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Re: x and n are positive integers, such that 7x = 10^n – 1. What is the sm [#permalink]
I got the correct option C but using the cyclicity method. As 7x+1 = 10^n , I plugged in values for x until I noticed the last digit to be repeated which was at x=11 (digit 8, 7+1=8, 7(11)+1=78) . Then I divided 99 by the cyclicity factor 11 which equals 9 and the 9th value had a 4 as its unit digit same as choice C. Is this method valid or a complete fluke? Would appreciate your feedback
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Re: x and n are positive integers, such that 7x = 10^n – 1. What is the sm [#permalink]
Numairrr wrote:
I got the correct option C but using the cyclicity method. As 7x+1 = 10^n , I plugged in values for x until I noticed the last digit to be repeated which was at x=11 (digit 8, 7+1=8, 7(11)+1=78) . Then I divided 99 by the cyclicity factor 11 which equals 9 and the 9th value had a 4 as its unit digit same as choice C. Is this method valid or a complete fluke? Would appreciate your feedback



How much time did it take?
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Re: x and n are positive integers, such that 7x = 10^n – 1. What is the sm [#permalink]
Bunuel wrote:
x and n are positive integers, such that \(7x = 10^n – 1\). What is the 99th smallest possible value of n?

A. 582
B. 588
C. 594
D. 606
E. 612




The way we can approach this is through only trial and error and putting values in.

Are we sure about that this a GMAT question?
Caus it takes me far more than two minutes to solve.
Thankyou in advance.
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Re: x and n are positive integers, such that 7x = 10^n 1. What is the sm [#permalink]
The faster we get to the value of 'n', the lesser time it will take to solve this. Note: 10^3/7, gives a remainder of - 1. So, 10^3/7 X 10^3/7, give a remainder of 1 {(-1)(-1)}. So, 10^6 - 1 is divisible by 7.
Ans. 6x99 = 594
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Re: x and n are positive integers, such that 7x = 10^n 1. What is the sm [#permalink]
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Re: x and n are positive integers, such that 7x = 10^n 1. What is the sm [#permalink]
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