If printing press A, running alone at its constant rate, produces 27,0

Question

If printing press A, running alone at its constant rate, produces 27,000 newspapers in six hours, how long does it take printing press B, running alone at its constant rate, to produce 27,000 newspapers?

(1) Running alone at their respective constant rates, printing press B produces two newspapers in the same amount of time that printing press A produces three newspapers.

(2) Running together at their respective constant rates, the two presses produce 7,500 newspapers in one hour.

yashikaaggarwal · Answer

Given: Printing press A, running alone at its constant rate, produces 27,000 newspapers in six hours => 27000 newspapers in 6 hours. 
27000/6 = 4500 newspaper in an hour.

To find: how long does it take printing press B, running alone at its constant rate, to produce 27,000 newspapers?

(1) Running alone at their respective constant rates, printing press B produces two newspapers in the same amount of time that printing press A produces three newspapers.

B prints 2/3 of newspaper what A print in a given time. 
A print 4500 newspaper in 1 hour
4500/60 = 75 newspaper per second.

So B prints 50 newspapers per second. 
27000 newspapers in 27000/50 = 540 minutes. 
540 seconds = 9 hours
(Sufficient)

(2) Running together at their respective constant rates, the two presses produce 7,500 newspapers in one hour.
A prints 4500 newspapers in an hour
So, B prints 7500-4500 = 3000 newspapers
B will print 27000 newspapers in 27000/3000 = 9 hours
(Sufficient)

Answer is D

Posted from my mobile device

Kinshook · Answer

Hi  yashikaaggarwal 
Your logic is fine but 1 hour = 60 minutes = 3600 seconds. 
Please correct minor issues.

Fighter1095 · Answer

If printing press A, running alone at its constant rate, produces 27,000 newspapers in six hours, how long does it take printing press B, running alone at its constant rate, to produce 27,000 newspapers?

So, r(A) = (27k/6)

Let t be the time which we need to find

r(B) = (27k/t).

Statement1:

3r(A) = 2r(B)

If we substitute the above statements,
We get the value of t --> Sufficient(A).

Statement2:

(27k/6)+ (27k/t) = 75k

We can calculate t ---> Sufficient

Hence, D

Posted from my mobile device

Gmatboat · Answer

If printing press A, running alone at its constant rate, produces 27,000 newspapers in six hours, how long does it take printing press B, running alone at its constant rate, to produce 27,000 newspapers?

(1) Running alone at their respective constant rates, printing press B produces two newspapers in the same amount of time that printing press A produces three newspapers.

(2) Running together at their respective constant rates, the two presses produce 7,500 newspapers in one hour.

Hi  Bunuel  or other club moderators, this is a GMAT Prep question, please feel free to update the tags.

Gmatboat · Answer

If printing press A, running alone at its constant rate, produces 27,000 newspapers in six hours, how long does it take printing press B, running alone at its constant rate, to produce 27,000 newspapers?

So, r(A) = (27k/6)
Let t be the time which we need to find
r(B) = (27k/t).
Statement1:
 3r(A) = 2r(B) 
If we substitute the above statements,
We get the value of t --> Sufficient(A).

Hence, D
Hi  Fighter1095 , great logic! It was helpful. Anyway, there is a small error in the highlighted portion. It should actually be 2r(A) = 3r(B), because the rate of "A" is "faster" than the rate of "B", so "B" produces 2/3 of what "A" produces.

Bunuel · Answer

_____________________
Added the tag. Thank you!

CEdward · Answer

Not sure if this was the most efficient way to think about this. I struggle with math and it took me 15 minutes to get this even though it is very straightforward. But I am challenging myself to think things through rather than look at the answers.

Statement 1 - Sufficient
RateA = 27000 newspapers/6 hours = 4500 papers/1hr
We now know that RateB is 3/2x greater than RateA.
3/2 x 4500papers/hr = 6750 papers/hr

Statement 2 - Sufficient 
TotalWork = (RateA x 1hr) + (RateB x 1hr) 
7500 = 4500papers/hr + RateB
RateB = 7500papers/4500 papers/hr

BLTN · Answer

Dear Gmatboat the quibble is what the highlighted portion represents

What if it is the time? then the initial expression is utterly valid. 3r(A) = 2r(B) = > Time B = 1.5 Time A, substitute Time B = 1.5 *6h = 9h --------- Dear CEdward I presume that you meant RateB = \frac{2}{3} RateA Then \frac{2}{3} * \frac{27000}{6} = \frac{3000}{h} Thus, B time: 27000 = 3000*T = > 9h First time I had saw the question, I made unnecessary computation. But when you realize that it is DS question and that you can form the equation with 1 variable, you do not need to calculate anything. That is valid for the 1st and 2nd statements. Hope it helps

bumpbot · Answer

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If printing press A, running alone at its constant rate, produces 27,0

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If printing press A, running alone at its constant rate, produces 27,0

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