p/q = 1.15 = 115/100 = 23/20

So, p COULD equal 23
Answer: E

Cheers,
Brent
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These are sub 600 level questions.
I don't fool myself
These sets of GMAT math bible questions aren't your typical GMAT 600-700 level questions.
One must have never reviewed a GMAT CAT to describe the question above as 600level.
It's simply ridiculous and delusional to rank it 600-700level.
I'm sorry but that's the truth.

This problem will be best solved using the remainder formula. Let’s first state the remainder formula:

When positive integer x is divided by positive integer y, if integer Q is the quotient and r is the remainder, then x/y = Q + r/y.

We are given that p and q are two positive integers and p/q = 1.15. Thus:

p/q = 1 + 15/100, or Q + r/q = 1 + 15/100

Since 15/100 = 3/20, r/q = 3/20 or r/q = 3k/20k for some positive integer k. We can see that r is 3 or a multiple of 3.

If r = 3, then q = 20 and p = 23.

Since 23 is one of the answer choices, choice E is the correct answer.

Alternate Solution:

Let’s convert the decimal 1.15 to a mixed number and then to an improper fraction:

1.15 = 1 15/100 = 1 3/20 = 23/20

We know that p/q = 1.15, so p/q = 23/20. Thus, one possible value for p is 23.

Answer: E
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