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What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project
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ITIZCODE wrote: What is the median number of employees assigned per project for the projects at Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. Not sufficient on its own. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project. Not sufficient on its own. (1)+(2) Since 35% of of the projects have 2 or fewer (\(\leq{2}\))employees and 25% of the projects have 4 or more (\(\geq{4}\)) employees, then 100%(25%+35%)=40% of the projects have exactly 3 employees assigned to each of them. So, the median number of employees assigned per project is 3. Sufficient. Answer: C. To elaborate more: consider there are 100 projects: \(\{p_1, \ p_2, \ ... , \ p_{100}\}\). The values of \(p_1\) to \(p_{35}\) will be 0, 1, or 2; the values of \(p_{36}\) to \(p_{75}\) will be exactly 3; the values of \(p_{76}\) to \(p_{100}\) will be 4 or more. \(Median=\frac{p_{50}+p_{51}}{2}=\frac{3+3}{2}=3\). For example list can be: \(\{2, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 4, \ ..., \ (p_{100}=4)\}\); OR: \(\{0, \ 0, \ 1, \ 1, \ 1, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 5, \ 7, \ 27, \ ..., \ (p_{100}=10000)\}\) (of course there are a lot of other breakdowns). In any case median=3. Hope it's clear. P.S. Please post PS questions in the PS subforum: gmatproblemsolvingps140/ and DS questions in the DS subforum: gmatdatasufficiencyds141/ No posting of PS/DS questions is allowed in the main Math forum.
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Re: What is the median number of employees assigned per project [#permalink]
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Will vote for C
let total be "x" projects i.e 100% projec
(A) 25% projects has number of employees >= 4
 we dont know anything about other 75% projects
(B) 35% project has number of employees <= 2
 we dont know anything about other 65% projects
(C)
for 35% > No. of emp <= 2 for 25% > No. of emp >= 4
based on above data we can calculate that Remaining 40% of projects > No. of emp = 3 (which is between 2 < no. of emp < 4)



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30 Aug 2012, 20:42
bunuel sir great reply ... your approach to the answers by taking apt samples scare me i feel like i just cant do it without error
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What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project Ruled out quickly A,B,D. remained with C, E. chose E. then looked here: whatisthemediannumberofemployeesassignedperproject131892.htmland i still dont understand bunuel's way. why the employees who are not in the 25% or 35% must have exactly 3 employees? thanks
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roygush wrote: What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project Ruled out quickly A,B,D. remained with C, E. chose E. then looked here: whatisthemediannumberofemployeesassignedperproject131892.htmland i still dont understand bunuel's way. why the employees who are not in the 25% or 35% must have exactly 3 employees? thanks 25% of company Z projects have 4 or more that (4,5,6,....) 35% of company z projects have 2 or less (0,1,2 )... there must b 3 employees per project of company z which consists of (25+35=60) and 10060=40%.. 0,1,2 must be first 35 projects 3 employees for next 40 project and 4 or more than 4 employees for remaning 25 projects..
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ITIZCODE wrote: What is the median number of employees assigned per project for the projects at Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project Ans: : Median is the middle value. Statements 1 and 2 alone give us insufficient data but when we combine both of them we see that 25 % have 4 or more and 35% have 2 or less therefore 40 %have 3 employees. Therefore the median would be 3 and the answer is (C).
