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Two pipes can fill a tank in 24 min and 32 min respectively.
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Updated on: 18 Oct 2010, 20:58
5
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Difficulty:
75% (hard)
Question Stats:
63% (02:46) correct 37% (03:03) wrong based on 391 sessions
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Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is fill in 18 min ?
A)4 min B)6 min C)9 min D)8 min E)12 min
I have the answer with me but need an easier solution. Please help with an explanation.
I think question is incomplete as there is no reference for B.
A worked for 18 mins so amount of work done in 18 mi ns. 1/24(18)=3/4 work left=1-3/4=1/4
complete work is done by B in 32 m ins so 1/4 work will be done in =1/4*32=8 mins
Agree that A worked for last 18 min But the 1/4th work left was done by A and B both working together. Thus they work at a combined rate of 7/96. Thus time would be 1/4*96/7 = 3.4 approx . Am still confused _________________
--- Jimmy
Life`s battles dont always go, To the stronger or faster man; But sooner or later the man who wins, Is the man who THINKS HE CAN .
KUDOS me if you feel my contribution has helped you.
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A)4 min B)6 min C)9 min D)8 min E)12 min
I have the answer with me but need an easier solution. Please help with an explanation.
Lets say that you shut down pipe B after x mins. And that pipe A runs for exactly 18mins.
Fraction of tank filled in x mins = (x/24) + (x/32) The logic being that if a pipe fills a tank in m minutes, running for n minutes (n<m) , it will fill n/m of the tank The rest of the tank is filled by A alone in 18-x mins Therefore, (18-x)/24 = 1 - (x/24 + x/32) 3/4 - x/24 = 1 - x/24 - x/32 x/32 = 1/4 x = 8min
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A)4 min B)6 min C)9 min D)8 min E)12 min
I have the answer with me but need an easier solution. Please help with an explanation.
Lets say that you shut down pipe B after x mins. And that pipe A runs for exactly 18mins.
Fraction of tank filled in x mins = (x/24) + (x/32) The logic being that if a pipe fills a tank in m minutes, running for n minutes (n<m) , it will fill n/m of the tank The rest of the tank is filled by A alone in 18-x mins Therefore, (18-x)/24 = 1 - (x/24 + x/32) 3/4 - x/24 = 1 - x/24 - x/32 x/32 = 1/4 x = 8min
Answer is (d)
Yes i get it .Thanks a LOT!!! Any idea where i can get more practice and theory on RATE Problems?
_________________
--- Jimmy
Life`s battles dont always go, To the stronger or faster man; But sooner or later the man who wins, Is the man who THINKS HE CAN .
KUDOS me if you feel my contribution has helped you.
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A)4 min B)6 min C)9 min D)8 min E)12 min
I have the answer with me but need an easier solution. Please help with an explanation.
Lets say that you shut down pipe B after x mins. And that pipe A runs for exactly 18mins.
Fraction of tank filled in x mins = (x/24) + (x/32) The logic being that if a pipe fills a tank in m minutes, running for n minutes (n<m) , it will fill n/m of the tank The rest of the tank is filled by A alone in 18-x mins Therefore, (18-x)/24 = 1 - (x/24 + x/32) 3/4 - x/24 = 1 - x/24 - x/32 x/32 = 1/4 x = 8min
Answer is (d)
Yes i get it .Thanks a LOT!!! Any idea where i can get more practice and theory on RATE Problems?
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A)4 min B)6 min C)9 min D)8 min E)12 min
I have the answer with me but need an easier solution. Please help with an explanation.
When the job is undefined, we can plug in our own number for the job. Let tank = 96.
Rate for A = w/t = 96/24 = 4/min Rate for B = w/t = 96/32 = 3/min Combined rate is 4+3 = 7/min
Now let's plug in the answer choices, which represent how long the tanks work together.
Answer choice C: w = r*t = 7*9 = 63. Remaining work = 96-63 = 33, which is not divisible by A's rate of 4. Eliminate C.
Answer choice D: w = r*t = 7*8 = 56. Remaining work = 96-56 = 40. For A alone, t = w/r = 40/4 = 10. Total time = 8+10 = 18. Success!
GMAT and GRE Tutor Over 1800 followers Click here to learn more GMATGuruNY@gmail.com New York, NY If you find one of my posts helpful, please take a moment to click on the "Kudos" icon. Available for tutoring in NYC and long-distance. For more information, please email me at GMATGuruNY@gmail.com.
Re: Two pipes can fill a tank in 24 min and 32 min respectively.
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20 Feb 2015, 09:54
2
jimmy86 wrote:
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A. 4 min B. 6 min C. 9 min D. 8 min E. 12 min
Pipe A will run for 18 minutes
Sp pipe A will do = 18/24 = 3/4 portion of the work
left work is 1/ 4
Just assume that what will be 1/4 if multiplied with 1/32 (B's rate )
Re: Two pipes can fill a tank in 24 min and 32 min respectively.
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19 Feb 2016, 18:43
jimmy86 wrote:
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A. 4 min B. 6 min C. 9 min D. 8 min E. 12 min
good question..this is how I solved.. 1 pipe in 8 minutes fills 1/3 of the tank 2 pipe in 8 minutes fills 1/4 of the tank after 8 minutes, we'll have 7/12 of the tank. suppose we stop the second pipe. after another 8 minutes, the tank fills 1/3, or 4/12. total, we have 11/12 of the tank after 16 minutes.
we know that tank 1 fills 4/12 in 8 minutes, then 2/12 in 4 minutes, and 1/12 in 2 minutes. we can thus see, that we need to stop the second pipe after 8 minutes. then 1 alone in 10 minutes will fill the tank.
Re: Two pipes can fill a tank in 24 min and 32 min respectively.
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25 Feb 2016, 16:31
jimmy86 wrote:
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
Re: Two pipes can fill a tank in 24 min and 32 min respectively.
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05 Mar 2016, 03:47
jimmy86 wrote:
Two pipes can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min ?
A. 4 min B. 6 min C. 9 min D. 8 min E. 12 min
Assume total unit = 96 Pipe A does 96/24=4 units Pipe B does 96/32=3 units Total effort =7 units Let required time be x Work done by (A+B)= 7x Work done by only A after pipe B is closed = 4(18-x) Hence, \(7x + 4(18-x)=96\) x=8 Ans D
Re: Two pipes can fill a tank in 24 min and 32 min respectively.
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