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Re: tricky DS inequalities problem from an old GMAT paper exam [#permalink]
ranjanav22 wrote:
If (k-3)(k-2)(k-1)>0, doesnt that mean, K>3 or K>2 or K>1?
Why is it K>3 or 1>k>2?
Please explain. Thank you.


When you have inequalities like this one A*B*C>0
Either all three terms are greater than 0 (k>3)
Or exactly one term is greater than 0, and other two are less than 0 (1<k<2)
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Re: tricky DS inequalities problem from an old GMAT paper exam [#permalink]
shrouded1 wrote:
ranjanav22 wrote:
If (k-3)(k-2)(k-1)>0, doesnt that mean, K>3 or K>2 or K>1?
Why is it K>3 or 1>k>2?
Please explain. Thank you.


When you have inequalities like this one A*B*C>0
Either all three terms are greater than 0 (k>3)
Or exactly one term is greater than 0, and other two are less than 0 (1<k<2)


Is there a reason for choosing K>3 ? Can it be K<3,K<2 and K>1?
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Re: tricky DS inequalities problem from an old GMAT paper exam [#permalink]
tonebeeze wrote:
Is k greater than 3?

(1) (k - 3)(k- 2)(k - 1) > 0

(2) k > 1


Can you help me explain how to simplify statement 1. Is the key to test values between 0 and 1?

Thanks


check out the link inequalities-trick-91482.html
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Re: Is k greater than 3? [#permalink]
St. 1 gives us that k>2 since the equation is +ve only when all 3 are +ve i.e. k>3 or when 2 -ve and 1+ve fig is there i.e. K>2 -- Not sufficient

St. 2 tells us k>1 -- Not sufficient

Merging St. 1 and St. 2 tells us that k>2 -- Not sufficient.

Therefore, answer is E
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Re: Is k greater than 3? [#permalink]
If the numbers are (k-3), (k-2), and (k-1), then these are consecutive numbers. Accordingly, (--+) won't exist as it needs to have 0 as well and we know the product is greater than zero.

Can any one of you explain why is my understanding incorrect?
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Re: Is k greater than 3? [#permalink]
­I dont get this... The only way the first equation works is if k>3. if its less, the first equation doesnt work. I thought this was A.

k=4 ====> 1*2*3 =  6 which is >0 
k=3 ====> 0* whatever = 0
k=-1 ====> -4*-3*-2 = -24 ­
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Re: Is k greater than 3? [#permalink]
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tomloveless wrote:
­I dont get this... The only way the first equation works is if k>3. if its less, the first equation doesnt work. I thought this was A.

k=4 ====> 1*2*3 =  6 which is >0 
k=3 ====> 0* whatever = 0
k=-1 ====> -4*-3*-2 = -24 ­

­_______________
What if 1 < k < 2? 
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Re: Is k greater than 3? [#permalink]
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