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Re: Data Insights Question of the Day [#permalink]
Could someone help me with this question?
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Re: Data Insights Question of the Day [#permalink]
muskaaaanmehra wrote:
Could someone help me with this question?

the-expenses-related-to-sponsoring-a-conference-can-be-immense-an-org-135390.html#p1102226
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Re: Data Insights Question of the Day [#permalink]
Hello Team!
I just have started with the data insight section. I picked up the official guide for preparation and I see it mostly consists of data sufficiently questions and not table or graph analysis questions.

Does anyone know a good source to prepare all kind of data insight questions?

Thanks in advance! :)
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Re: Data Insights Question of the Day [#permalink]
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Hi Ashtha! If you have bought the OG book(hard copy or e-book) , you will be able to access the online question of DI questions that have other types as well.

But, you can also check out our repository of questions as well. There are more than 1000 questions on DI

gmat-di-question-directory-by-topic-418297.html#p3265387
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Re: Data Insights Question of the Day [#permalink]
Thanks @bottomjee I will have a look!
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Re: Data Insights Question of the Day [#permalink]
how can we solve in-semanta-there-are-52-major-businesses-10-in-the-manufacturing-sec-424986.html

second i can’t figure out how logic works in here
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Re: Data Insights Question of the Day [#permalink]
Got answer in diagram 32 is denominator and 10 is manufacturing so 5/16

nah.. 5 servie + 1 manufacture 3/16 so 18.75% sorry for demusing
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Re: Data Insights Question of the Day [#permalink]
hello, does anyone can help me with "no. 001240" questions from Ebook of OG? I can’t find it on Gmatclub forum section

and also "no. 001022-06" too.
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Re: Data Insights Question of the Day [#permalink]
1 troy ounce = 31.1 gram so 100 grams will be approximately 3.21 troy ounces. So the year end prize in 2008 is 3.21* 600 = 1926 which can be rounded down to 1900 . the prize at 2010 year end will be 3.21*900 = 2889.

adding all the number of arrivals before 1 pm gives you around 7900 vehicles whereas accumulation is around 7000. the question mentions that you should select before 1pm if the condition gets satisfied before 1pm regardless of what happens after 1 pm so the answer before 1pm is correct
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Re: Data Insights Question of the Day [#permalink]
Why do we need to add the values? The graph says "cumulative arrivals" and "Cumulative departures" doesn’t that mean all values are prior value plus number of arrivals/departures in the next hour? According to me, we just need to compare the cumulative arrivals value in the graph to accumulation. And accumulation is simply the the total(cumulative) number of cars arrived minus total(cumulative) number of cars left. In above question we just need to see if cumulative arrivals value as represented in the graph gets above accumulation value before 1PM at least once or not. This occurrence happens when first departure happens. This can be seen in the graph. Also, the accumulation will be max when cumulative arrival and cumulative departure are furthest apart(just expanding on what values we can obtain from the graph)
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Re: Data Insights Question of the Day [#permalink]
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Re: Data Insights Question of the Day [#permalink]
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Re: Data Insights Question of the Day [#permalink]
From a group of J employees, K will be selected, at random, to sit in a line of K chairs. There are absolutely no restrictions, either in the selection process nor in the order of seating — both are entirely random. What is the probability that the employee Lisa is seated exactly next to employee Phillip?

(1) K = 15
(2) K = J

In this DS question can anyone explain the calculation. How do I solve for the numerator?
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Re: Data Insights Question of the Day [#permalink]
VerbalFaker wrote:
Why do we need to add the values? The graph says "cumulative arrivals" and "Cumulative departures" doesn’t that mean all values are prior value plus number of arrivals/departures in the next hour? According to me, we just need to compare the cumulative arrivals value in the graph to accumulation. And accumulation is simply the the total(cumulative) number of cars arrived minus total(cumulative) number of cars left. In above question we just need to see if cumulative arrivals value as represented in the graph gets above accumulation value before 1PM at least once or not. This occurrence happens when first departure happens. This can be seen in the graph. Also, the accumulation will be max when cumulative arrival and cumulative departure are furthest apart(just expanding on what values we can obtain from the graph)

that is what i thought. But the graph does not indicate that the accumulation exceed the cumulative arrival line either before or after 1 p.m.
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Re: Data Insights Question of the Day [#permalink]
Accumulation can nevermind exceed cumulative arrivals unless there were cars stored prior to counting arrivals. They will be equal until first departure. Which happens before 1pm hence the answer
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Re: Data Insights Question of the Day [#permalink]
Can anyone tell me if there are any other free FOCUS mocks other than
2 official,
1 egmat and
1 experts global?
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Re: Data Insights Question of the Day [#permalink]
Yes there are a few free mocks

Kaplan
Veritas
GMAT Club
Princeton Review
e-GMAT
Experts’ Global
Best My Test
TTP Diagnostic Quant and Verbal

This should be a good list let me know if you need anything else

Approach verbal with caution and I am not sure if all of these have Data Insights incorporated yet or not
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Re: Data Insights Question of the Day [#permalink]
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