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A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15

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A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15  [#permalink]

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New post 17 Feb 2016, 22:41
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Question Stats:

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A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15, respectively. If some of the nuts of one of the three types are removed, which of the following could be the ratio of pecans to cashews to almonds remaining in the bowl?

i. 1 : 2 : 3

ii. 2 : 3 : 4

iii. 4 : 7 : 10


A. I only

B. II only

C. III only

D. I and III only

E. II and III only

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Re: A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15  [#permalink]

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New post 17 Feb 2016, 22:46
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1
Official Answer on Manhattanprep.

To solve this question, it’s necessary to understand that if only one kind of nut is removed, the ratio of the two remaining nuts must remain unchanged. That means our correct answers must have a ratio of two nuts that corresponds to one of the nut to nut ratios we started with.

i. The ratio 2 : 3 is the same as the given ratio 10 : 15. If one pecan were removed, the new ratio would be 5 : 10 : 15, or 1 : 2 : 3.

ii. None of the nuts currently have a ratio of 3 : 4. The cashews and almonds do have a ratio of 2 : 3, but there are not enough pecans in the bowl to complete the ratio.

iii. The ratio 4 : 10 is the same as the given ratio 6 : 15. To see this, multiply the ratio by 3/2 . The new ratio is 6 : 10.5 : 15. Unfortunately, this means that there are fewer cashews that this ratio would require. Removing cashews won’t create the desired ratio.

The correct answer is (A).
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Re: A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15  [#permalink]

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New post 17 Feb 2016, 22:56
IMO : A

I don’t know the standard approach for this sum, but I just tried number plug in method
6:10:15
Which means 6x,10x,15x
So probably 6,10,15
12,20,30
18,30,45
24,40,60
No we try to fit with answer 6,10 ,15 to be fitted with
1:2:3 ( 2 & 3 direct fit when we multiply 5) , reduce 6 by one number 5
5, 10 15 (1:2:3)
So A works
Remaining I tried it doesn’t get fit
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A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15  [#permalink]

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New post 17 Feb 2016, 23:02
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jasper20151012 wrote:
A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15, respectively. If some of the nuts of one of the three types are removed, which of the following could be the ratio of pecans to cashews to almonds remaining in the bowl?

i. 1 : 2 : 3

ii. 2 : 3 : 4

iii. 4 : 7 : 10


A. I only

B. II only

C. III only

D. I and III only

E. II and III only


Hi,
we have ratios of three items as 6:10:15..

restriction


we can remove nuts only from one bowl..

inference of restriction


the ratio between the other two will remain the same

solution


lets see the choices..

i. 1 : 2 : 3
the ratio 10:15 is same as 2:3..
so the nuts are removed from 1st bowl..
1:2:3 will mean 5:10:15.. so 1 nut is removed from 1st bowl...
POSSIBLE


ii. 2 : 3 : 4
the corresponding ratios are 6:10:15..
no two ratios are equal in earlier and present..
so not possible..
\(2:3\neq{6:10}\)..
\(2:4\neq{6:15}\)..
\(3:4\neq{10:15}\)..
so NOT POSSIBLE.


iii. 4 : 7 : 10
same reason as ii..
NOT POSSIBLE..


ANS A
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1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html


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Re: A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15  [#permalink]

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New post 28 May 2017, 16:22
i managed to get this correct by implementing a shorter method. not sure if this can be applied to other/similar problems, so lmk what you think:

GIVEN-- 6:10:15:31
CONSTRAINT: can only remove nuts from ONE jar

i. 1 : 2 : 3

- 1:2:3:6 (total).
NOTICE YOU CAN MULTIPLY BY 5 (to get us as close to 31 as possible).
- Result: 5:10:15:30.
* We need to make the following adjustments: 1 (6 is missing 1, giving us "5" in this example. Therefore, only removing nut from ONE jar). 2:3 is the same proportion as 10:15. CORRECT.

ii. 2 : 3 : 4

- 2:3:4:9 (total).
NOTICE YOU CAN MULTIPLY BY 3 (to get us as close to 31 as possible).
- Result: 6:9:12:27.
* We need to make the following adjustments: (9 should be "10". 12 should be "15". Therefore, need to remove nuts from TWO jars). INCORRECT.

iii. 4 : 7 : 10

- 4:7:10:21
DO NOT NEED TO MULTIPLY BY ANYTHING B/C MULTIPLYING 2X WOULD GIVE YOU SAME DIFFERENCE (+/- 10)
- Result: same
* We need to make the following adjustments: (4 should be "5". 7 should be "10". 10 should be "15". Therefore, need to remove nuts from THREE jars). INCORRECT.

Again, please let me know your thoughts! If this was helpful, kudos please :)
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Re: A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15  [#permalink]

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New post 25 Aug 2017, 16:07
As always, get it from answer,

Given:
P:C:A = 6x:10x:15x
Some nuts removed from one of three types
Which of the following be the ratio?

i. 1 : 2 : 3

ii. 2 : 3 : 4

iii. 4 : 7 : 10

From the given ratio we need to get the above three answer,
NOTE: all the number should be divisible by common number(dividend)
Let's say some quantity removed from pecans, then we need to figure out the divisor divisible by common dividend

i) if removed 1 from 6 changes to 5 =>5:10:15 = 1:2:3
SATISFIED
ii) if anything removed from cashew, we not going to get divisor that is divisible by common dividend
NOT SATISFIED
iii) if removed a number we can able to solve,
OPTION 1:- 6:10:14 = 3:5:7
whatever may the number we get reduced still we gonna get same amount of peacans and cashew.
NOT SATISFIED

Only satisfied option is 1

Answer will be 'A'
Re: A bowl contains pecans, cashews, and almonds in a ratio of 6 : 10 : 15 &nbs [#permalink] 25 Aug 2017, 16:07
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