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Re: If x is a positive integer then find x? (1) x^2−5x+6=0 (2) x^2=3x [#permalink]
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Kudos
by non negative integers the integers series ; (0,1,2.....)

#1
\(x^2−5x+6=0\)
x=3,2
insufficient
#2
\(x^2=3x\)
x=3 , 0
insufficient
from 1 &2
x= 3 sufficient
IMO C


GMATinsight wrote:
If x is a Non-Negative integer then find x?

(1) \(x^2−5x+6=0\)

(2) \(x^2=3x\)

(Source:www.GMATINSIGHT.com)

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Re: If x is a positive integer then find x? (1) x^2−5x+6=0 (2) x^2=3x [#permalink]
Top Contributor
GMATinsight wrote:
If x is a Non-Negative integer then find x?

(1) \(x^2−5x+6=0\)
(2) \(x^2=3x\)

(Source: https://www.GMATINSIGHT.com )



(1) x=3, x=2 both are nonnegative. INSUFFICIENT.

(2) X= 3

ANS B.

I CONFUSED WHY IS B NOT ANSWER. THE OPTION GIVING ONLY ONE ANSWER.
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If x is a positive integer then find x? (1) x^2−5x+6=0 (2) x^2=3x [#permalink]
Top Contributor
GMATinsight wrote:
If x is a Non-Negative integer then find x?

(1) \(x^2−5x+6=0\)
(2) \(x^2=3x\)

(Source: https://www.GMATINSIGHT.com )



GMATinsight
Bunuel

if x a no-negative integer then why we can't divide both sides by x in option (2)?

Originally posted by MHIKER on 11 Nov 2020, 16:43.
Last edited by MHIKER on 12 Nov 2020, 07:35, edited 1 time in total.
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Re: If x is a positive integer then find x? (1) x^2−5x+6=0 (2) x^2=3x [#permalink]
Expert Reply
MHIKER wrote:
GMATinsight wrote:
If x is a Non-Negative integer then find x?

(1) \(x^2−5x+6=0\)
(2) \(x^2=3x\)

(Source: https://www.GMATINSIGHT.com )



GMATinsight
Bunuel

if x a no-negative integer then why we can divide both sides by x in option (2)?


We cannot divide x^2 = 3x by x because x can be 0 and we cannot divide by 0. When dividing by x, you loose a root, namely x = 0. Notice that both x = 0 and x = 3 satisfy x^2 = 3x.

I think you mixed "non-negative integer" with "non-zero integer" in the stem.

Hope it's clear.
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Re: If x is a positive integer then find x? (1) x^2−5x+6=0 (2) x^2=3x [#permalink]
Top Contributor
Bunuel wrote:
MHIKER wrote:
GMATinsight wrote:
If x is a Non-Negative integer then find x?

(1) \(x^2−5x+6=0\)
(2) \(x^2=3x\)

(Source: https://www.GMATINSIGHT.com )



GMATinsight
Bunuel

if x a no-negative integer then why we can divide both sides by x in option (2)?


We cannot divide x^2 = 3x by x because x can be 0 and we cannot divide by 0. When dividing by x, you loose a root, namely x = 0. Notice that both x = 0 and x = 3 satisfy x^2 = 3x.

I think you mixed "non-negative integer" with "non-zero integer" in the stem.

Hope it's clear.


Thank you. I missed the important part. Non-negative means the number is not negative but it can be "ZERO" and we can't divide any number with "0".
Thanks for the catch.
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Re: If x is a positive integer then find x? (1) x^2−5x+6=0 (2) x^2=3x [#permalink]
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