Last visit was: 20 Nov 2025, 04:10 It is currently 20 Nov 2025, 04:10
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 20 Nov 2025
Posts: 105,409
Own Kudos:
Given Kudos: 99,987
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,409
Kudos: 778,474
 [71]
5
Kudos
Add Kudos
64
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 20 Nov 2025
Posts: 105,409
Own Kudos:
Given Kudos: 99,987
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,409
Kudos: 778,474
 [23]
9
Kudos
Add Kudos
14
Bookmarks
Bookmark this Post
User avatar
shasadou
Joined: 12 Aug 2015
Last visit: 24 Nov 2022
Posts: 219
Own Kudos:
3,099
 [17]
Given Kudos: 1,476
Concentration: General Management, Operations
GMAT 1: 640 Q40 V37
GMAT 2: 650 Q43 V36
GMAT 3: 600 Q47 V27
GPA: 3.3
WE:Management Consulting (Consulting)
GMAT 3: 600 Q47 V27
Posts: 219
Kudos: 3,099
 [17]
9
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
General Discussion
avatar
imperfectdark
Joined: 06 Jan 2013
Last visit: 14 Nov 2014
Posts: 9
Own Kudos:
165
 [7]
Given Kudos: 24
Location: United States
Concentration: Finance, Economics
GMAT Date: 11-15-2013
GPA: 3.5
WE:Education (Education)
Posts: 9
Kudos: 165
 [7]
5
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Is it valid to set this up as a weighted average? If the overall % gain was 5% then we could solve this as:

(+10)x + (-15)y = 0 yielding that x = 3y. The only combination of prices which matches the ratio is (D)
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 20 Nov 2025
Posts: 105,409
Own Kudos:
778,474
 [2]
Given Kudos: 99,987
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,409
Kudos: 778,474
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
imperfectdark
Is it valid to set this up as a weighted average? If the overall % gain was 5% then we could solve this as:

(+10)x + (-15)y = 0 yielding that x = 3y. The only combination of prices which matches the ratio is (D)

Yes, that's correct.
avatar
josegf1987
Joined: 20 Apr 2015
Last visit: 30 Aug 2015
Posts: 3
Own Kudos:
2
 [2]
Given Kudos: 42
Posts: 3
Kudos: 2
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
imperfectdark
Is it valid to set this up as a weighted average? If the overall % gain was 5% then we could solve this as:

(+10)x + (-15)y = 0 yielding that x = 3y. The only combination of prices which matches the ratio is (D)

Yes, that's correct.

Hi Bunuel, can you elaborate more about how we go about setting up the weighted average equation? Thanks.
avatar
Erina89
Joined: 04 Sep 2015
Last visit: 19 Apr 2016
Posts: 1
Own Kudos:
1
 [1]
Given Kudos: 1
Posts: 1
Kudos: 1
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel,

sorry I just clicked on the feedback button of the question. I think I probably misunderstood the question stem. Are the 20,000 the total sales price of the cars? And don't I have to calculate the profit/loss of each car like that: 1,1x=15,000 =>~13,636 => 15,000 - 13,636 is the actual profit of this car?

Thanks for your Support.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 20 Nov 2025
Posts: 105,409
Own Kudos:
Given Kudos: 99,987
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,409
Kudos: 778,474
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Erina89
Hi Bunuel,

sorry I just clicked on the feedback button of the question. I think I probably misunderstood the question stem. Are the 20,000 the total sales price of the cars? And don't I have to calculate the profit/loss of each car like that: 1,1x=15,000 =>~13,636 => 15,000 - 13,636 is the actual profit of this car?

Thanks for your Support.

Profit and loss are on costs price. So, $20,000 was total cost price of two cars.
User avatar
DJ1986
Joined: 05 Jul 2015
Last visit: 16 May 2016
Posts: 51
Own Kudos:
227
 [4]
Given Kudos: 3
Concentration: Real Estate, International Business
GMAT 1: 600 Q33 V40
GPA: 3.3
GMAT 1: 600 Q33 V40
Posts: 51
Kudos: 227
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
With the Allegation method this question takes 2 seconds.

