Archit3110 wrote:
Bunuel wrote:
Working alone Jerry can complete a work in 6 minutes. Working alone, Adam can complete a work in 8 minutes. Working together, Jerry leaves the work after 2 minutes. How long will it take Adam to complete the work?
A. 2 minutes
B. 3 minutes
C. 10/3 minutes
D. 5 minutes
E. 10 minutes
GMATinsight :
Sir, I solved the question using below method , but I am not able to get option C which is correct answer ...
Rate of jerry = x/6 and rate of Adam= x/8
combined rate : x/6+x/8 = 7x/24 and work would be x.24/7
work done in 2 mins: x.(7/24) * 2 = 7x/12
work left =x - 7x/12 = 5x/12
time Adam will take : work = rate * time
5x/12=x/8* time
time : 10/3 IMO C
This question can be solved in two ways
Method 1:Jerry's 1 minute work = 1/6
Adam's 1 minute work = 1/8
Work done by Jerry in 2 minutes = 2/6 = 1/3
Remaining work = 1 - (1/3) = 2/3
Adam can finish (1/8) work in 1 minute
Adam will finish (2/3) work in (2/3)*8 = 16/3 minutes
But Adam worked for first two minutes with Adam hence
Additional time for which Adam worked alone = 16/3 - 2 - 10/3
Answer: Option C
Method 2Let work = LCM of 8 and 6 = 24 units
Jerry's 1 minute work = 24/6 = 4 units
Adam's 1 minute work = 24/8 = 3 units
Jerry's work done in 2 minutes = 2*4 = 8 units
Remaining work = 24 - 8 = 16 units
Time taken by Adam to finish 16 unit work = 16/3 minutes
Extra time that Adam worked alone for = 16/3 - 2 = 10/3 minutes
Answer: Option C