Orange08
Bunuel, many thanks for your explanation.
One query : while considering median, we need to arrange the numbers in sequence, i guess.
If there are 20 projects,
1) 35% i.e. 7 projects have value as 4,5,6,7,8,8,8
2) 25% i.e. 5 projects have value as 1,2,2,2,0
3) 40% i.e. 8 projects have value as 3,3,3,3,3,3,3,3
So to derive the median, are we suppose to arrange the number in sequence i.e. ascending ?
0,1,2,2,2,3,3,3,3,3,3,3,3,4,5,6,7,8,8
Is my understanding correct Bunuel?
If a set has odd number of terms the median of a set is the middle number when arranged in ascending or descending order;
If a set has even number of terms the median of a set is the average of the two middle terms when arranged in ascending or descending order.So if there are 20 projects,
35% i.e. 7 projects have 2 or fewer employees assigned to each project, for example: 0, 0, 1, 1, 1, 2, 2;
40% i.e. 8 projects have exactly 3 employees assigned to each project: 3, 3, 3, 3, 3, 3, 3, 3;
25% i.e. 5 projects have 4 or more employees assigned to each project, for example: 4, 5, 6, 7, 8;
0, 0, 1, 1, 1, 2, 2, 3, 3,
3, 3, 3, 3, 3, 3, 4, 5, 6, 7, 8.
So, as 20 is even, then the median number of employees per project would be the average of two middle terms: 10th and 11th --> (3+3)/2=3.
Hope it helps.