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Re: There are two alloys, A and B, of copper and zinc. The ratio (by weigh [#permalink]
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Given: There are two alloys, A and B, of copper and zinc. The ratio (by weight) of copper and zinc in alloy A is 8 : 1 and that in alloy B is 2 : 7. It is found that, if alloy A and alloy B are mixed in a certain ratio, the weights of copper and zinc in the resultant alloy are also in that ratio.

Asked: What is that ratio?

Let the ratio be x.

Copper = 8x + 2
Zinc = x + 7

(8x+2)/(x+7) = x
8x + 2 = x^2 + 7x
x^2 - x - 2 = 0
(x-2)(x+1) = 0
x = 2

IMO D
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Re: There are two alloys, A and B, of copper and zinc. The ratio (by weigh [#permalink]
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