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If y= 4 + (x - 3)^2, then y is lowest when x =

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Math Expert
Joined: 02 Sep 2009
Posts: 50572
If y= 4 + (x - 3)^2, then y is lowest when x =  [#permalink]

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16 Sep 2018, 23:31
00:00

Difficulty:

5% (low)

Question Stats:

80% (00:44) correct 20% (00:41) wrong based on 59 sessions

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If y= 4 + (x - 3)^2, then y is lowest when x =

A. 14
B. 13
C. 0
D. 3
E. 4

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Senior Manager
Joined: 18 Jul 2018
Posts: 377
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: If y= 4 + (x - 3)^2, then y is lowest when x =  [#permalink]

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16 Sep 2018, 23:37
$$(x-3)^2$$ is always positive.

minimum value of this expression is 0. So x = 3.

then y = 4.

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Director
Joined: 31 Oct 2013
Posts: 775
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
Re: If y= 4 + (x - 3)^2, then y is lowest when x =  [#permalink]

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17 Sep 2018, 00:34
Bunuel wrote:
If y= 4 + (x - 3)^2, then y is lowest when x =

A. 14
B. 13
C. 0
D. 3
E. 4

we are looking for the lowest value of y.

y has 2 parts.

1. 4
2. $$( x - 3)^2.$$

we have nothing to do with 4 but we can curb the value of$$(x - 3)^2$$.

x = 3 will give us the nothing in $$(x-3)^2$$ .

Negative value will change the scenario. $$(x-3)^2$$ always gives us positive value.

Re: If y= 4 + (x - 3)^2, then y is lowest when x = &nbs [#permalink] 17 Sep 2018, 00:34
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