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Re: A shop sells 5 different types of sweets. In how many different ways [#permalink]
chetan2u wrote:
Bunuel wrote:
A shop sells 5 different types of sweets. In how many different ways a total of 8 sweets can be purchased?

(A) 125
(B) 495
(C) 795
(D) 840
(E) 930



Quickest way : Use partition method and the formula involved.
The equation can be written as \(a+b+c+d+e=8\), and we have find non negative solutions for the same
If there are 4 partitions, the answer would be (8+4)C4=\(\frac{12!}{8!/4!}=\frac{12*11*10*9}{4*3*2}=495\)

You can also calculate each type


B



You distributed 8 boxes of sweets among 5 sweets. That's a great approach.
GMAT Club Bot
Re: A shop sells 5 different types of sweets. In how many different ways [#permalink]
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