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Is x > y? (1) 12x = 4c (2) c = 3y^4

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Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   01 Jul 2020, 23:02
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Is \(x > y\)?


(1) \(12x = 4c\)

(2) \(c = 3y^4\)
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E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   01 Jul 2020, 23:20
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St. 1 or St. 2 alone is insufficient because there is no direct relation between x and y.

St. 1 and St. 2:
x = y^4

(i) y is a positive integer
=> x > y

(ii) y is a negative integer
=> x is positive
=> x > y

(iii) y is a positive fraction
=> x < y

(iv) y is a negative fraction
=> x is positive
=> x > y

=> Because of (iii), st. 1 and st. 2 are together insufficient.

Answer: E

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   01 Jul 2020, 23:33
Explanation:
To find x>y


Statement 1: 12x=4c
3x=c
cannot say about y
Not Sufficient

Statement 2: c=3y^4
Cannot say about y.
Not Sufficient.

From 1 & 2,
3x=3y^4
x=y^4
Let y= 1, then x=1 ; x>y No
if y = 2, then x = 16 ; x>y yes
Not Sufficient

IMO-E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   01 Jul 2020, 23:36
1
Kudos
Is x>y?

(1) 12x=4c
NOT SUFFICIENT.

(2) \(c=3y^4\)
NOT SUFFICIENT.

Together 1 and 2
\(12x = 12y^4\)
\(x = y^4\)
\(1 = 1^4\) NO
\(16 = 2^4\) YES

NOT SUFFICIENT.

Answer E.
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   01 Jul 2020, 23:51
1
Kudos
Statement 1:
\(12x = 4c\)
\(3x = c\)
We know only about x. Insufficient

Statement 2:
\(c = 3y^4\)

We know only about y. Insufficient

S1 + S2
\(3x = c = 3y^4\)
\(x = y^4\)

If y = 2
\(x = y^4 = 2^4 = 16 > 2\). YES

If y = \(\frac{1}{2}\)

\(x = y^4 = ( \frac{1}{2} )^4 = \frac{1}{16} < \frac{1}{2}\) NO

INSUFFICIENT

OA, E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 00:07
E

x=y^4

They can both be between 0 and 1, in which case x is less than y, or they both are more than 1. In this case x shall be greater than y.

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 01:11
1
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Individual statements are clearly insufficient as the information about the other variable is not available.

Combining both the statements, we get
=> 3x=3y^4
=> x=y^4

when y=1, x=1 => x=y
when y=-1, x=1 => x>y

Hence (E) is the answer
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 02:40
1
Kudos
IMO E

Is x>y?

(1) 12x=4c
No information about y, Not sufficient.

(2) c=3y^4
No information about x, Not sufficient

Together:
c= 3x = 3y^4
x = y^4
Let y=2=> x=16 , So x>y
Let y=0.5=> x= 0.0625 , So x<y
Not Sufficient.
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 04:11
1
Kudos
12x=4c
3x=c
while second statement implies
c=3*y^4
therefore c is positive so is x
and we have x=y^4
Now if y is between 0 and 1 y^4 will be a number less than y itself (0.1^2<0.1) therefore both statements together are insufficient imo
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 04:24
Both statement together are sufficient . as 12x=12y^4 ; x=y^4 ; so y could be 1 or -1 so both statement together are not sufficient
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 04:26
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answer is E) both statement together are not sufficient 12x=12y^4 ; x=y^4 ; y= 1 or -1 ....x>y when y=-1 and x=y when y=1 ... both together are not sufficient .
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 05:21
1. 12x=4c. Insufficient
2. c=3y^4. Insufficient

Combined, x=y^4.

x=y=1, => x = y
x=0.0001, y=0.1, => x < y
x=16, y=2 => x > y

all 3 conditions satisfy x=y^4

Insufficient.

Ans: E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 05:43
IMO E.

Stmt 1
Gives nothing about y.
Insuff.

Stmt 2
Gives nothing about x.
Insuff.

1+2.

3x = 3y^4

x=y^4

x could be 1
x could be 0.
x could be fraction.
We cant say its greater than or less than y.
So E

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 05:54
IMO E.

Stmt 1
Gives nothing about y.
Insuff.

Stmt 2
Gives nothing about x.
Insuff.

1+2.

3x = 3y^4

x=y^4

x could be 1
x could be 0.
x could be fraction.
We cant say its greater than or less than y.
So E

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 13:02
Ans - E

Statement 1
3x= c, without value of y we cannot tell, so not sufficient

Statement 2
C= 3y4, without value of x we cant determine

Statement 1 &2
We get x=y4,
With x=1, x=y
With x= 2 , y= 16 so y>x
So clearly it’s giving two different so it is not sufficient

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 21:17
Is x>y?


(1) 12x=4c

(2) c=3y^4

1) 3x = c
no info about y
insufficient

2)c=3y^4
no info about x
insufficient

1+2)
3x=3y^4
x=y^4

is y^4>y?
if y=integers, yes
if y=decimals, no
insufficient

Ans E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   02 Jul 2020, 21:37
Statement 1:
\(12x = 4c \)
=> \(3x = c\)
Insufficient as no information about y.

Statement 2:
\(c = 3y^4\)
Insufficient as no information about x

Combining both we get
\(3x = 3y^4\)
=> \(x = y^4\)
Can be of any value

Hence, OA is (E).
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink] New post   03 Jul 2020, 01:41
Clearly E.

Question doesn't state that x, y, and c cannot all be equal to 0.
Therefore, x=y=c=0 is a condition that will always be true, unless one of the statements tells us that they are not equal to 0.
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4 [#permalink]
03 Jul 2020, 01:41
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