What is the area of isosceles triangle X?

If the perimeter of an isosceles triangle is 15 and all the sides are integer, then there is only one possible triangle (4,4,7) This information would have been sufficient to calculate the area, had the perimeter been 15 instead of 16. The logic is: sum of any two sides of a triangle has to be greater than the third side .

DJ

No I stand corrected. (6,6,3) and (7,7,1) are also possible. The point I am making is to look for such possible cases.

DJ

Hello akashganga
The task doesn't say anything about "all the sides are integer"

Thanks. Yes, you are right.

**goes to error log and select Careless from the dropdown menu**

Area of isosceles triangle = ½ * base * height
1. Largest side =6, insufficient to find area of isosceles traingle
2. Sum of all sides =16, side can be any value so not sufficient

C )1+2 largest side is 6 so rest 2 are 5, enough to find out the value of area of isosceles triangle. Sufficient

Hence answer is C
Thanks,

Platinum GMAT Official Solution:

In a triangle, the side opposite the largest angle will be the longest. Correspondingly, the side opposite the smallest angle will be the shortest.

Evaluate Statement (1) alone.

The side opposite the single largest angle must be the single largest side in the triangle. Since an isosceles triangle contains two equal sides and two equal angles yet we know that a "single largest angle" exists, the side opposite the single largest angle cannot be one of these equal sides. If the longest side of an isosceles triangle were one of its equal sides, both angles opposite the equal sides would have equal measurement and there would be no single largest angle as Statement (1) indicates there must be.

The single largest side must be the base since the two other angles will have equivalent measurements and thus the length of the sides opposite them will be equivalent. The two equal sides must be less than 6cm (otherwise, the angle opposite the base would not be the single largest angle in the triangle). To reiterate, the two angles opposite the equivalent sides must be smaller than the angle opposite the base (otherwise the angle opposite 6cm side would not be the single largest angle).

The two equal sides must be longer than 3cm. Otherwise a closed triangle could not be formed (i.e., the lines would not connect).

Draw a diagram with the information we know:

AC = 6
3cm < AB < 6cm
3cm < BC < 6cm

Although we know the base, we know nothing about the height, BD. Without knowing that a definitive value for the height exists, we cannot calculate the area of the triangle.

Statement (1) is NOT SUFFICIENT.

Evaluate Statement (2) alone.

Since triangle X is an isosceles triangle, the perimeter is formed by adding two equal sides and a third side. Set up an equation to reflect this:

2L + N = 16 where L is the length of the equivalent sides of the triangle and N is the length of the other side.

There are many different combinations of L and N that would give a different area. Assume that N is the base:

If N = 4 and L = 6, then the height of the triangle (via the Pythagorean theorem) would be the square root of 32, which is 5.65

If N = 5 and L = 5.5, then the height of the triangle (via the Pythagorean theorem) would be the square root of 24, which is 4.89.

Without being able to determine that a definitive value for the base and height exists, we cannot calculate the area of the triangle.

Statement (2) is NOT SUFFICIENT.

Evaluate Statements (1) and (2) together.

Write equations that are derived from the information in both Statements:

(1) Base = 6cm
(2) 2L + B = 16

Combine the two equations:
2L + 6 = 16
L = 5

We now have a right triangle formed by half the base (AD = 3), the height (BD = unknown), and an equal side (AB = 5).


AC = 6
AD = 3
AB = BC = 5
Note: Since the triangle is isosceles, the height (or line BD) must perfectly bisect the base. This is because angles A and C are equal and sides AB and BC are equal. Further, angle D is right since it is the height and the height is by definition a right angle.

Through the Pythagorean theorem, BD must equal 4:
(AD)^2 + (BD)^2 = (AB)^2
9 + (BD)^2 = 25
(BD)^2 = 16
BD = 4

The area of triangle X must be (1/2)Base*Height = 3(4) = 12

Statements (1) and (2), when taken together, are SUFFICIENT.

Since Statement (1) alone is NOT SUFFICIENT and Statement (2) alone is NOT SUFFICIENT, but Statements (1) and (2), when taken together are SUFFICIENT, answer C is correct.

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