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Re: What is the median number of employees assigned per project [#permalink]
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Bunuel wrote: ITIZCODE wrote: What is the median number of employees assigned per project for the projects at Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. Not sufficient on its own. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project. Not sufficient on its own. (1)+(2) Since 35% of of the projects have 2 or fewer (\(\leq{2}\))employees and 25% of the projects have 4 or more (\(\geq{4}\)) employees, then 100%(25%+35%)=40% of the projects have exactly 3 employees assigned to each of them. So, the median number of employees assigned per project is 3. Sufficient. Answer: C. To elaborate more: consider there are 100 projects: \(\{p_1, \ p_2, \ ... , \ p_{100}\}\). The values of \(p_1\) to \(p_{35}\) will be 0, 1, or 2; the values of \(p_{36}\) to \(p_{75}\) will be exactly 3; the values of \(p_{76}\) to \(p_{100}\) will be 4 or more. \(Median=\frac{p_{50}+p_{51}}{2}=\frac{3+3}{2}=3\). For example list can be: \(\{2, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 4, \ ..., \ (p_{100}=4)\}\); OR: \(\{0, \ 0, \ 1, \ 1, \ 1, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 5, \ 7, \ 27, \ ..., \ (p_{100}=10000)\}\) (of course there are a lot of other breakdowns). In any case median=3. Hope it's clear. P.S. Please post PS questions in the PS subforum: gmatproblemsolvingps140/ and DS questions in the DS subforum: gmatdatasufficiencyds141/ No posting of PS/DS questions is allowed in the main Math forum. I Did not understand this. How can you deduce about the 40% of the projects based on the information given. The problem just says 25% of the projects have 4 or more. 35% of the projects have 2 or less. So it does not talk anything about 40%. 40 % can be 5,6,7 or anything right?? Could you explain it in detail.
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rajathpanta wrote: Bunuel wrote: ITIZCODE wrote: What is the median number of employees assigned per project for the projects at Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. Not sufficient on its own. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project. Not sufficient on its own. (1)+(2) Since 35% of of the projects have 2 or fewer (\(\leq{2}\))employees and 25% of the projects have 4 or more (\(\geq{4}\)) employees, then 100%(25%+35%)=40% of the projects have exactly 3 employees assigned to each of them. So, the median number of employees assigned per project is 3. Sufficient. Answer: C. To elaborate more: consider there are 100 projects: \(\{p_1, \ p_2, \ ... , \ p_{100}\}\). The values of \(p_1\) to \(p_{35}\) will be 0, 1, or 2; the values of \(p_{36}\) to \(p_{75}\) will be exactly 3; the values of \(p_{76}\) to \(p_{100}\) will be 4 or more. \(Median=\frac{p_{50}+p_{51}}{2}=\frac{3+3}{2}=3\). For example list can be: \(\{2, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 4, \ ..., \ (p_{100}=4)\}\); OR: \(\{0, \ 0, \ 1, \ 1, \ 1, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 5, \ 7, \ 27, \ ..., \ (p_{100}=10000)\}\) (of course there are a lot of other breakdowns). In any case median=3. Hope it's clear. P.S. Please post PS questions in the PS subforum: gmatproblemsolvingps140/ and DS questions in the DS subforum: gmatdatasufficiencyds141/ No posting of PS/DS questions is allowed in the main Math forum. I Did not understand this. How can you deduce about the 40% of the projects based on the information given. The problem just says 25% of the projects have 4 or more. 35% of the projects have 2 or less. So it does not talk anything about 40%. 40 % can be 5,6,7 or anything right?? Could you explain it in detail. 35 of the projects have 2 or fewer employees. 25 of the projects have 4 or more employees. How many employees can be assigned to the remaining 40 projects? The ranges \(\leq{2}\) and \(\geq{4}\) are covered, thus the remaining 40 projects have 3 employees assigned to them. Hope it's clear.
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1st 35% are either 1 or 2 and last 25% are 4 and above hence 35  75% should be 3



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Aren't we assuming here that, statement 1 and 2 refer to highest 25 and bottom 35 percent of the employees, couldn't it be first 35 % then the next 25% and the remaining 40% with unknown number of employees per project, then the median will lie in 4 or more employees, we do not have any particular value and hence E as the correct answer.



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raxsin12 wrote: Aren't we assuming here that, statement 1 and 2 refer to highest 25 and bottom 35 percent of the employees, couldn't it be first 35 % then the next 25% and the remaining 40% with unknown number of employees per project, then the median will lie in 4 or more employees, we do not have any particular value and hence E as the correct answer. Statement 2 and 1 must refer to the bottom and to the highest part. "couldn't it be first 35 % then the next 25% and the remaining 40%"? NO. The first 35% have 2 or fewer (till here correct), but then your reasoning goes against the info in statement 1. What you are saying is that 25%+40%= 65% has 4 or more employees => wrong, look at statement 1: (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. Hope it's clear P.S: Welcome to GMAT Club!
