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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
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MrWallSt wrote:
If x / (x+y) = n, and x / (x-y) = m, then x/y=? (|x| does not equal |y|, xy does not equal 0)

A. 3mn/2
B. (3m)/(2n)
C. (n * (m+2))/2
D. 2nm / (m-n)
E. (n^2 - m^2) / nm


Let us say x = 3, y = 1, n = 0.75, m = 1.5

x/y = 3

(A) 3(3/2)(3/4) = 9/8 (Eliminated)
(B) 3(3/2) 2(3/4) = (Eliminated)
(C) (3/4) (3/2 + 2)/2 = (Eliminated)
(D) 2(3/4)(3/2)/(.75) = 3 (BINGO!)
(E) Eliminated

Hence answer is D
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
CrackVerbalGMAT wrote:
MrWallSt wrote:
If x / (x+y) = n, and x / (x-y) = m, then x/y=? (|x| does not equal |y|, xy does not equal 0)

A. 3mn/2
B. (3m)/(2n)
C. (n * (m+2))/2
D. 2nm / (m-n)
E. (n^2 - m^2) / nm


Let us say x = 3, y = 1, n = 0.75, m = 1.5

x/y = 3

(A) 3(3/2)(3/4) = 9/8 (Eliminated)
(B) 3(3/2) 2(3/4) = (Eliminated)
(C) (3/4) (3/2 + 2)/2 = (Eliminated)
(D) 2(3/4)(3/2)/(.75) = 3 (BINGO!)
(E) Eliminated

Hence answer is D


Sorry for opening a long answered question.

with algebric solution, i am getting many answers in terms of m & n. so the problem needed to be solved by picking numbers.
when we pick x = 3 & y = 1. I am getting B & D both as answer and but with x = 2 & y= 3. I am getting D as an answer. shouldnt it be unique for all numbers, since there is no restriction (like x, y = consequetive or x>y or viceversa) on picking numbers.
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
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Alaukik wrote:
CrackVerbalGMAT wrote:
MrWallSt wrote:
If x / (x+y) = n, and x / (x-y) = m, then x/y=? (|x| does not equal |y|, xy does not equal 0)

A. 3mn/2
B. (3m)/(2n)
C. (n * (m+2))/2
D. 2nm / (m-n)
E. (n^2 - m^2) / nm


Let us say x = 3, y = 1, n = 0.75, m = 1.5

x/y = 3

(A) 3(3/2)(3/4) = 9/8 (Eliminated)
(B) 3(3/2) 2(3/4) = (Eliminated)
(C) (3/4) (3/2 + 2)/2 = (Eliminated)
(D) 2(3/4)(3/2)/(.75) = 3 (BINGO!)
(E) Eliminated

Hence answer is D


Sorry for opening a long answered question.

with algebric solution, i am getting many answers in terms of m & n. so the problem needed to be solved by picking numbers.
when we pick x = 3 & y = 1. I am getting B & D both as answer and but with x = 2 & y= 3. I am getting D as an answer. shouldnt it be unique for all numbers, since there is no restriction (like x, y = consequetive or x>y or viceversa) on picking numbers.


When you take one of the numbers as 1 or 0, or when you take numbers to be equal, you could get multiple options satisfying your conditions.

For example, if n = 1
3n/(m+n) will give the same result as 3/(m+n).

Sometimes, you will get the same answer from multiple options if the options are written intelligently. So you could need to try out 2 or even 3 sets of values.
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
VeritasPrepKarishma wrote:
When you take one of the numbers as 1 or 0, or when you take numbers to be equal, you could get multiple options satisfying your conditions.

For example, if n = 1
3n/(m+n) will give the same result as 3/(m+n).

Sometimes, you will get the same answer from multiple options if the options are written intelligently. So you could need to try out 2 or even 3 sets of values.


well the question states xy != 0, so x or y cant be 0. also |x| != |y| so they cant be equal either.

I was hoping for a more bullet proof solution for this question. as 2 sets will take more time. we will get answer but at a huge expense of time.
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
Expert Reply
Alaukik wrote:
VeritasPrepKarishma wrote:
When you take one of the numbers as 1 or 0, or when you take numbers to be equal, you could get multiple options satisfying your conditions.

For example, if n = 1
3n/(m+n) will give the same result as 3/(m+n).

