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D
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Difficulty:
55%
(hard)
Question Stats:
69% (02:36) correct
31%
(02:59)
wrong
based on 752
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Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A. 4 min
B. 6 min
C. 9 min
D. 8 min
E. 12 min
A. 4 min
B. 6 min
C. 9 min
D. 8 min
E. 12 min
18 Oct 2010, 22:52
Kudos
Bookmarks
D)
A worked for 18 mins so amount of work done in 18 mi ns.
1/24(18)=3/4
work left=1-3/4=1/4
complete work is done by B in 32 m ins
so 1/4 work will be done in =1/4*32=8 mins
A worked for 18 mins so amount of work done in 18 mi ns.
1/24(18)=3/4
work left=1-3/4=1/4
complete work is done by B in 32 m ins
so 1/4 work will be done in =1/4*32=8 mins
18 Oct 2010, 23:38
Kudos
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jimmy86
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A)4 min
B)6 min
C)9 min
D)8 min
E)12 min
I have the answer with me but need an easier solution. Please help with an explanation.
A)4 min
B)6 min
C)9 min
D)8 min
E)12 min
I have the answer with me but need an easier solution. Please help with an explanation.
Lets say that you shut down pipe B after x mins. And that pipe A runs for exactly 18mins.
Fraction of tank filled in x mins = (x/24) + (x/32)
The logic being that if a pipe fills a tank in m minutes, running for n minutes (n<m) , it will fill n/m of the tank
The rest of the tank is filled by A alone in 18-x mins
Therefore, (18-x)/24 = 1 - (x/24 + x/32)
3/4 - x/24 = 1 - x/24 - x/32
x/32 = 1/4
x = 8min
Answer is (d)
