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If y= 4 + (x - 3)^2, then y is lowest when x =

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 50572
If y= 4 + (x - 3)^2, then y is lowest when x =  [#permalink]

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New post 16 Sep 2018, 23:31
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

80% (00:44) correct 20% (00:41) wrong based on 59 sessions

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Senior Manager
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Joined: 18 Jul 2018
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Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
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Re: If y= 4 + (x - 3)^2, then y is lowest when x =  [#permalink]

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New post 16 Sep 2018, 23:37
\((x-3)^2\) is always positive.

minimum value of this expression is 0. So x = 3.

then y = 4.

D is the answer.
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Re: If y= 4 + (x - 3)^2, then y is lowest when x =  [#permalink]

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New post 17 Sep 2018, 00:34
Bunuel wrote:
If y= 4 + (x - 3)^2, then y is lowest when x =

A. 14
B. 13
C. 0
D. 3
E. 4



we are looking for the lowest value of y.

y has 2 parts.

1. 4
2. \(( x - 3)^2.\)

we have nothing to do with 4 but we can curb the value of\((x - 3)^2\).

x = 3 will give us the nothing in \((x-3)^2\) .

Negative value will change the scenario. \((x-3)^2\) always gives us positive value.

The best answer is D.
GMAT Club Bot
Re: If y= 4 + (x - 3)^2, then y is lowest when x = &nbs [#permalink] 17 Sep 2018, 00:34
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