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Yves can paint a certain fence in 1/2 the time it takes Marcel to pain

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Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post Updated on: 26 Jul 2017, 21:16
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Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

(1) Yves can paint the fence by himself in 3 hours.
(2) Working together, each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.

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Originally posted by NoHalfMeasures on 19 Dec 2015, 02:47.
Last edited by Bunuel on 26 Jul 2017, 21:16, edited 1 time in total.
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 19 Dec 2015, 02:49
S1) Vyes can do work in 3hrs. Marcel can do the same work in 6 hrs. V+M can do the same work in 3*6/(3+6). SUFF
St2) No info on anytime . INSUFF

Ans A
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 18 Feb 2016, 08:08
regarding statement2:
Say Marcel can finish the work in x hrs. Then Vyes can finish the same work in 2x hrs. So they together can finish the work in
(2x^2)/3x hrs
The statement says, this time is equal to 'half the time it would take Marcel alone'. Thus
(2x^2)/3x = 2x/2 --> 2/3 = 1 What'm I doing wrong here?
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 03 May 2016, 11:05
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NoHalfMeasures wrote:
Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

(1) Yves can paint the fence by himself in 3 hours.
(2) Working together, each at his own constant rate, they can paint the fence in 1/2 the time it would take Marcel, working alone, to paint the fence.


Dear experts,

Please advise how statement-2 is not suffcient
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 29 May 2016, 02:30
1
smartguy595 wrote:
NoHalfMeasures wrote:
Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

(1) Yves can paint the fence by himself in 3 hours.
(2) Working together, each at his own constant rate, they can paint the fence in 1/2 the time it would take Marcel, working alone, to paint the fence.


Dear experts,

Please advise how statement-2 is not suffcient


Remember that the stem asks us for the number of hours - an explicit value - it would take both of them to paint the fence. From the stem we know that Yves is twice as fast as Marcel, but we do not know what this is in hours. It could be that Yves alone uses 1 hour and Marcel 2 hours, or it could be that Yves alone uses 3 hours and Marcel 6 hours. This would give different answers to the combined time that they use to paint the fence. Therefore, as Statement 2 doesn't provide any explicit value - a value that we can relate the speed of Yves to that of Marcel - statement 2 is not sufficient.
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 29 May 2016, 03:07
2
1
NoHalfMeasures wrote:
Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

(1) Yves can paint the fence by himself in 3 hours.
(2) Working together, each at his own constant rate, they can paint the fence in 1/2 the time it would take Marcel, working alone, to paint the fence.



Key to solving such problem is to realize that rates are additive.

Statement (1)
Yves can paint the fence in 3 hours. Therefore in one hour Y can paint (1/3) fence

Now it is given that Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence.

So Marcel can paint the fence in 6 hours.
In other words, M can paint (1/6) fence in one hour.

in one hour both can paint (\(\frac{1}{3}\)+\(\frac{1}{6}\)) fence in one hour

This is (\(\frac{2}{6}\)+\(\frac{1}{6}\)) = \(\frac{1}{2}\))

Together in an hour they paint (1/2) fence. they can paint the fence in two hours. Sufficient.

Statement (2)
Working together, each at his own constant rate, they can paint the fence in 1/2 the time it would take Marcel, working alone, to paint the fence.

Suppose M completes fence in x hours.
So Y competes fence in x/2 hours (this is given)

Also given when they work together they complete fence in x/2 hours. --> This appears poblematic. Has to be less than x/2.

In one hour say M paints (1/x) part of fence.
In one hour say Y paints (2/x) part of fence.
So in one hour both will paint (3/x) part of fence.
In other words they will complete fence in 1/ (3/x) = (x/3) hours.

(x/3) = (x/2)

This gives no solution for x.

Not sufficient.
Hence Answer is A
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 26 Jul 2017, 10:20
1
This question is posted incorrectly. It should read:

Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

(1) Yves can paint the fence by himself in 3 hours.
(2) Working together, each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 26 Jul 2017, 21:15
grassmonkey wrote:
This question is posted incorrectly. It should read:

Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

(1) Yves can paint the fence by himself in 3 hours.
(2) Working together, each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.

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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain  [#permalink]

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New post 13 Aug 2017, 15:33
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Re: Yves can paint a certain fence in 1/2 the time it takes Marcel to pain &nbs [#permalink] 13 Aug 2017, 15:33
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