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Hi,
i understand the answers, although i must say there is no information that says that no percentage has more than for example 5 employees per project. It could be possible to have a 25% with 4 or more, and from there a group that has 5 or more. Both equalities would still be right. For example a 25% thats has 4 or more, and only 15% that has 5 or more. A group within a group. I hope i made myself clear... In that case the answer for me would be "e"
thank you in advance,



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Statement (1) by itself is insufficient because we have no clue how the rest of the employees are assigned... same problem with statement (2).
When we combine the statement, we know that all the other projects have 3 employees assigned to each of them. If we were to write out the list, "3" would cover the middle terms, so it will end up being the median of the set. Hence C.



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I've solved it this way (see attachment) > the mid section of 40% =3 (it must be an integer, you cannot have fractions when dealing with persons So Statement 1+2 are sufficient (C)
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Detailed Solution StepI: Given Info
The question asks us to find the median number of employees assigned per project for projects at Company Z, using the 2 statements given. StepII: Interpreting the Question Statement
To find the median number of employees, we need to somehow extract the central value for employees, when arranged in ascending order. Central value or median value will be the exact determination of value at the 50%th observation. StepIII: StatementI
Statement I gives us the information about the 25% of projects have 4 or more employees assigned to each project. Now let us say we have 100 projects. There could be a possibility that remaining 75 projects (>50 projects) have 3 employees. Then the central observation (50%th observation in this case 50th project value in total 100 projects) will have a median value of 3 employees. But the remaining 75 projects can have 2 employees as well. Then the median will be 2. So we cannot determine with exact surety, the exact value of median at 50%th observation. Hence, statement 1 is not sufficient to answer the question. StepIV: StatementIIStatement II gives us information that 35% of the projects have 2 or fewer employees assigned to each project. Now, the remaining 65 projects (>50 projects) can have 3 employees. Then the central observation (50%th observation in this case 50th project value in total 100 projects) will have a median value of 3 employees. But the remaining 65 projects(>50 projects) can have a median value of 4 employees as well. Then the median value will be 4 employees. So we cannot determine with exact surety, the exact value of median at 50%th observation. Hence, statement 2 is not sufficient to answer this question. StepV: Combining Statements I & IIWhen we combine both the statements we know the value of 25% of projects (4 or more employees) and 35% projects(2 or fewer employees). So the remaining 40 projects (<50 projects) will have 3 employees. When the observations are arranged in ascending order. The first 35 observations will have 2 or fewer employees and next 40 observations will have 3 employees and then next 25 observations will have 4 or more employees. Thus, the median number of employees will be 3. Hence, the exact determination of central value or value at 50%th observation is 3. So the correct answer is C. Both the statements together are sufficient. Key Takeaways Use of concept of median and evaluating all possible value of central value (median value) for observations to be able to find exact value at 50%th observation (when values arranged in ascending order).



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Each statement alone is insufficient Combining the two, we understand that there are three categories of employees. Group1: Less than 2 Group 2: Between 2 and 4 i.e. 3 Group 3: Greater than or equal to 4. The media falls in the mid  the 50th percent, which is group 2 Hence C, Both statements together are sufficient.
