Bunuel wrote:
BANON wrote:
Lines n and p lie in the xy-plane. Is the slope of line n less than the slope of line p ?
(1) Lines n and p intersect at the point (5 , 1).
(2) The y-intercept of line n is greater than the y-intercept of line p.
Algebraic approach:Lines n and p lie in the xy-plane. Is the slope of line n less than the slope of line p?We have two lines: \(y_n=m_1x+b_1\) and \(y_p=m_2x+b_2\). Q: \(m_1<m_2\) true?
(1) Lines n and p intersect at the point (5,1) --> \(1=5m_1+b_1=5m_2+b_2\) --> \(5(m_1-m_2)=b_2-b_1\). Not sufficient.
(2) The y-intercept of line \(n\) is greater than the y-intercept of line \(p\) --> y-intercept is value of \(y\) for \(x=0\), so it's the value of \(b\) --> \(b_1>b_2\) or \(b_2-b_1<0\). Not sufficient.
(1)+(2) \(5(m_1-m_2)=b_2-b_1\), as from (2) \(b_2-b_1<0\) (RHS), then LHS (left hand side) also is less than zero \(5(m_1-m_2)<0\) --> \(m_1-m_2<0\) --> \(m_1<m_2\). Sufficient.
Answer: C.
For more on this topic check Coordinate Geometry Chapter of Math Book:
https://gmatclub.com/forum/math-coordina ... 87652.htmlHope it helps.
BunuelI ended up using smart numbers
Let's say for line n that b =6 and for line p that b=4
Line n --> y=mx+6
Line p --> y=mx+4
I then plugged in the point (5,1) to find the slope of each equation
Line n's equation ends up being --> y=-x+6
Line p's equation ends up being --> y=-3/5x+4
So, the slope of line n is less than the slope of line p.
Is this an okay approach, or did I just stumble upon the answer?