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# In 1998 the profits of company N were 10 percent of revenues. In 1999,

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In 1998 the profits of company N were 10 percent of revenues. In 1999,  [#permalink]

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12 Dec 2015, 09:29
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In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?

A. 80%
B. 105%
C. 120%
D. 124.2%
E. 138%

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Re: In 1998 the profits of company N were 10 percent of revenues. In 1999,  [#permalink]

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12 Dec 2015, 13:12
0,12R = x/100*0.1R
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Re: In 1998 the profits of company N were 10 percent of revenues. In 1999,  [#permalink]

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14 Dec 2015, 17:11
Hi All,

This question can be solved either algebraically or by TESTing VALUES.

We're told that, in 1998, profits were 10% of revenues....

Let's TEST:
1998
Revenues= $100 Profits =$10

Next we're told that, in 1999, revenue FELL by 20%, but profits were 15% of revenues. Using the numbers from 1998 (above), we end up with...

1999
Revenues = $80 Profits =$12

We're asked to compare the profits in 1999 to the profits in 1998 (as a percentage):

$12/$10 = 1.2 = 120%

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Re: In 1998 the profits of company N were 10 percent of revenues. In 1999,  [#permalink]

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17 Apr 2017, 06:41
Bunuel wrote:
In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?

A. 80%
B. 105%
C. 120%
D. 124.2%
E. 138%

Take simple numbers
98--100--10 $--10% 99--80--12$--15%(80 since revenue fell by 20%)
x=12/10*100
x=12*10
x=120%
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In 1998 the profits of company N were 10 percent of revenues. In 1999,  [#permalink]

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17 May 2017, 15:17
2
In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?
A. 80%
B. 105%
C. 120%
D. 124.2%
E. 138%

Let 1998 revenue be = 100
1998 Profits = 10% of revenue = 10% of 100 =$$\frac{10}{100}$$ x 100 = 10
1999 revenue = revenue fell by 20% of 1998 revenue = 80% of 100 = $$\frac{80}{100}$$ x 100 = 80
1999 Profits = 15% of 1999 revenue = 15% of 80 = $$\frac{15}{100}$$ x 80 = 12
Required fraction = 1999 Profits / 1998 Profits x 100 = $$\frac{12}{10}$$ x 100 = 120%

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Re: In 1998 the profits of company N were 10 percent of revenues. In 1999,  [#permalink]

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21 Jun 2017, 04:45
Bunuel wrote:
In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?

A. 80%
B. 105%
C. 120%
D. 124.2%
E. 138%

We can apply a few formulas to solve this problem

$100(.1) =$10 profit in 1998

$100(.8)(.15) =$12 profit in 1999

new-old/ old = $12-$10/\$10

120%

Thus
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Re: In 1998 the profits of company N were 10 percent of revenues. In 1999,  [#permalink]

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21 Jan 2019, 20:34
Bunuel wrote:
In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?

A. 80%
B. 105%
C. 120%
D. 124.2%
E. 138%

We can let the revenues in 1998 = 100. Thus, the profits in 1998 = 100 x 0.1 = 10, the revenues in 1999 = 100 x 0.8 = 80, and the profits in 1999 = 80 x 0.15 = 12. Therefore, the profits in 1999 were 12/10 x 100 = 120 percent of the profits in 1998.

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Re: In 1998 the profits of company N were 10 percent of revenues. In 1999,   [#permalink] 21 Jan 2019, 20:34
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