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manrasingh
Six friends live in the city of Monrovia. There are four natural attractions around Monrovia – a waterfall, a safari, a lake and some caves. The friends decide to take a vacation together at one of these attractions. To select the attraction, each one of them votes for one of the attractions. What is the probability that each one of them votes for the same attraction?


(A) (1/6)^4

(B) (1/6)^3

(C) (1/4)^6

(D) (1/4)^5

(E) (1/4)

Bunuel
can you please tell why (1/4)^6 is not the answer here?

Think of it this way: the probability of all six friends voting for one specific attraction, say the waterfall, is (1/4)^6. The same probability applies for each of the other attractions—safari, lake, and caves. Thus, the probability of them all choosing the same attraction, regardless of which one it is, would be (1/4)^6 + (1/4)^6 + (1/4)^6 + (1/4)^6 = 4*(1/4)^6 = (1/4)^5.

Answer: D.

Hope it's clear.
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