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# If p and q are two positive integers and p/q = 1.15

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If p and q are two positive integers and p/q = 1.15 [#permalink]
These are sub 600 level questions.
I don't fool myself
These sets of GMAT math bible questions aren't your typical GMAT 600-700 level questions.
One must have never reviewed a GMAT CAT to describe the question above as 600level.
It's simply ridiculous and delusional to rank it 600-700level.
I'm sorry but that's the truth.
Current Student
Joined: 10 Mar 2013
Posts: 360
Own Kudos [?]: 2705 [0]
Given Kudos: 200
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Concentration: Finance, Entrepreneurship
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Re: If p and q are two positive integers and p/q = 1.15 [#permalink]
Nez wrote:
These are sub 600 level questions.
I don't fool myself
These sets of GMAT math bible questions aren't your typical GMAT 600-700 level questions.
One must have never reviewed a GMAT CAT to describe the question above as 600level.
It's simply ridiculous and delusional to rank it 600-700level.
I'm sorry but that's the truth.

Might be, but relax... Based on the responses one can evaluate better the difficulty level of this question, and I'll update it accordingly.
BTW there's no difficulty level given for GMATprep questions and even respected GMAT Tutors avoid classifying those
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Re: If p and q are two positive integers and p/q = 1.15 [#permalink]
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BrainLab wrote:
If p and q are two positive integers and p/q = 1.15, then p can equal which one of the following?

(A) 15
(B) 18
(C) 20
(D) 22
(E) 23

This problem will be best solved using the remainder formula. Let’s first state the remainder formula:

When positive integer x is divided by positive integer y, if integer Q is the quotient and r is the remainder, then x/y = Q + r/y.

We are given that p and q are two positive integers and p/q = 1.15. Thus:

p/q = 1 + 15/100, or Q + r/q = 1 + 15/100

Since 15/100 = 3/20, r/q = 3/20 or r/q = 3k/20k for some positive integer k. We can see that r is 3 or a multiple of 3.

If r = 3, then q = 20 and p = 23.

Since 23 is one of the answer choices, choice E is the correct answer.

Alternate Solution:

Let’s convert the decimal 1.15 to a mixed number and then to an improper fraction:

1.15 = 1 15/100 = 1 3/20 = 23/20

We know that p/q = 1.15, so p/q = 23/20. Thus, one possible value for p is 23.

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Re: If p and q are two positive integers and p/q = 1.15 [#permalink]
BrainLab wrote:
If p and q are two positive integers and p/q = 1.15, then p can equal which one of the following?

(A) 15
(B) 18
(C) 20
(D) 22
(E) 23

Source: GMAT math Bible

$$\frac{p}{q} = 1.15$$

Or, $$\frac{p}{q} = 115/100$$

Or, $$\frac{p}{q} = 23/50$$

So the answer is p can be (E) 23
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Re: If p and q are two positive integers and p/q = 1.15 [#permalink]
BrainLab wrote:
If p and q are two positive integers and p/q = 1.15, then p can equal which one of the following?

(A) 15
(B) 18
(C) 20
(D) 22
(E) 23

Source: GMAT math Bible

1.15 = 115/100 = 23/20 = p/q

IMO E

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Re: If p and q are two positive integers and p/q = 1.15 [#permalink]
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Re: If p and q are two positive integers and p/q = 1.15 [#permalink]
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