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Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 58310
Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so  [#permalink]

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New post 31 Mar 2019, 22:51
1
5
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

19% (02:44) correct 81% (02:29) wrong based on 26 sessions

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Manager
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S
Joined: 04 Sep 2016
Posts: 66
Location: Germany
GPA: 3
CAT Tests
Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so  [#permalink]

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New post 09 Apr 2019, 02:44
Can someone tell how to solve this?

I got 60 which is I guess is the trap answer

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Joined: 25 Feb 2019
Posts: 336
Re: Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so  [#permalink]

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New post 14 Apr 2019, 11:55
1
IMO E ,

in the attached picture ,

in triangle DMC,

DC = MC =6 (sidea opposite to equal angles )

now in right angle triangle BMC ,

here I applied cos formula from trigonometry

cos $ = BC/MC =3/6 = 1/2 = cos $ = cos 60

$ = 60
so angle BMC = 30

now
angle AMD + DMC + 30 = 180

calculate AMD = 75



award kudos if helpful

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Senior Manager
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G
Joined: 25 Feb 2019
Posts: 336
Re: Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so  [#permalink]

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New post 14 Apr 2019, 11:56
Sory guys , it is not giving me option to upload the picture which i drew

:(

you can draw your self and assume

angle MCB = $

and follow the above mentioned approach

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S
Joined: 04 Sep 2016
Posts: 66
Location: Germany
GPA: 3
CAT Tests
Re: Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so  [#permalink]

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New post 14 Apr 2019, 13:03
Gmat doesnt expect us to use trigonometry....there must be another way to solve this

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Re: Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so   [#permalink] 14 Apr 2019, 13:03
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Rectangle ABCD has AB = 6 and BC = 3. Point M is chosen on side AB so

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