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In the xycoordinate plane, is point R equidistant from [#permalink]
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In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3) ? (1) The xcoordinate of point R is 1. (2) Point R lies on the line y = 3.
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In the xycoordinate plane, is point R equidistant from [#permalink]
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In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3) ?Look at the diagram below: Notice, that the green line (x=1) is the perpendicular bisector of the line segment with endpoints (3,3) and (1,3), thus ANY point on this line will be equidistant from points (3,3) and (1,3). (1) The xcoordinate of point R is 1 > point R is on the green line. Sufficient. (2) Point R lies on the line y = 3 > point R may or may not be on the green line. Not sufficient. Answer: A. Attachment:
Equidistant points.png [ 9.68 KiB  Viewed 11338 times ]
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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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13 May 2013, 20:17
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Walkabout wrote: In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3) ?
(1) The xcoordinate of point R is 1. (2) Point R lies on the line y = 3. Any point that lie on the perpendicular bisector the line segment with extreme points (3,3) and (1,3) will satisfy this condition. The perpendicular bisector of the line segment is x=1. 1) this means the point lies on x=1. Sufficient. 2) This may or may not lie in the middle. The point 1,3 is the mid point of the line segment but their are other points on the line such as (2,3) which doesn't satisfy the requirements. Insufficient. Hence A.



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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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06 Aug 2014, 05:30
Why does the green line go through point 1 ? I couldn't find any chapter which explains this system.. can anyone help?



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In the xycoordinate plane, is point R equidistant from [#permalink]
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We have to find out whether \(R(x,y)\) is equidistant from the two points mentioned
Using the distance formula \((x+3)^2+(y+3)^2 = (x1)^2+(y+3)^2\) \((x+3)^2 = (x1)^2\)
So basically we have to prove whether \((x+3)^2 = (x1)^2\)or not?
1)Substituting\(1\) in the above equation \((x+3)^2 = (x1)^2\) results in it being equal Thus sufficient
2)\(y = 3\)wouldn't help us with this eqn:\((x+3)^2 = (x1)^2\) Thus insufficient
Ans is A



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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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16 May 2015, 09:25
I got really scared seeing this question. But visualizing the coordinate plane made for a much simpler approach. Once I got the two points mapped out it was obvious that point R had to be on X = 1. I suppose this was possible because the two points had the same Y coordinates, which allowed for several a straight line at equidistance from the two points. Has anyone got any suggestions or Q's that involves points without this possibility? e.g. A=(1,0) B=(6,6)
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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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16 May 2015, 11:32
Hi MarkusKarl, Most Geometry questions have a "visual" component to them, so drawing the "work" involved (the shapes, the graph, etc.) will almost always be beneficial  in that way, you can connect conceptual ideas to realworld examples. GMAT questions in general are almost all patternbased, so if you find yourself 'stuck' conceptually, you have to think about the rules involved and simplify the logic. In your example, you name two points that don't share an X or Y coordinate, but the concept involved in this prompt applies to your example as well. There WILL be a "line" of coordinates that are equidistant from the two points that you named (it's just that the "line" will be a diagonal line and will NOT involve any shared X or Y coordinates). GMAT assassins aren't born, they're made, Rich
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In the xycoordinate plane, is point R equidistant from points (3,3) [#permalink]
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04 Feb 2017, 00:07
In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3)?
(1) The xcoordinate of point R is 1. (2) Point R lies on the line y=3.



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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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04 Feb 2017, 00:45
Bunuel wrote: Kchaudhary wrote: In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3)?
(1) The xcoordinate of point R is 1. (2) Point R lies on the line y=3. Merging topics. Please refer to the discussion above. Hi Bunnel, in statement 1, how can you consider that ycoordinate of R is 0?



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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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04 Feb 2017, 00:55
Kchaudhary wrote: Bunuel wrote: Kchaudhary wrote: In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3)?
(1) The xcoordinate of point R is 1. (2) Point R lies on the line y=3. Merging topics. Please refer to the discussion above. Hi Bunnel, in statement 1, how can you consider that ycoordinate of R is 0? The ycoordinate of R is not necessarily 0. The point is that since xcoordinate of R is 1, then R is on the green line, so no matter what is the ycoordinate, R will be equidistant from the given points.
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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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14 May 2017, 05:10
Hi lou34, Thats because S1 says so. S1 says  The Xcoordinate of Point R is 1. This mean it will have to R WILL have to be ANY point on the green line mentioned by Bunuel. I hope this clears your question. lou34 wrote: Why does the green line go through point 1 ? I couldn't find any chapter which explains this system.. can anyone help?
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Re: In the xycoordinate plane, is point R equidistant from [#permalink]
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14 May 2017, 05:55
HI Kchaudhary, Just adding to Bunuel's solution. Even though the term perpendicular bisector is used, we can infer S1 is sufficient without knowing about it. A quick sketch of the Coordinate will be able to get us there. Consider the attached image. In the Image I have taken an Arbitrary point R on the green line. Named the given two points as A and B. Also labelled O for easier understanding. What is asked is  AR = BR?. If you notice  Point A, B and R form two Right angles at common point O. In these two Right angled triangle, two sides are equal. AO = AB = 2 (Follows from given coordinates) and OR is common to both Right triangles. So, it clearly follows that the third side of both right angles MUST be equal. Meaning AR = BR. This makes S1 sufficient. I hope this helped Kchaudhary wrote: Bunuel wrote: Kchaudhary wrote: In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3)?
(1) The xcoordinate of point R is 1. (2) Point R lies on the line y=3. Merging topics. Please refer to the discussion above. Hi Bunnel, in statement 1, how can you consider that ycoordinate of R is 0?
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File comment: Named given point A and B for clarity. Assumed Point R on green line
Equidistant points.png [ 18.45 KiB  Viewed 608 times ]
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In the xycoordinate plane, is point R equidistant from [#permalink]
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14 May 2017, 10:43
Walkabout wrote: In the xycoordinate plane, is point R equidistant from points (3,3) and (1,3) ?
(1) The xcoordinate of point R is 1. (2) Point R lies on the line y = 3. Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution. From the original condition, we can set up as this question as follows. The distance between \(R(x,y)\) and \((3,3)\) is \(\sqrt{(x+3)^2 + (y+3)^2}\) and the distance between \(R(x,y)\) and \((1,3)\) is \(\sqrt{(x1)^2 + (y+3)^2}\). Thus, we have \(\sqrt{(x+3)^2 + (y+3)^2} = \sqrt{(x1)^2 + (y+3)^2}\). Then \(x^2 + 6x + 9 + y^2 + 6y + 9 = x^2 2x + 1 + y^2 + 6y + 9\). \(6x + 9 = 2x + 1\) \(8x = 8\) \(x = 1\) We have 2 variables \(x\) and \(y\) and 1 equation, \(x = 1\). In the original condition, there is 1 variable(x), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer. For 1), \(x = 1\), which is equivalent to the condition from the original question. No additional condition is provided. Thus this is not sufficient. For 2), \(y = 3\). Then the point R is (1,3). This is sufficient. Therefore, the answer is B. > For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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