|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Updated on: 26 May 2013, 09:16
Originally posted by atalpanditgmat on 26 May 2013, 08:56.
Last edited by Bunuel on 26 May 2013, 09:16, edited 1 time in total.
Last edited by Bunuel on 26 May 2013, 09:16, edited 1 time in total.
Edited the question.
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
41% (01:59) correct
59%
(01:48)
wrong
based on 834
sessions
History
Date
Time
Result
Not Attempted Yet
If n is a positive integer and 10^n is a factor of m, what is the value of n?
(1) m is the product of the first positive 40 numbers .
(2) n > 8*m/40!
(1) m is the product of the first positive 40 numbers .
(2) n > 8*m/40!
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
26 May 2013, 09:18
Kudos
Bookmarks
If n is a positive integer and 10^n is a factor of m, what is the value of n?
Given that \(m=10^n*k\) for some positive integer k.
(1) m is the product of the first positive 40 numbers --> \(m=40!\) --> \(40!=10^n*k\). The number of trailing zeros of 40! is 40/5+40/25=8+1=9 (check here: everything-about-factorials-on-the-gmat-85592.html). So, 40! ends with 9 zeros, which means that n could be from 1 to 9, inclusive. Not sufficient.
(2) n > 8*m/40!. Clearly not sufficient.
(1)+(2) From (1) \(m=40!\), thus from (2) \(n>\frac{8*40!}{40!}=8\). Since from (1) we also have that \(1\leq{n}\leq{9}\), then n=9. Sufficient.
Answer: C.
Similar question to practice: if-d-is-a-positive-integer-and-f-is-the-product-of-the-first-126692.html
Hope it helps.
Given that \(m=10^n*k\) for some positive integer k.
(1) m is the product of the first positive 40 numbers --> \(m=40!\) --> \(40!=10^n*k\). The number of trailing zeros of 40! is 40/5+40/25=8+1=9 (check here: everything-about-factorials-on-the-gmat-85592.html). So, 40! ends with 9 zeros, which means that n could be from 1 to 9, inclusive. Not sufficient.
(2) n > 8*m/40!. Clearly not sufficient.
(1)+(2) From (1) \(m=40!\), thus from (2) \(n>\frac{8*40!}{40!}=8\). Since from (1) we also have that \(1\leq{n}\leq{9}\), then n=9. Sufficient.
Answer: C.
Similar question to practice: if-d-is-a-positive-integer-and-f-is-the-product-of-the-first-126692.html
Hope it helps.
mvictor
Board of Directors
Joined: 17 Jul 2014
Last visit: 14 Jul 2021
Posts: 2,116
Own Kudos:
Given Kudos: 236
Location: United States (IL)
Concentration: Finance, Economics
Schools: Stanford '20 (WD)
GMAT 1: 650 Q49 V30
GPA: 3.92
WE:General Management (Transportation)
Products:
19 Nov 2015, 20:49
Kudos
Bookmarks
oh man..completely forgot about trailing zeroes..
did the long way to see how many numbers of factors have 5 and 2...
did the long way to see how many numbers of factors have 5 and 2...
