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fresinha12, in 2) we are given that 5-x>0 Consider x=3, then sqrt((x-5)^2) = sqrt((3-5)^2) = sqrt((-2)^2) = sqrt (4) = 2 or -2, which can be either equal to 5-x = 5-3=2, or not (-2), Insuff. Am I missing smth?

fresinha12, in 2) we are given that 5-x>0 Consider x=3, then sqrt((x-5)^2) = sqrt((3-5)^2) = sqrt((-2)^2) = sqrt (4) = 2 or -2, which can be either equal to 5-x = 5-3=2, or not (-2), Insuff. Am I missing smth?

Hi Thanks Jallenmorris, I did get more answers.

The OA is D

atletikos, since S2 says 5-x>0 and the Q stem does not ask you if x-5=5-x. It asks whether ( x-5)^2= (5-x)^2 and so the sign of x or x-5 is not considered.