+10____5____-10

The distance from average is 5:15.
User avatar
HimJ
Joined: 15 Dec 2016
Last visit: 25 Jun 2021
Posts: 6
Own Kudos:
30
 [12]
Given Kudos: 17
Location: India
GMAT 1: 600 Q44 V28
GMAT 2: 700 Q49 V37
GPA: 3.9
WE:Marketing (Real Estate)
Products:
GMAT 2: 700 Q49 V37
Posts: 6
Kudos: 30
 [12]
9
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
Hello friends, sharing with you the pure algebraic approach.

Let A & B be two cars.

As per the given info, we can deduce two equations.

As per the profit, which is 10% of A - 10% of B = 1000 that is 0.1A - 0.1B = 1000,
Multiplying the above equation we get that A - B = 10,000.

5% of total cost of A & B = 1000. So, 100% of the cost is 20,000.
OR
5/100 = 1000/x, then x=20,000.
OR
0.5(A+B) = 1000, A+B = 20,000.

Now we have two equations A+B = 20,000 & A-B = 10,000
Solving those we get that A = 15,000
That is one of the options so no need to solve for B.

CORRECT ANSWER D.

If it helped you then quickly hit that +Kudos button :-D
avatar
Soul777
Joined: 17 May 2016
Last visit: 05 Oct 2018
Posts: 10
Own Kudos:
7
 [5]
Given Kudos: 51
Location: United States
Schools: AGSM '18
Schools: AGSM '18
Posts: 10
Kudos: 7
 [5]
4
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
1) a,b - prices of cars:
10% of a - 10% of b = 1,000
a) 500-100 nope
b) 900-500 nope
c) 1100-900 nope
d) 1500-500 =1000
e) 2000-1000 = 1000 .
So we have d and e left.
2) 0,05 (a+b) = 1000:
d) 0,05 (20k) = 1k OK
e) 0,05 (30k) = 1.5 Nope.
hence d.
avatar
DmitryP
Joined: 20 Sep 2012
Last visit: 17 Nov 2025
Posts: 4
Own Kudos:
Given Kudos: 902
Location: Russian Federation
Concentration: Finance, General Management
GMAT 1: 710 Q49 V38
GPA: 3.5
Products:
GMAT 1: 710 Q49 V38
Posts: 4
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation.
User avatar
dcummins
Joined: 14 Feb 2017
Last visit: 08 Oct 2025
Posts: 1,064
Own Kudos:
2,326
 [5]
Given Kudos: 368
Location: Australia
Concentration: Technology, Strategy
GMAT 1: 560 Q41 V26
GMAT 2: 550 Q43 V23
GMAT 3: 650 Q47 V33
GMAT 4: 650 Q44 V36
GMAT 5: 600 Q38 V35
GMAT 6: 710 Q47 V41
WE:Management Consulting (Consulting)
Products:
4
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
I really like HimJ 's approach to this. It's much simpler than the official explanation or any weighted average type as its the type of logic I'd apply in business.

For clarification:
We can derive two equations

The first from profit
Let A and B represent the cost price

0.1A - 0.1B = 1000 -> 10% profit on cost price of A less 10% loss on cost price of B
A - B = 10,000

0.05 (A+B) = 1,000 -> we are told that the overall profit of $1000 represents 5%
A+B = 20,000 -> from simplifying

Combining the equations
2A = 30,000
A = 15,000

Substitute back in, B = 5000
User avatar
AnirudhaS
User avatar
LBS Moderator
Joined: 30 Oct 2019
Last visit: 25 Jun 2024
Posts: 811
Own Kudos:
872
 [1]
Given Kudos: 1,575
Posts: 811
Kudos: 872
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Let x be the cost price of both cars
5% of x = 1000,
therefore, x = 20,000
Option C and D both total to 20,000. We just check which one it is.
10% of 15,000 = 1500
10% of 5,000 = 500
Total profit = profit - loss = 1500 - 500 = 1000.
Thats the answer : D.
User avatar
TheNightKing
Joined: 18 Dec 2017
Last visit: 20 Mar 2024
Posts: 1,139
Own Kudos:
1,302
 [1]
Given Kudos: 421
Location: United States (KS)
GMAT 1: 600 Q46 V27
GMAT 1: 600 Q46 V27
Posts: 1,139
Kudos: 1,302
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
A car dealership sold two cars: the first car at a 10% profit and the second car at a 10% loss, which gave them an overall profit of 5% from these two sales. If the dealership's total profit was $1000, what was the cost price of each car?

