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Re: If x and y are positive integers such that y is a multiple of 5 and 3x
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09 Feb 2018, 17:09
Can someone pls verify if this method will work for all similar question types? This is the way I approached as well wvu wrote: I approached this in a different style I think than the other posters  is this way correct as well?
First, 200 factors down to \(2^3 * 5^2\)
Looking at the information we know that from the equation \(3x + 4y\), where y is a multiple of 5, we have the factors of \(2^2\) (from the 4), 3, and 5. Given this, we can then determine that we need one more factor of both 2 and 5. E  10 is the only answer choice that provides those two factors.



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Re: If x and y are positive integers such that y is a multiple of 5 and 3x
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12 Feb 2018, 04:38
mrdlee23 wrote: Can someone pls verify if this method will work for all similar question types? This is the way I approached as well wvu wrote: I approached this in a different style I think than the other posters  is this way correct as well?
First, 200 factors down to \(2^3 * 5^2\)
Looking at the information we know that from the equation \(3x + 4y\), where y is a multiple of 5, we have the factors of \(2^2\) (from the 4), 3, and 5. Given this, we can then determine that we need one more factor of both 2 and 5. E  10 is the only answer choice that provides those two factors. Since y is a factor of 5, 4y will end in 0. So get the sum of 200, 3x should end in 0 as well. So x should be a multiple of 10.
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Re: If x and y are positive integers such that y is a multiple of 5 and 3x
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16 Apr 2018, 00:59
Abhishek009 wrote: AbdurRakib wrote: If x and y are positive integers such that y is a multiple of 5 and 3x + 4y = 200, then x must be a multiple of which of the following? A) 3 B) 6 C) 7 D) 8 E) 10 OG 2017 New Question Plug in values and check  Let y = 5 ; 3x + 4y = 200 So, 3x + 20 = 200 Or, x = 60 ( Options C & D rejected , Left with options A, B & E ) Let y = 20 ; 3x + 4y = 200 So, 3x + 80 = 200 Or, x = 40 ( Options A &B rejected , Left with option E ) Hence, answer will be optin (E)Hey, Abhishek009! 40 is also a multiple of 8, option D. So we still have D and E remaining.



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Re: If x and y are positive integers such that y is a multiple of 5 and 3x
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16 Apr 2018, 01:19
advait92 wrote: Hey, Abhishek009! 40 is also a multiple of 8, option D. So we still have D and E remaining. Hey advait92 , As Abhishek009 has explained, we have already rejected option D when we substituted y = 5 in the equation. Remember for a "MUST" be true question, it should work for all the scenarios but we are not getting x a multiple of 8 whenever we have y = 5. Hence, D cannot be the answer. Does that make sense?
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Re: If x and y are positive integers such that y is a multiple of 5 and 3x
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16 Apr 2018, 02:00
abhimahna wrote: advait92 wrote: Hey, Abhishek009! 40 is also a multiple of 8, option D. So we still have D and E remaining. Hey advait92 , As Abhishek009 has explained, we have already rejected option D when we substituted y = 5 in the equation. Remember for a "MUST" be true question, it should work for all the scenarios but we are not getting x a multiple of 8 whenever we have y = 5. Hence, D cannot be the answer. Does that make sense? Hey abhimahna! Thank you for bringing this to my notice.



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Re: If x and y are positive integers such that y is a multiple of 5 and 3x
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26 Jul 2018, 08:12
X,Y >0 i.e.X,Y both positive Y=mul(5) i.e. Y is multiple of 5 3X+4Y=200 Because Y=mul(5),4Y will be multiple of 20 200 is also multiple of 20. Hence 2004Y will also be multiple of 20 I.e. 3X= multiple of 20 Hence, X will be multiple of 20, 10×2, and hence of 10. Posted from my mobile device
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If x and y are positive integers such that y is a multiple of 5 and 3x
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28 Jul 2018, 01:58
niks18 chetan2u pushpitkc KarishmaB gmatbustersQuote: If x and y are positive integers such that y is a multiple of 5 and 3x + 4y = 200, then x must be a multiple of which of the following? How about this approach? Given: y is a multiple of 5, so unit digits of product with y must end with 0 or 5. 4*y = (Unit digit will always end with 0, since 4*5 = 20 and 4*0 =0 ) Now look RHS, I need unit digit as 0, __ + 0 = 0 Hence 3 must be some multiple an integer ending with 0. Ans: 10
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Re: If x and y are positive integers such that y is a multiple of 5 and 3x
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28 Jul 2018, 02:41
This is the perfect approach. adkikani wrote: niks18 chetan2u pushpitkc KarishmaB gmatbustersQuote: If x and y are positive integers such that y is a multiple of 5 and 3x + 4y = 200, then x must be a multiple of which of the following? How about this approach? Given: y is a multiple of 5, so unit digits of product with y must end with 0 or 5. 4*y = (Unit digit will always end with 0, since 4*5 = 20 and 4*0 =0 ) Now look RHS, I need unit digit as 0, __ + 0 = 0 Hence 3 must be some multiple an integer ending with 0. Ans: 10
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If x and y are positive integers such that y is a multiple of 5 and 3x
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06 Aug 2018, 18:09
i. We see that 4y is always a multiple of 10 when y is a multiple of 5 . So 3x is a multiple of 10 or x is a multiple of 3.33. ii. However x is an integer . So x has to be a multiple of 3.33*3=10 since that is the minimum value that makes x an integer. iii. So a multiple of 10. Hence E.
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