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# Is x > y? (1) 12x = 4c (2) c = 3y^4

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Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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01 Jul 2020, 22:02
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68% (01:03) correct 32% (00:48) wrong based on 60 sessions

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Is $$x > y$$?

(1) $$12x = 4c$$

(2) $$c = 3y^4$$

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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01 Jul 2020, 22:20
1
St. 1 or St. 2 alone is insufficient because there is no direct relation between x and y.

St. 1 and St. 2:
x = y^4

(i) y is a positive integer
=> x > y

(ii) y is a negative integer
=> x is positive
=> x > y

(iii) y is a positive fraction
=> x < y

(iv) y is a negative fraction
=> x is positive
=> x > y

=> Because of (iii), st. 1 and st. 2 are together insufficient.

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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01 Jul 2020, 22:33
Explanation:
To find x>y

Statement 1: 12x=4c
3x=c
Not Sufficient

Statement 2: c=3y^4
Not Sufficient.

From 1 & 2,
3x=3y^4
x=y^4
Let y= 1, then x=1 ; x>y No
if y = 2, then x = 16 ; x>y yes
Not Sufficient

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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01 Jul 2020, 22:36
1
Is x>y?

(1) 12x=4c
NOT SUFFICIENT.

(2) $$c=3y^4$$
NOT SUFFICIENT.

Together 1 and 2
$$12x = 12y^4$$
$$x = y^4$$
$$1 = 1^4$$ NO
$$16 = 2^4$$ YES

NOT SUFFICIENT.

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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01 Jul 2020, 22:51
1
Statement 1:
$$12x = 4c$$
$$3x = c$$
We know only about x. Insufficient

Statement 2:
$$c = 3y^4$$

We know only about y. Insufficient

S1 + S2
$$3x = c = 3y^4$$
$$x = y^4$$

If y = 2
$$x = y^4 = 2^4 = 16 > 2$$. YES

If y = $$\frac{1}{2}$$

$$x = y^4 = ( \frac{1}{2} )^4 = \frac{1}{16} < \frac{1}{2}$$ NO

INSUFFICIENT

OA, E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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01 Jul 2020, 23:07
E

x=y^4

They can both be between 0 and 1, in which case x is less than y, or they both are more than 1. In this case x shall be greater than y.

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 00:11
1
Individual statements are clearly insufficient as the information about the other variable is not available.

Combining both the statements, we get
=> 3x=3y^4
=> x=y^4

when y=1, x=1 => x=y
when y=-1, x=1 => x>y

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 01:40
1
IMO E

Is x>y?

(1) 12x=4c
No information about y, Not sufficient.

(2) c=3y^4
No information about x, Not sufficient

Together:
c= 3x = 3y^4
x = y^4
Let y=2=> x=16 , So x>y
Let y=0.5=> x= 0.0625 , So x<y
Not Sufficient.
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 03:11
1
12x=4c
3x=c
while second statement implies
c=3*y^4
therefore c is positive so is x
and we have x=y^4
Now if y is between 0 and 1 y^4 will be a number less than y itself (0.1^2<0.1) therefore both statements together are insufficient imo
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 03:24
Both statement together are sufficient . as 12x=12y^4 ; x=y^4 ; so y could be 1 or -1 so both statement together are not sufficient
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 03:26
1
answer is E) both statement together are not sufficient 12x=12y^4 ; x=y^4 ; y= 1 or -1 ....x>y when y=-1 and x=y when y=1 ... both together are not sufficient .
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 04:21
1. 12x=4c. Insufficient
2. c=3y^4. Insufficient

Combined, x=y^4.

x=y=1, => x = y
x=0.0001, y=0.1, => x < y
x=16, y=2 => x > y

all 3 conditions satisfy x=y^4

Insufficient.

Ans: E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 04:43
IMO E.

Stmt 1
Insuff.

Stmt 2
Insuff.

1+2.

3x = 3y^4

x=y^4

x could be 1
x could be 0.
x could be fraction.
We cant say its greater than or less than y.
So E

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 04:54
IMO E.

Stmt 1
Insuff.

Stmt 2
Insuff.

1+2.

3x = 3y^4

x=y^4

x could be 1
x could be 0.
x could be fraction.
We cant say its greater than or less than y.
So E

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 12:02
Ans - E

Statement 1
3x= c, without value of y we cannot tell, so not sufficient

Statement 2
C= 3y4, without value of x we cant determine

Statement 1 &2
We get x=y4,
With x=1, x=y
With x= 2 , y= 16 so y>x
So clearly it’s giving two different so it is not sufficient

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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 20:17
Is x>y?

(1) 12x=4c

(2) c=3y^4

1) 3x = c
insufficient

2)c=3y^4
insufficient

1+2)
3x=3y^4
x=y^4

is y^4>y?
if y=integers, yes
if y=decimals, no
insufficient

Ans E
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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02 Jul 2020, 20:37
Statement 1:
$$12x = 4c$$
=> $$3x = c$$
Insufficient as no information about y.

Statement 2:
$$c = 3y^4$$
Insufficient as no information about x

Combining both we get
$$3x = 3y^4$$
=> $$x = y^4$$
Can be of any value

Hence, OA is (E).
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Re: Is x > y? (1) 12x = 4c (2) c = 3y^4  [#permalink]

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03 Jul 2020, 00:41
Clearly E.

Question doesn't state that x, y, and c cannot all be equal to 0.
Therefore, x=y=c=0 is a condition that will always be true, unless one of the statements tells us that they are not equal to 0.
Re: Is x > y? (1) 12x = 4c (2) c = 3y^4   [#permalink] 03 Jul 2020, 00:41