Given: Two trains (Train A and Train B) leave their stations at exactly 6 pm, travelling towards each other from stations exactly 60 miles apart. There are no other stops between these two stations.
Asked: What time does Train B arrive at its destination?
Let the speeds of train A & train B be vA & vB respectively.
1. Train A travels twice as fast as Train B.
vA = 2vB
The time when train B arrive at its destination = 60/vB.
Since vA or vB is unknown
NOT SUFFICIENT
2. At 6:40 pm, the two trains pass each other.
Time taken for the trains to pass each other = 60/(vA + vB) = 40/60 = 2/3
vA + vB = 60*3/2 = 90 km/h
The time when train B arrive at its destination = 60/vB.
Since vB is unknown
NOT SUFFICIENT
(1) + (2)
1. Train A travels twice as fast as Train B.
vA = 2vB
2. At 6:40 pm, the two trains pass each other.
Time taken for the trains to pass each other = 60/(vA + vB) = 40/60 = 2/3
vA + vB = 60*3/2 = 90 km/h
vB = 30 km/h
The time takebn by train B arrive at its destination = 60/vB = 60/30 = 2 hours
The time when train B arrive at its destination = 6 + 2 = 8 pm
SUFFICIENT
IMO C