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Dear Friends, I need your help, coz I'm having problem I have two questions: 1) What if there is no project with THREE employees? Why can't 40% of projects have 5 or more employees or only 1 employee for that matter 2) I couldn't understand why 40% must be between 2 (35%) and 4 (25%): please see the attachment below. I would to know the reasoning behind why 3 employees (40%) must be between 2 and 4. The question does not say that 25% is at the higher band or that the 35% is at the lower band. (Although we can deduce 25% band is higher than the 35% band). Why can't the rest 100(25+35)=40% be at an even higher band (eg 5 employees or more) ? It hasn't been stated nowhere that 35% is the 1st and 25% is the last : rohantiwari wrote: 1st 35% are either 1 or 2 and last 25% are 4 and above hence 35  75% should be 3 I would be so grateful, if u could explain me thoroughly. Thank you very much! Bunuel wrote: What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. Not sufficient on its own. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project. Not sufficient on its own. (1)+(2) Since 35% of of the projects have 2 or fewer (\(\leq{2}\))employees and 25% of the projects have 4 or more (\(\geq{4}\)) employees, then 100%(25%+35%)=40% of the projects have exactly 3 employees assigned to each of them. So, the median number of employees assigned per project is 3. Sufficient. Answer: C. To elaborate more: consider there are 100 projects: \(\{p_1, \ p_2, \ ... , \ p_{100}\}\). The values of \(p_1\) to \(p_{35}\) will be 0, 1, or 2; the values of \(p_{36}\) to \(p_{75}\) will be exactly 3; the values of \(p_{76}\) to \(p_{100}\) will be 4 or more. \(Median=\frac{p_{50}+p_{51}}{2}=\frac{3+3}{2}=3\). For example list can be: \(\{2, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 4, \ ..., \ (p_{100}=4)\}\); OR: \(\{0, \ 0, \ 1, \ 1, \ 1, \ 2, \ 2, \ ..., \ (p_{35}=2), \ (p_{36}=3), \ 3, \ ..., \ (p_{75}=3), \ (p_{76}=4), \ 5, \ 7, \ 27, \ ..., \ (p_{100}=10000)\}\) (of course there are a lot of other breakdowns). In any case median=3.
BrainLab wrote: I've solved it this way (see attachment) > the mid section of 40% =3 (it must be an integer, you cannot have fractions when dealing with persons So Statement 1+2 are sufficient (C) hdwnkr wrote: Each statement alone is insufficient Combining the two, we understand that there are three categories of employees. Group1: Less than 2 Group 2: Between 2 and 4 i.e. 3 Group 3: Greater than or equal to 4. The media falls in the mid  the 50th percent, which is group 2 Hence C, Both statements together are sufficient. Zarrolou wrote: Statement 2 and 1 must refer to the bottom and to the highest part. "couldn't it be first 35 % then the next 25% and the remaining 40%"? NO. The first 35% have 2 or fewer (till here correct), but then your reasoning goes against the info in statement 1. What you are saying is that 25%+40%=65% has 4 or more employees => wrong, look at statement 1: (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project.
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studentsensual wrote: Dear Friends, I need your help, coz I'm having problem I have two questions: 1) What if there is no project with THREE employees? Why can't 40% of projects have 5 or more employees or only 1 employee for that matter 2) I couldn't understand why 40% must be between 2 (35%) and 4 (25%): please see the attachment below. I would to know the reasoning behind why 3 employees (40%) must be between 2 and 4. The question does not say that 25% is at the higher band or that the 35% is at the lower band. (Although we can deduce 25% band is higher than the 35% band). Why can't the rest 100(25+35)=40% be at an even higher band (eg 5 employees or more) ? It hasn't been stated nowhere that 35% is the 1st and 25% is the last : rohantiwari wrote: 1st 35% are either 1 or 2 and last 25% are 4 and above hence 35  75% should be 3 I would be so grateful, if u could explain me thoroughly. Thank you very much! Because "5 or more" is already a part of "4 or more" set. Look, the number of employees assigned to a project could be any of the following: 0 (debatable but ok), 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ... and so on When you say 35% project have 2 or fewer employees assigned, it means that 25% projects have either 0 or 1 or 2 employees assigned. All projects that have 1 employee assigned to them are a part of this 25%. Say, this is the first group. When you say 25% projects have 4 or MORE employees assigned, it includes all projects with 4 or 5 or 6 or 7 or 8 etc employees assigned to them. Any project that has 5 or more employees is already a part of this 25%. This is the second group. So what about the rest of the 40% projects? Can they have 1 employee assigned? No. All those projects are accounted for in first group. Can they have 6 employees assigned? No. All those projects are accounted for in second group. The only number left that is not accounted for in wither group is 3. So 40% projects must have exactly 3 employees assigned. Makes sense, now?
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(1) If 25 % of the projects at Company Z have 4 or more employees assigned to each project, then 75% of the projects have less than 4 employees. The median thus would be less than 4. But don't know its exact value. Insufficient. BCE (2) Therefore 65% of the projects have more than 2 employees. But still we do not have an exact value. Combine the two statements: 2<Median number of employees<4 Thus its 3. C
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