Bunuel wrote:

The amount of electrical current that flows through a wire is inversely proportional to the resistance in that wire. If a wire currently carries 4 amperes of electrical current, but the resistance is then cut to one-third of its original value, how many of electrical current will flow through the wire?

A. 3/4 amperes

B. 4/3 amperes

C. 4 amperes

D. 8 amperes

E. 12 amperes

Kudos for a correct solution.

Directly Proportional : The relation when due to increase in one variable, other variable needs to be increased is called a Directly Proportional Relationship e.g. Speed and Distance. "More Distance in same time require more speed and Vise versa"

Inversely Proportional : The relation when due to increase in one variable, other Variable needs to be Decreased is called a Inversely Proportional Relationship e.g. Speed and Time. "More Speed will cover a specific Distance in Less time and Vise versa"Given: Current is INVERSELY Proportional to Resistance

i.e. Current = (1/Resistance)*Constant [Removal of Proportional sign always comes with a constant]

i.e.

\(Current_1 / Current_2 = Resistance_2 / Resistance_1\)If Initially Resistance = \(R_1\)

Then, \(R_2 = (1/3)*R_1\)

Current after reducing Resistance, \(C_2 = ?\)

Current Before reducing Resistance, \(C_1 = 4\)

\(4 / C_2 = (1/3)*R_1 / R_1\)

i.e. \(C_2 = 4*3 = 12\) Amperes

Answer: Option

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