE:Information Technology (Computer Software)
Re: Sets A and B each consist of three terms selected from the 5 [#permalink]
Set B product divisible by 22 i.e should have 2 and 11.
Set A average =4 i.e sum =12 i.e should have 2,3 ,7
a/c to statement 1 set B product not divisible by 5 so set be does not contain 5 so what are the options either 3 or 7. So in Set be could be either of the following 2,3,11 or 2,7, 11. In both the cases it shares two integers with set b i.e 2,3 or 2,7. Hence sufficient.

A/c to statement 2 product of the terms in Set b divisible by 14 so must have 2 and 7 set B has 2,7 and 11 as the integers.Now Set be has two integers common with set A i.e 2 and 7. hence sufficient. Hope this explanation helps.
Intern
Joined: 13 May 2014
Posts: 4
Own Kudos [?]: 3 [1]
Given Kudos: 15
Schools: ISB '16
Sets A and B each consist of three terms selected from the 5 [#permalink]
1
Bookmarks
1st 5 prime integers are 2, 3 , 5, 7, 11

Given: Average of terms in Set A is 4
=> Sum of terms in Set A is (4*3) = 12

2+3+7 = 12
Hence, terms in Set A are 2, 3, 7

Given: Product of terms in Set B is divisible by 22 which implies that 2 and 11 are definitely in Set B

Statement (1) Product of the terms in Set B are not divisible by 5
Means that 5 is definitely not a part of Set B

So, Set B could be either (2,3,11) or (2,7,11), so the two sets share 2 terms. Hence, statement is sufficient.

Statement (2) Product of the terms in Set B are divisible by 14
Means that 2 and 7 are definitely a part of Set B and since the question stem has already established that 2 and 11 are a part of Set B, the remaining term is 7. It completely discards 3 and 5.
Hence, Set B contains 2, 7, 11. Which means that 2 terms are shared by both sets, i.e. 2 and 7. Hence, statement is sufficient. (D)
Intern
Joined: 18 May 2017
Posts: 9
Own Kudos [?]: 13 [0]
Given Kudos: 116
WE:Corporate Finance (Health Care)
Sets A and B each consist of three terms selected from the 5 [#permalink]
I am not comprehending how each statement alone is sufficient . Without looking at the statements I can arrive at (7,3,2) & (2,3,11) . If I use statement one alone I can arrive at (2,3,11) to form 66 which is divisible by 22. I need statement two to arrive at the LCM of 22 and 14 ( 154) . If one was to use 66 or 154, set A and B will share two terms . Is the answer D because there are no other primes that can form a multiple of 22 that perhaps share one or 3 terms? I am really confused about this data sufficiency thing . Your help will be appreciated.
Manhattan Prep Instructor
Joined: 04 Dec 2015
Posts: 935
Own Kudos [?]: 1545 [3]
Given Kudos: 115
GMAT 1: 790 Q51 V49
GRE 1: Q170 V170
Re: Sets A and B each consist of three terms selected from the 5 [#permalink]
3
Kudos
NanaA wrote:
Without looking at the statements I can arrive at (7,3,2) & (2,3,11)

Without looking at the statements, Set A has to be (2, 3, 7). But, there are actually some other possibilities for Set B. B could be (2,3,11), (2,7,11), OR (2,5,11).

Data Sufficiency questions can never be answered without any info from the statements. So, if you look at a question and you feel like you can narrow it down to a single scenario without using either of the statements, it means you've left something out.

Statement 1 narrows B down to either (2, 3, 11) or (2, 7, 11). (You've missed the second one there.) Make sure you go all the way back to the question and answer it! If B is (2, 3, 11), then the answer ("how many terms are shared by both sets?") is two. If B is (2, 7, 11), the answer is still two.

That means statement 1 lets you answer the question definitively. So, it's sufficient.

Statement 2 narrows it down to just (2, 7, 11). Go back to the question. How many terms are shared? The answer is again, two. That's a single answer, so it's sufficient.
Non-Human User
Joined: 09 Sep 2013
Posts: 33057
Own Kudos [?]: 828 [0]
Given Kudos: 0
Re: Sets A and B each consist of three terms selected from the 5 [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Re: Sets A and B each consist of three terms selected from the 5 [#permalink]
Moderator:
Math Expert
93334 posts