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The table above shows present rates and proposed rates for electricity

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HKD1710
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The table above shows present rates and proposed rates for electricity [#permalink] New post   16 Dec 2018, 07:38
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The table above shows present rates and proposed rates for electricity for residential customers. For which of the monthly kilowatt-hours shown would the proposed rate be the greatest percent increase over the present rate?

(A) 500
(B) 1,000
(C) 1,500
(D) 2,000
(E) Each of the percent increases is the same.

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B
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Re: The table above shows present rates and proposed rates for electricity [#permalink] New post   11 Feb 2019, 02:14
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HKD1710 wrote:


The table above shows present rates and proposed rates for electricity for residential customers. For which of the monthly kilowatt-hours shown would the proposed rate be the greatest percent increase over the present rate?

(A) 500
(B) 1,000
(C) 1,500
(D) 2,000
(E) Each of the percent increases is the same.

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Recall that smaller the denominator, larger the number.

You need to compare the percentage increases:

500 -> 2/24 = 1/12

1000 -> 4/41 = 1/10.2

1500 -> 5/57 = 1/11.4

2000 -> 6/73 = 1/12

The smallest denominator belongs to 1000 units and hence the percentage increase is the highest.

Answer (B)
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Re: The table above shows present rates and proposed rates for electricity [#permalink] New post   16 Dec 2018, 11:50
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Solution



Given:
    • The table shows present rates and proposed rates for electricity for residential customers.

To find:
    • For which monthly kilowatt-hours shown, the proposed rate shown the greatest percent increase over the present rate.

Approach and Working:

    • For 500 kilowatt-hours:
      o Percentage change= \(\frac{{26-24}}{24} *100 = \frac{2}{24}*100= \frac{1}{12} *100 =\frac{100}{12}=8.33%\)

    • For 1,000 kilowatt-hours:
      o Percentage change= \(\frac{{45-41}}{41} *100 = \frac{4}{41}*100= \frac{1}{10.25} *100 =\frac{100}{10.25}=9.756%\)

    • For 1,500 kilowatt-hours:
      o Percentage change= \(\frac{{62-57}}{57} *100 = \frac{5}{57}*100= \frac{1}{11.4}*100 =\frac{100}{11.4}=8.77%\)

    • For 2,000 kilowatt-hours:
      o Percentage change= \(\frac{{79-73}}{73} *100 = \frac{6}{73}*100= \frac{1}{12.166} *100 =\frac{100}{12.166}=8.219%\)

Hence, for 1000 kilowatt-hours, the percentage change is greatest.

Hence, the correct answer is option B.

Answer: B
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Re: The table above shows present rates and proposed rates for electricity [#permalink] New post   11 Feb 2019, 00:39
[quote="HKD1710"]

The table above shows present rates and proposed rates for electricity for residential customers. For which of the monthly kilowatt-hours shown would the proposed rate be the greatest percent increase over the present rate?

(A) 500
(B) 1,000
(C) 1,500
(D) 2,000
(E) Each of the percent increases is the same.

[/textarea]

Some calculation ahead, still For the ease of calculation lets remove 100 from KW units value, this helped a lot

(Proposed Price - Initial Price)/ Initial Price * 100

Proposed price = units * cost

Only for B you will get maximum value of 9

for A [130-120/120] * 100 = 8%

for B 450-410 / 410 * 100 = 9%
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Re: The table above shows present rates and proposed rates for electricity [#permalink] New post   12 Jun 2023, 02:15
Hello from the GMAT Club BumpBot!

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Re: The table above shows present rates and proposed rates for electricity [#permalink]
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