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Quant Question of the Day Chat

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aayushimehta12
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 04:28
can anyone please tell me the answer asap
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Bunuel
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 04:30
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aayushimehta12 wrote:
can anyone please tell me the answer asap

Check here: 

https://gmatclub.com/forum/if-x-3-2-whi ... 19682.html
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Nidhi1715
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:16
Edoua wrote:
I count the favorable case a b c d e … t abc def ghi Jkl mno pqr —st— (6cases) —a—. bcd efg hij klm nop qrs —t —(6cases) —a b— cde fgh ijk lmn opq rst (6 cases) 6*3

Hey while counting the favourable cases here "consecutive names on the list"
Why will we not multiply 6*3 by 3!? 3! assuming that say abc (three consecutive people) can be selected in 6 ways?
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Nidhi1715
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:40
For the first question, on solving the equation, whatever answers you’ll get for X, if you’ll put them again in the equation to cross check, you’ll see that RHS will be negative. And absolute value of any equation can never be negative. Hence ans will be 0
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aayushimehta12
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:43
but -1 (2x - 3) = x -5 will be for value of X = 3/8
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:44
Number of odd integers from 1 to 79 is 40
Number of odd integers from 1 to 23 is 12
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Shwarma
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:45
The first question
Solve when |2x-3| is positive = x value is -2 so, RHS becomes -7 which is not possible as LHS has to be positive
When |2x-3| is negative, x=8/3, even then RHS will be -7/3 which is again negative, so 0 solution is the answer
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niels.v_
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:45
the theory behind it is that, as the left side is an absolute value which must be equal or greater than zero, the left side must be as well, this means that x-5 > 0 or x>5. As you can see none of the possibilities are greater than 5 which means they’re not valid therefore the answer is 0.

aayushimehta12 wrote:
but -1 (2x - 3) = x -5 will be for value of X = 3/8

for future refernce, if you cant seem to figure out a question, just type the question in the search bar above and you’ll likely find a detailed explenation of that particular question on the forum!
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aayushimehta12
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:50
Thank you all

but can anyone explain question 2

further 2
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:55
question 2:
formula given -- first 5 odd numbers consecutive - aka 1,3,5,7-

so you need to find the formula for n^2 upto 25 --> n =13 (13 odd numbers)-> but since 26 is inclusive it will be 12
79--> N=40
so you find the difference between them
40^2-12^2 to get the answer
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 05:59
anyone cal solve the compound interest math
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aayushimehta12
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 06:01
Shwarma wrote:
question 2: formula given -- first 5 odd numbers consecutive - aka 1,3,5,7- so you need to find the formula for n^2 upto 25 --> n =13 (13 odd numbers)-> but since 26 is inclusive it will be 12 79--> N=40 so you find the difference between them 40^2-12^2 to get the answer

I understand how to get 40, but I thought it should be 40 and 13 not 40 and 12, because using An= a + (n-1) 2, formula on both we get 40 and 13 as answers.
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 06:02
Nidhi1715 wrote:
Hey while counting the favourable cases here "consecutive names on the list" Why will we not multiply 6*3 by 3!? 3! assuming that say abc (three consecutive people) can be selected in 6 ways?

Because we are filling up three numbers in 6 cases
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aayushimehta12
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 06:12
Hey Bunuel are you available ?
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 06:22
aayushimehta12 wrote:
I understand how to get 40, but I thought it should be 40 and 13 not 40 and 12, because using An= a + (n-1) 2, formula on both we get 40 and 13 as answers.

The question says 25 to 79, inclusive
so the sum should be from 26 till 79

If you take 13, then you will be removing 25 from the answer
so you need to take one less term.

*from 25 till 79
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Nidhi1715
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 06:37
for Q.1 here,
impact of increase in speed will be:
impact of increase in load will be:
and both these things will be added to 24 so that equation is: 24 + (-1/2(S-40))/10 + (-L/500)

when you’ll solve this, you’ll get the ans
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 07:28
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words starting with E: Remaining RRIV will be arranged in 4!/2! or 12 ways. Similarly words starting from I, so 24 gone. Next RE_,_,_ : 3! or 6 ways, RI_,_,_ again 6 ways. Total 24+6+6 or 36 gone. 37 will be RREIV, then RREVI and 39th RRIEV
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allisondesouza
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 08:04
Sylvia is driving at 48 miles/hr and her husband Kal is driving at 55 miles/hr. If he starts off from home 45 minutes after she has left, how long would he take to catch up with her on the journey if they’re both taking
the same route?

can someone help me with this?
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allisondesouza
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 08:12
answer is 5 hours 8 minutes
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   13 Apr 2024, 08:13
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In 45 minutes, S would have covered 36 miles. K can cover 55-48 or 7 kms extra in one hour. So to cover 36 he requires 36/7 which is 5 hrs 1/7*60 minutes, that is 5 h and 8 .5 min
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Re: Quant Question of the Day Chat [#permalink]
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