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At a certain baseball game attended by 2,000 people, 800 people like

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Bunuel
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At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   06 Apr 2016, 01:16
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59% (01:58) correct 41% (02:09) wrong based on 182 sessions
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At a certain baseball game attended by 2,000 people, 800 people like eating popcorn, and 300 people like eating both popcorn and peanuts. At most, how many people like eating peanuts?

(1) At least 700 people do not like eating popcorn or peanuts.
(2) At least 1,200 people do not like eating peanuts.
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D
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ravisinghal
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   06 Apr 2016, 02:38
Like Popcorn Don't like Popcorn

Like Peanuts 300 ?
Don't like peanuts 500 B
---------------------------------------------------
1800 A 2000


Now as per Statement 1 :- A+B > 700 which does not say anything about ?
Statement 2 :- B >= 1200 which again does not confirm the number of people like peanuts

combining both statements again does not say anything about ?

Hence E should be the answer
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At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   06 Apr 2016, 03:01
Popcorn(only) + Peanuts(only) + Both + Neither = 2000 --- (1)
Popcorn(only) + Both = 800
Both = 300 --> Popcorn(only) = 800 - 300 = 500

N(Peanuts) = Peanuts(only) + Both = ?

St1: Neither >= 700. Since question asks atmost, fix the value of Neither to 700.
Substitute in (1) --> Peanuts(only) + Both = 2000 - (500 + 700) = 800.
Sufficient

St2: Popcorn(only) + Neither >= 1200
Popcorn(only) = 500 --> Neither >=700 --> Peanuts(only) <= 500

Since the question asks atmost(maximum) how many like peanuts, we have to fix the value of 'Neither' to minimum --> Neither = 700
Hence, Peanuts(only) + Both = 500 + 300 = 800
Sufficient

Answer: D
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   06 Apr 2016, 04:16
Expert Reply
ravisinghal wrote:
Like Popcorn Don't like Popcorn

Like Peanuts 300 ?
Don't like peanuts 500 B
---------------------------------------------------
1800 A 2000


Now as per Statement 1 :- A+B > 700 which does not say anything about ?
Statement 2 :- B >= 1200 which again does not confirm the number of people like peanuts

combining both statements again does not say anything about ?

Hence E should be the answer


Hi,

we are looking for EXACT number but AT THE MOST..
so relook in your solution and you will find you both statements are sufficient
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   07 Apr 2016, 09:12
ravisinghal wrote:
Like Popcorn Don't like Popcorn

Like Peanuts 300 ?
Don't like peanuts 500 B
---------------------------------------------------
1800 A 2000


Now as per Statement 1 :- A+B > 700 which does not say anything about ?
Statement 2 :- B >= 1200 which again does not confirm the number of people like peanuts

combining both statements again does not say anything about ?

Hence E should be the answer


Both the statements are enough to find the MAXIMUM value, which is 800. The answer should be (D).
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gatreya14
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   26 Nov 2016, 15:35
Can someone please explain how statement 2 adds additional info? The info provided in the q stem alone is sufficient to derive info provided in statement 2, is it not?

From the q stem alone (black : given info from q stem; red : info you can derive from q stem).

................. PopCorn...........Not PopCorn...... Total
Peanuts............300.........
Not Peanuts........500
Total...............800........... 1200..................2000
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yezz
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   02 Jan 2017, 06:19
relations in 2 overlapping sets


when "neither" is maxed overlap is maxed and thus both is maxed and accordingly "only set A" and "only set B" are both minimised , and vice versa.

let Peanuts set = A and pop set = B and Peanuts only = a and Pop only = b

Total = a+b+both+neither

(a+b) = total -both -neither , total = 2000, both = 300, b= 500

thus a = 2000-500-300-neither and to max a we need min neither

from 1

neither min = 700 thus a = 500.... suff

from 2

min (b+neither ) = 1200 thus min neither is 1200-500 = 700 ... same info as in 1.... suff

D
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   07 Sep 2017, 00:18
Pop + Pea - Both + Neither = 2000
Both = 300
Pop = 800
=> Pea + Neither = 2000 + 300 - 800 = 1500

(1) At least 700 people do not like eating popcorn or peanuts.

--> Neither >= 700
--> 1500 - Pea >= 700
--> Pea =< 800

Max(Pea)=800
Suff.

(2) At least 1,200 people do not like eating peanuts.
--> Min (Pea) = 1200
Also, Max(Pea)= Max(1500 - Neither)= 1500 with Neither = 0

Suff.
So D is the answer.

Posted from my mobile device
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink] New post   11 Jul 2020, 01:29
At least 700 people do not like eating popcorn or peanuts - Should this not consider all scenarios except the scenario where people like both popcorn and peanuts? The solutions provided make sense if the statement mentioned 'At least 700 people like neither popcorn nor peanuts'. I know I am testing verbal interpretation skills in a quant question, but would love if I can get some clarity around this.
Bunuel
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Re: At a certain baseball game attended by 2,000 people, 800 people like [#permalink]
11 Jul 2020, 01:29
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Bunuel
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