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Re: If j is an integer, is k an integer? [#permalink]
Bunuel wrote:
If j is an integer, is k an integer?

(1) j – 2k is an integer.
(2) 5k – j is an integer.



let j=10
(1) then, if k=1 then yes
k=1/2 No ....insuff

(2) k=1 then yes
k=1/5 then No...insuff..

combined k must be ineteger....suff

Ans C
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Re: If j is an integer, is k an integer? [#permalink]
rohit8865 wrote:
Bunuel wrote:
If j is an integer, is k an integer?

(1) j – 2k is an integer.
(2) 5k – j is an integer.



let j=10
(1) then, if k=1 then yes
k=1/2 No ....insuff

(2) k=1 then yes
k=1/5 then No...insuff..

combined k must be ineteger....suff


Ans C


Questions asks if k is an integer? J is already integer. (it can be positive or negative).

A) is quite clear, its is INSUFFICIENT

in B if, k = 0.2 (which is 1/5) --> 5(0.2) - j (the integer) --> 1 - 2 = -1 there fore k is NOT integer.(is j is 2, 3, 4.. since answer is an integer, so answer can be negative or positive).
On the other hand, if k =1 --> then 5 - 4 (if j = 4) --> 1 or 5 - (-2) --> 7. Again K is Integer.
So both are INSUFFICIENT.
Hence E

How is C the answer? Could you give me a little detail into the solving? Thank you, it would be highly appreciated :)
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If j is an integer, is k an integer? [#permalink]
1 and 2 alone are clearly not sufficient

Now, If we combine 1 and 2:

2K is an integer, and 5K is integer
for 5K to be integer, k = 0.2, 0.4, 0.6, 0.8, 1.0, 1.2....and so on...
but 2K cannot be an integer if k = 0.2, 0.4, 0.6, 0.8, 1.0, 1.2.

So K has to be an integer if 2k and 5k are integer.

1 and 2 combined are sufficient to answer the question
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If j is an integer, is k an integer? [#permalink]
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