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# What is the largest integer k such that 10! is divisible by

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Intern
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Joined: 07 Aug 2011
Posts: 37
Location: India
Schools: WBUT - Class of 2011
GMAT Date: 01-06-2014
GPA: 2.6
WE: Research (Education)
What is the largest integer k such that 10! is divisible by [#permalink]

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Updated on: 11 Jun 2014, 02:13
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Difficulty:

5% (low)

Question Stats:

82% (00:25) correct 18% (00:40) wrong based on 174 sessions

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What is the largest integer k such that 10! is divisible by $$10^{k}$$ ?

A. 1
B. 2
C. 3
D. 4
E. 5

M23-11

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Arindam Sur

Originally posted by arindamsur on 11 Jun 2014, 01:54.
Last edited by arindamsur on 11 Jun 2014, 02:13, edited 2 times in total.
Math Expert
Joined: 02 Sep 2009
Posts: 46267
Re: What is the largest integer k such that 10! is divisible by [#permalink]

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11 Jun 2014, 02:07
2
3
arindamsur wrote:
What is the largest integer k such that 10! is divisible by 10^k ?

A. 1
B. 2
C. 3
D. 4
E. 5

M23-11

Trailing zeros:
Trailing zeros are a sequence of 0's in the decimal representation (or more generally, in any positional representation) of a number, after which no other digits follow.

Fro example, 125000 has 3 trailing zeros (125000);

The number of trailing zeros in the decimal representation of n!, the factorial of a non-negative integer n, can be determined with this formula:

$$\frac{n}{5}+\frac{n}{5^2}+\frac{n}{5^3}+...+\frac{n}{5^k}$$, where k must be chosen such that 5^(k+1)>n

It's more simple if you look at an example:

How many zeros are in the end (after which no other digits follow) of 32!?
$$\frac{32}{5}+\frac{32}{5^2}=6+1=7$$ (denominator must be less than 32, $$5^2=25$$ is less)

So there are 7 zeros in the end of 32!

The formula actually counts the number of factors 5 in n!, but since there are at least as many factors 2, this is equivalent to the number of factors 10, each of which gives one more trailing zero.

BACK TO THE ORIGINAL QUESTION:

According to above 10! has $$\frac{10}{5}=2$$ trailing zeros. So, the largest integer k such that 10! is divisible by 10^k is 2.

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Hope it helps.
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Re: What is the largest integer k such that 10! is divisible by [#permalink]

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05 Apr 2018, 08:18
It's indeed a trailing zero concept, but the numbers mentioned in question made it way simpler.
Concept - https://gmatclub.com/forum/everything-a ... 85592.html

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Ujjwal
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Re: What is the largest integer k such that 10! is divisible by   [#permalink] 05 Apr 2018, 08:18
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# What is the largest integer k such that 10! is divisible by

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