Sometimes, you will get the same answer from multiple options if the options are written intelligently. So you could need to try out 2 or even 3 sets of values.


well the question states xy != 0, so x or y cant be 0. also |x| != |y| so they cant be equal either.

I was hoping for a more bullet proof solution for this question. as 2 sets will take more time. we will get answer but at a huge expense of time.


Note that it is a generic comment about number plugging - not just specific to this question.

Also, I have given the algebra solution above - as "bulletproof" as you can get.
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
VeritasPrepKarishma your solution is excellence. I am wondering, how do we know that one form of fraction (you mentioned it as case) is easier to manipulate than another? I tried to solve this problem using the original form of fraction but I ended up nowhere. Do you have the solution using original form of the fraction?
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
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evdo wrote:
VeritasPrepKarishma your solution is excellence. I am wondering, how do we know that one form of fraction (you mentioned it as case) is easier to manipulate than another? I tried to solve this problem using the original form of fraction but I ended up nowhere. Do you have the solution using original form of the fraction?


When you need to separate the variables, multiple terms in the numerator are easy to handle since you can split them:

(x+y)/ x = x/x + y/x = 1 + y/x

But if they are in the denominator, you cannot separate them.

You can start with the equations as they are but you will eventually cross multiply to simplify the denominator. If you do different things with the equations, you will get different but equivalent expressions. So a case can be made to do the question by number plugging instead.
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
Hello,

Could someone explain why is it not possible to assume that: x = n(x+y) and x = m(x-y); so n(x+y) = m(x-y) if we solve this we arrive to x/y = (n+m) / (m-n)

I know it is not the correct answer, but I would like to understand my mistake. Many thanks
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
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jmmanquez wrote:
Hello,

Could someone explain why is it not possible to assume that: x = n(x+y) and x = m(x-y); so n(x+y) = m(x-y) if we solve this we arrive to x/y = (n+m) / (m-n)

I know it is not the correct answer, but I would like to understand my mistake. Many thanks


It is not incorrect, it is just not what you need. Different manipulations can lead to different but equivalent expressions.
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If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
MrWallSt wrote:
If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not equal |y|, xy does not equal 0)

A. 3mn/2
B. (3m)/(2n)
C. (n * (m+2))/2
D. 2nm / (m-n)
E. (n^2 - m^2) / nm


Asked: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not equal |y|, xy does not equal 0)

Let us take x = 3; y = 2
x/y = 3/2 = 1.5
3/5 = n = .6
2/1 = m = 2

A. 3mn/2
3*2*.6/2 = 1.8; NO
B. (3m)/(2n)
6*1.2 = 7.2; NO
C. (n * (m+2))/2
.6*4/2 = 1.2; NO
D. 2nm / (m-n)
2*.6*2/(2-.6) = 2.4/1.4 = 12/7; NO
E. (n^2 - m^2) / nm
(.36 - 4 )1.2 ; NO

MrWallSt
All answers seem incorrect.
Please check.
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
Kindly see the attachment.
It took me around 2:45 min to solve this.

At first, my answer didn't match any of the options. I tried checking my calculation but didn't get to the right choice. Lastly, I went to replacing m and n in options and landed in D. Option D was my first guess, but since it was not exam mode, I was inclined on solving this.

VeritasKarishma, your both approaches help to get a new perspective on this question.

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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
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This is the simplest question

substitute values to each variable and check with the option provided

assuming x=5 and y = 1
m =5/4 and n=5/6

and my x/y should be = 5 (ie,5/1)

only in option D when i substitute the variables I get the value as 5.. Hence my answer is D

(In Gmat the time is a luxury.. try to avoid algebra whenever possible)
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
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sambitspm wrote:
Kindly see the attachment.
It took me around 2:45 min to solve this.

At first, my answer didn't match any of the options. I tried checking my calculation but didn't get to the right choice. Lastly, I went to replacing m and n in options and landed in D. Option D was my first guess, but since it was not exam mode, I was inclined on solving this.

VeritasKarishma, your both approaches help to get a new perspective on this question.


Hi
I dont quite seem to understand how did you checked each answer? could you please elaborate more on that?
Also , after getting x/y as m+n/m-n , i assumed m=5 and n=4 but still none of the answer matches. could you help on that please?
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Re: If x/(x+y) = n, and x/(x-y) = m, then x/y = ? (|x| does not [#permalink]
Hello

Can someone please tell what is wrong with this way of solving....none of the answer choice is matching

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