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Re: A box contains balls of two sizes – big and small – and different colo [#permalink]
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Probability (Blue ball) = 1/4
Probability (Not Blue) = Probablity (other colour) = 3/4

To find Probability (Neither Blue nor small) = Probability (other colour and Big)

Statement 1 : Probability (Not small = Big ) = 5/8
Probability small = 3/8
Can't calculate anything from this..
Insufficient

Statement 2 :
Probability (small and other colour) = 9/40
Probability (big and other colour) = 3/4 - 9/40 = 21/40
Sufficient


Answer B
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Re: A box contains balls of two sizes – big and small – and different colo [#permalink]
Let the total number of balls be 40 (which is the LMC of denominators of the given probabilities).
The question translates to :
A box contains balls of two sizes – big and small – and different colors. Number of blue balls is 10 . How many balls are neither blue nor small?

(1) Number of balls not small is 25

(2) Number of balls that are small but not blue is 9

Now treat this as a double matrix problem.
GMAT Club Bot
Re: A box contains balls of two sizes – big and small – and different colo [#permalink]
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