GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 20 Jun 2019, 06:20

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

If x, y, and k are positive and x is less than y, then (x + k)/(y + k)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 55729
If x, y, and k are positive and x is less than y, then (x + k)/(y + k)  [#permalink]

Show Tags

New post 26 Apr 2019, 06:09
1
3
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

68% (01:29) correct 32% (01:27) wrong based on 249 sessions

HideShow timer Statistics

CEO
CEO
User avatar
V
Joined: 12 Sep 2015
Posts: 3786
Location: Canada
Re: If x, y, and k are positive and x is less than y, then (x + k)/(y + k)  [#permalink]

Show Tags

New post 26 Apr 2019, 06:24
1
Top Contributor
Bunuel wrote:
If x, y, and k are positive and x is less than y, then \(\frac{x + k}{y + k}\) is

A. 1
B. greater than x/y
C. equal to x/y
D. less than x/y
E. less than x/y or greater than x/y, depending on the value of k


PS87502.01
Quantitative Review 2020 NEW QUESTION


Key concept (also covered in video below):
Image

Since x < y, we know that x/y is less than 1

So, \(\frac{x + k}{y + k}\) will be closer to 1 than x/y is.

In other words, \(\frac{x + k}{y + k}\) must be greater than x/y

Answer: B

Cheers,
Brent

RELATED VIDEO FROM MY COURSE

_________________
Test confidently with gmatprepnow.com
Image
CEO
CEO
User avatar
P
Joined: 18 Aug 2017
Posts: 3897
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
GMAT ToolKit User Premium Member CAT Tests
Re: If x, y, and k are positive and x is less than y, then (x + k)/(y + k)  [#permalink]

Show Tags

New post 28 Apr 2019, 04:07
Bunuel wrote:
If x, y, and k are positive and x is less than y, then \(\frac{x + k}{y + k}\) is

A. 1
B. greater than x/y
C. equal to x/y
D. less than x/y
E. less than x/y or greater than x/y, depending on the value of k


PS87502.01
Quantitative Review 2020 NEW QUESTION


let x=5 ,y=6 and k =1
solve
\(\frac{x + k}{y + k}\) = 6/7
and x/y=5/6
we see that 6/7>5/6
IMO B
_________________
If you liked my solution then please give Kudos. Kudos encourage active discussions.
Manager
Manager
avatar
B
Joined: 25 Sep 2018
Posts: 60
Re: If x, y, and k are positive and x is less than y, then (x + k)/(y + k)  [#permalink]

Show Tags

New post 11 May 2019, 12:03
Bunuel wrote:
If x, y, and k are positive and x is less than y, then \(\frac{x + k}{y + k}\) is

A. 1
B. greater than x/y
C. equal to x/y
D. less than x/y
E. less than x/y or greater than x/y, depending on the value of k


PS87502.01
Quantitative Review 2020 NEW QUESTION


x<y
So, x/y= less than 1
If x=1
y=2
x/y=1/2=.5

Now, if we increase both numerator and denominator by same number then result must be increased.
1+1/2+1=2/3=.67

Answer is B

Posted from my mobile device
Target Test Prep Representative
User avatar
D
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 6589
Location: United States (CA)
Re: If x, y, and k are positive and x is less than y, then (x + k)/(y + k)  [#permalink]

Show Tags

New post 23 May 2019, 17:10
Bunuel wrote:
If x, y, and k are positive and x is less than y, then \(\frac{x + k}{y + k}\) is

A. 1
B. greater than x/y
C. equal to x/y
D. less than x/y
E. less than x/y or greater than x/y, depending on the value of k


PS87502.01
Quantitative Review 2020 NEW QUESTION


When a positive constant is added to the numerator and denominator of a positive fraction, the resulting value of the fraction increases. For example, to the fraction 1/6, add 4 to both the numerator and denominator, obtaining 5/10, which is greater than 1/6.

Thus, (x + k)/(y + k) is greater than x/y.

Answer: B
_________________

Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com
TTP - Target Test Prep Logo
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

CrackVerbal Quant Expert
User avatar
B
Joined: 23 Apr 2019
Posts: 15
Re: If x, y, and k are positive and x is less than y, then (x + k)/(y + k)  [#permalink]

Show Tags

New post 23 May 2019, 21:49
One way to solve this question is to know that if you add the same constant to the numerator and denominator of a positive fraction, then the value of the fraction increases and will always tend to 1. But even if we did not know this, we can easily solve the question by using the answer choices. Remember this is a PS question, so there have to be only ONE possible answer.

We have x, y and k to be positive and x < y. The question asks us for (x + k)/(y + k)

A. If (x + k)/(y + k) = 1, then x = y. This is not possible since x < y
B. If (x + k)/(y + k) > x/y, cross multiplying (since x and y are positive), we get xy + yk > xy + xk. Cancelling xy on both sides, we get y > x or x < y. So B works.

Hope this helps!

Aditya
CrackVerbal Quant Expert
GMAT Club Bot
Re: If x, y, and k are positive and x is less than y, then (x + k)/(y + k)   [#permalink] 23 May 2019, 21:49
Display posts from previous: Sort by

If x, y, and k are positive and x is less than y, then (x + k)/(y + k)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne