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If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such.

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stonecold
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If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   Updated on: 03 Aug 2016, 23:08
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If A,B,C,D,E,F,G,H,I,J are in an increasing Arithmetic Progression as such. Then Which of the following operations will result in either mean or the median being modified.
A) A is removed
B) A and J are removed
C) B and I are removed
D) A,B,C,H,I,J are removed
E) A and E are removed

1) A and B
2) A and E
3) A,C,E
4) All of them
5) None of them
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B

Originally posted by stonecold on 03 Aug 2016, 18:21.
Last edited by stonecold on 03 Aug 2016, 23:08, edited 3 times in total.
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 18:36
Why is b not the correct answer?
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stonecold
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 18:51
robanm90 wrote:
Why is b not the correct answer?



Counter Question =>
If B and I are removed will it remain an AP?

I hope that answers your query
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 18:59
stonecold wrote:
robanm90 wrote:
Why is b not the correct answer?



Counter Question =>
If B and I are removed will it remain an AP?

I hope that answers your query


The AP will not remain but the median ant the mean remain the same or i am missing something?
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 22:48
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stonecold wrote:
If A,B,C,D,E,F,G,H,I,J are in an increasing Arithmetic Progression as such. Then Which of the following operations will result in either mean or the median being modified.
A) A is removed
B) A and J are removed
C) B and I are removed
D) A,B,C,H,I,J are removed
E) A and E are removed

1) A and B
2) A and E
3) A,C,E
4) All of them
5) None of them



Here answer will be (B).

There are 10 equidistant numbers on the number line.

Mean and median will be the average of middle two numbers.

If you remove two numbers which is equidistant from either extreme (e.g. B and I), the total deviation on either side of the mean stays the same so mean stays the same. Also, the median is still the average of middle two numbers.
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 23:02
VeritasPrepKarishma wrote:
stonecold wrote:
If A,B,C,D,E,F,G,H,I,J are in an increasing Arithmetic Progression as such. Then Which of the following operations will result in either mean or the median being modified.
A) A is removed
B) A and J are removed
C) B and I are removed
D) A,B,C,H,I,J are removed
E) A and E are removed

1) A and B
2) A and E
3) A,C,E
4) All of them
5) None of them



Here answer will be (B).

There are 10 equidistant numbers on the number line.

Mean and median will be the average of middle two numbers.

If you remove two numbers which is equidistant from either extreme (e.g. B and I), the total deviation on either side of the mean stays the same so mean stays the same. Also, the median is still the average of middle two numbers.


Hi

My question is that => if we remove Two elements B and I then the series wont be in AP
So the mean will have changed.
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 23:04
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stonecold wrote:
VeritasPrepKarishma wrote:
stonecold wrote:
If A,B,C,D,E,F,G,H,I,J are in an increasing Arithmetic Progression as such. Then Which of the following operations will result in either mean or the median being modified.
A) A is removed
B) A and J are removed
C) B and I are removed
D) A,B,C,H,I,J are removed
E) A and E are removed

1) A and B
2) A and E
3) A,C,E
4) All of them
5) None of them



Here answer will be (B).

There are 10 equidistant numbers on the number line.

Mean and median will be the average of middle two numbers.

If you remove two numbers which is equidistant from either extreme (e.g. B and I), the total deviation on either side of the mean stays the same so mean stays the same. Also, the median is still the average of middle two numbers.


Hi

My question is that => if we remove Two elements B and I then the series wont be in AP
So the mean will have changed.


Mean will not change. Assume values and see why. It doesn't matter that you don't have an AP anymore.
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If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 23:11
Hi VeritasPrepKarishma
You are right karishma.
I just checked.
Do you have any blogs on topic underlying the questions such as above

Regards
S.C.S.A
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   03 Aug 2016, 23:14
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stonecold wrote:
Hi VeritasPrepKarishma
You are right karishma.
I just checked.
Do you have any blogs on topic underlying the questions such as above

Regards
S.C.S.A


Yes, the concept of deviation will help you understand it.
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2012/05 ... eviations/
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   04 Aug 2016, 11:02
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VeritasPrepKarishma wrote:
stonecold wrote:
If A,B,C,D,E,F,G,H,I,J are in an increasing Arithmetic Progression as such. Then Which of the following operations will result in either mean or the median being modified.
A) A is removed
B) A and J are removed
C) B and I are removed
D) A,B,C,H,I,J are removed
E) A and E are removed

1) A and B
2) A and E
3) A,C,E
4) All of them
5) None of them



Here answer will be (B).

There are 10 equidistant numbers on the number line.

Mean and median will be the average of middle two numbers.

If you remove two numbers which is equidistant from either extreme (e.g. B and I), the total deviation on either side of the mean stays the same so mean stays the same. Also, the median is still the average of middle two numbers.


Karishma thank you for your explanation my answer was B
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink] New post   25 Jun 2023, 07:25
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Re: If A,B,C,D,E,F,G,H,I,J are in an increasing AP as such. [#permalink]
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