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How much greater is the combined area in square inches of the front an

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Bunuel
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How much greater is the combined area in square inches of the front an [#permalink] New post   11 Feb 2015, 06:36
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How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?

A. 50%
B. 87%
C. 100%
D. 187%
E. 200%

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C
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rajthakkar
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Re: How much greater is the combined area in square inches of the front an [#permalink] New post   11 Feb 2015, 07:15
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IMO C

Area of 11by17 sheet 11*17*2

Area of 11by8.5 sheet 11*8.5*2

Area difference in percent with respect to smaller sheet

=((11*34-11*17)/11*8.5*2)*100
=100%

Whats the OA?
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Re: How much greater is the combined area in square inches of the front an [#permalink] New post   12 Feb 2015, 01:22
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Answer = C. 100%

Just look at the dimensions (no calculation needed)

With dimension 11 same, the other dimension 17 is twice than 8.5

Twice means 100% more
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Re: How much greater is the combined area in square inches of the front an [#permalink] New post   12 Feb 2015, 01:48
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How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?

A. 50%
B. 87%
C. 100%
D. 187%
E. 200%


Area of sheet A = 11*17
Area of sheet B = 11*8.5
Difference in Area = 11*8.5
Required % = (11*8.5)*100/(11*8.5)% = 100%

OA = C
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Re: How much greater is the combined area in square inches of the front an [#permalink] New post   16 Feb 2015, 05:56
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Bunuel wrote:
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?

A. 50%
B. 87%
C. 100%
D. 187%
E. 200%

Kudos for a correct solution.


VERITAS PREP OFFICIAL SOLUTION

Correct Answer: C

Because we're concerned with the percentage difference between the two sheets of paper, we don't need to calculate the areas if it's easier to simply compute the difference in percent/ratio terms. The area of the larger sheet is 11 * 17 * 2, while the area of the smaller sheet is 11 * 8 . 5 * 2 . Because the 11s cancel each other out, and 17 = 8.5 * 2, the difference between the two sheets is that the larger sheet has an additional factor of 2. Therefore, the larger sheet is twice the area of the smaller. Because this is a percentage difference problem, we need to determine how much must be added to the smaller to equal the larger. We would need to double it, or add one more sheet, to do so, so the larger sheet is 100% greater (the initial sheet plus an entire new one) than the smaller, and the correct answer is C.
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Re: How much greater is the combined area in square inches of the front an [#permalink] New post   21 Jul 2020, 10:47
Bunuel wrote:
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?

A. 50%
B. 87%
C. 100%
D. 187%
E. 200%

Kudos for a correct solution.


Asked: How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?

Difference in the areas = 11*17 - 8.5*11 = 11(17-8.5) = 11*8.5 = 93.5

Percentage difference = 11*8.5 / 11*8.5 = 100%

IMO C
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Re: How much greater is the combined area in square inches of the front an [#permalink] New post   22 Jul 2020, 16:14
Bunuel wrote:
Bunuel wrote:
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?

A. 50%
B. 87%
C. 100%
D. 187%
E. 200%

Kudos for a correct solution.


VERITAS PREP OFFICIAL SOLUTION

Correct Answer: C

Because we're concerned with the percentage difference between the two sheets of paper, we don't need to calculate the areas if it's easier to simply compute the difference in percent/ratio terms. The area of the larger sheet is 11 * 17 * 2, while the area of the smaller sheet is 11 * 8 . 5 * 2 . Because the 11s cancel each other out, and 17 = 8.5 * 2, the difference between the two sheets is that the larger sheet has an additional factor of 2. Therefore, the larger sheet is twice the area of the smaller. Because this is a percentage difference problem, we need to determine how much must be added to the smaller to equal the larger. We would need to double it, or add one more sheet, to do so, so the larger sheet is 100% greater (the initial sheet plus an entire new one) than the smaller, and the correct answer is C.



Dear All

Greetings.
I have a small confusion: Isn't the question stem asking us to calculate the areas of both-front and back- sides of the 11, 17 sheet of paper and then compare the total combined area with the the total area of smaller rectangle that has sides 11, 8.5?
Please let me know if I am misinterpreting the question stem.
Thank you.

Regards
GMAT Club Bot
gmatclubot
Re: How much greater is the combined area in square inches of the front an [#permalink]
22 Jul 2020, 16:14
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