A. $5,000 and $1,000
B. $9,000 and $5,000
C. $11,000 and $9,000
D. $15,000 and $5,000
E. $20,000 and $10,000

I used options.

We made an overall Profit. So let's assume that it is more likely that the higher priced model is sold at Profit.

A. $5,000 and $1,000
+500-100=400 Nope

B. $9,000 and $5,000
+900-500=400 Nope

C. $11,000 and $9,000
+1100-900=200 Nope Nope

D. $15,000 and $5,000
1500-500=1000. Okay. Lets make sure we are right.

Total Cost Price=20,000. Profit =1000 which is 5% of 20,000. Looks like we are in good shape.
User avatar
MHIKER
Joined: 14 Jul 2010
Last visit: 24 May 2021
Posts: 942
Own Kudos:
5,647
 [4]
Given Kudos: 690
Status:No dream is too large, no dreamer is too small
Concentration: Accounting
Posts: 942
Kudos: 5,647
 [4]
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Bunuel
A car dealership sold two cars: the first car at a 10% profit and the second car at a 10% loss, which gave them an overall profit of 5% from these two sales. If the dealership's total profit was $1000, what was the cost price of each car?

A. $5,000 and $1,000
B. $9,000 and $5,000
C. $11,000 and $9,000
D. $15,000 and $5,000
E. $20,000 and $10,000

First car \(=X\)

Second car\(= Y\)

\(1.10X+0.90Y=1.05X+1.05Y\)

\(=0.05X=0.15Y\)

\(=X=3Y\)

From options, only D satisfies this condition. So:

First car \(=$15,000\)

Second car \(= $5,000\)

The answer is \(D\)
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 20 Nov 2025
Posts: 105,409
Own Kudos:
Given Kudos: 99,987
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,409
Kudos: 778,474
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
User avatar
BottomJee
User avatar
Retired Moderator
Joined: 05 May 2019
Last visit: 09 Jun 2025
Posts: 996
Own Kudos:
Given Kudos: 1,009
Affiliations: GMAT Club
Location: India
GMAT Focus 1: 645 Q82 V81 DI82
GMAT 1: 430 Q31 V19
GMAT 2: 570 Q44 V25
GMAT 3: 660 Q48 V33
GPA: 3.26
WE:Engineering (Manufacturing)
Products:
GMAT Focus 1: 645 Q82 V81 DI82
GMAT 3: 660 Q48 V33
Posts: 996
Kudos: 1,328
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation.
User avatar
manntri
Joined: 26 Jul 2023
Last visit: 21 Mar 2024
Posts: 22
Own Kudos:
8
 [1]
Given Kudos: 6
Posts: 22
Kudos: 8
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation. This question can be more quickly solved by algebra:

first car price: x, second car price: y

10x/100 -10y/100 = 5 (x+y)/100

on simplifying , x=3y implies price of first car is a multiple of second car and multiple is 3.

quickly glance thru options, only option D works.
User avatar
CoffeeNCream
Joined: 10 Nov 2022
Last visit: 13 Sep 2024
Posts: 9
Own Kudos:
2
 [1]
Given Kudos: 11
Location: Australia
Posts: 9
Kudos: 2
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation. I'm sorry Bunuel, I have read this question solution and the discussion probably 50 times.

I am missing something here.

I understand 0.1a - 0.1b = 1000, so a - b = 10000

What I'm struggling with is the "cost price"

5 percent of TOTAL SALES = 1000, thus TOTAL SALES = 20 000

So how are we getting cost price = 20 000?


I saw Bunuel's response to this twice but I'm still at a loss.

Sorry, and thank you.
 1   2   3   
Moderators:
Math Expert
105409 posts
Founder
42395 posts