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03 Jul 2013, 06:27
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
25% (02:58) correct
75%
(02:38)
wrong
based on 176
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Six friends live in the city of Monrovia. There are four natural attractions around Monrovia – a waterfall, a safari, a lake and some caves. The friends decide to take a vacation together at one of these attractions. To select the attraction, each one of them votes for one of the attractions. What is the probability that each attraction gets at least one vote?
A. 220/4^6
B. 480/4^6
C. 1,080/4^6
D. 1560/4^6
E. 5760/4^6
A. 220/4^6
B. 480/4^6
C. 1,080/4^6
D. 1560/4^6
E. 5760/4^6
The answer is 1560/(4^6). I was wondering if we can get to this answer by removing the cases where [an "attraction" gets zero votes] can be subtracted from the [total number of cases].
24 Mar 2014, 02:12
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v1gnesh
The cases when attractions get zero votes are:
{6, 0, 0, 0}
{5, 1, 0, 0}
{4, 2, 0, 0}
{4, 1, 1, 0}
{3, 2, 1, 0}
{3, 1, 1, 1}
{2, 2, 2, 0}
{2, 2, 1, 1}
Counting those is harder than a direct approach when we need to count only:
{3, 1, 1, 1} --> \(\frac{4!}{3!}*C^3_6*3!=480\).
{2, 2, 1, 1} --> \(\frac{4!}{2!2!}*C^2_6*C^2_4*C^1_2=1,080\).
The total number of ways in which the 6 friends can vote = 4*4*4*4*4*4 = 4^6.
P = (480 + 1,080)/4^6 = 1560/4^6.
Hope it helps.
28 Apr 2014, 10:11
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niyantg
For each attraction to get at least one vote we should have the following distributions of 6 votes: {3, 1, 1, 1} or {2, 2, 1, 1}.
A - B - C - D (attractions)
{3, 1, 1, 1} --> \(\frac{4!}{3!}*C^3_6*3!=480\), where:
\(\frac{4!}{3!}\) is the # assignments of {3, 1, 1, 1} to attractions (A gets 3, B gets 1, C gets 1, D gets 1; A gets 1, B gets 3, C gets 1, D gets 1; A gets 1, B gets 1, C gets 3, D gets 1; A gets 1, B gets 1, C gets 1, D gets 3);
\(C^3_6\) is selecting the 3 people who will vote for the attraction with 3 votes;
3! is the distribution of other 3 votes among the remaining attractions.
The same logic applies to {2, 2, 1, 1} case.
As for 4^6: each friend can vote in 4 ways (for waterfall, safari, lake or caves). So, the total number of ways in which the 6 friends can vote = 4*4*4*4*4*4 = 4^6.
Hope it's clear.
