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A ring of paint that is w units wide completely divides a circular
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09 Mar 2020, 09:35
09 Mar 2020, 09:35
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A ring of paint that is w units wide completely divides a circular racetrack's inner and outer lanes, both of which are r units wide and enclose a circular field that is 2w units wide. Since the boundaries that divide the field, inner lane, ring of paint, and outer lane from each other have no width, a person running in a lane may run anywhere in that lane or on the boundaries of that lane. If Person X uses the inner lane and runs the shortest possible distance once around the track, and Person Y uses the outer lane and runs the shortest possible distance once around the track, how much farther, in units, does Person Y run than Person X ?
(1) w + r = 4
(2) w = 3r
(1) w + r = 4
(2) w = 3r
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Re: A ring of paint that is w units wide completely divides a circular
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25 Apr 2020, 05:50
25 Apr 2020, 05:50
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Hello,
I am unable to visualize the this question and hence unable to understand the solution. Could someone please explain.
Thanks.
I am unable to visualize the this question and hence unable to understand the solution. Could someone please explain.
Thanks.
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Re: A ring of paint that is w units wide completely divides a circular
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10 Mar 2020, 00:32
10 Mar 2020, 00:32
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Expert Reply
770GMAT wrote:
A ring of paint that is w units wide completely divides a circular racetrack's inner and outer lanes, both of which are r units wide and enclose a circular field that is 2w units wide. Since the boundaries that divide the field, inner lane, ring of paint, and outer lane from each other have no width, a person running in a lane may run anywhere in that lane or on the boundaries of that lane. If Person X uses the inner lane and runs the shortest possible distance once around the track, and Person Y uses the outer lane and runs the shortest possible distance once around the track, how much farther, in units, does Person Y run than Person X ?
(1) w + r = 4
(2) w = 3r
(1) w + r = 4
(2) w = 3r
Diamere of Field = 2w/2 = w units
Smallest track on inner ring = 2πw
Smallest track on Outer ring = 2π(w+r+w)
w - Width of paint ring
r - width of inner lane
Question: 2π(w+r+w) - 2πw = ??
i.e. Question: 2π(w+r) = ?
Statement 1: w + r = 4
SUFFICIENT
Statement 2: w = 3r
NOT SUFFICIENT
Answer: Option A
