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Updated on: 09 Oct 2025, 01:09
Originally posted by Sajjad1994 on 15 Mar 2020, 07:27.
Last edited by Bunuel on 09 Oct 2025, 01:09, edited 6 times in total.
Last edited by Bunuel on 09 Oct 2025, 01:09, edited 6 times in total.
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In calculating the final score for the contest, the weight loss for a fitness trainer's third client (Client 3) had equal weighting as the weight loss on Client 2.: Yes
The median final score for all fitness trainers was 27.40: Yes
In the data set for "Client 1" clients who worked with a fitness trainer having four years of experience, the range was 8.: No
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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39% (03:07) correct
61%
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During the Summer Fitness Challenge, 27 individuals entered the contest to lose weight. Each contestant was categorized by weight group into 3 groups. Each fitness trainer, 9 in total, was assigned to one contestant from each weight group. The number of kilograms lost by the end of the 8-week session is recorded in the table below.
The final score for the contest was computed as a weighted mean of the kilograms lost for client 1, client 2, and client 3, using the same weights for each fitness trainer.
For each of the following statements, select Yes if the statement is true based on the information provided; otherwise select No.
TA.jpg [ 56.11 KiB | Viewed 5152 times ]
| Years of Experience | Fitness Trainer | Client 1 (100- 125kg) | Client 2 (125- 150kg) | Client 3 (150- 250kg) | Final Score |
|---|---|---|---|---|---|
| 1 | Susan | 10 | 20 | 35 | 20.5 |
| 3 | Megan | 14 | 22 | 45 | 25.7 |
| 4 | Tom | 25 | 35 | 70 | 41.5 |
| 4 | Brad | 20 | 25 | 66 | 35.3 |
| 2 | Peter | 22 | 28 | 49 | 31.9 |
| 1 | Melissa | 25 | 33 | 62 | 38.5 |
| 3 | Nick | 16 | 18 | 52 | 27.4 |
| 2 | Russel | 14 | 15 | 39 | 21.8 |
| 2 | Patty | 8 | 12 | 22 | 13.4 |
The final score for the contest was computed as a weighted mean of the kilograms lost for client 1, client 2, and client 3, using the same weights for each fitness trainer.
For each of the following statements, select Yes if the statement is true based on the information provided; otherwise select No.
Attachment:
TA.jpg [ 56.11 KiB | Viewed 5152 times ]
| Yes | No | |
| In calculating the final score for the contest, the weight loss for a fitness trainer's third client (Client 3) had equal weighting as the weight loss on Client 2. | ||
| The median final score for all fitness trainers was 27.40 | ||
| In the data set for "Client 1" clients who worked with a fitness trainer having four years of experience, the range was 8. |
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Official Answer
In calculating the final score for the contest, the weight loss for a fitness trainer's third client (Client 3) had equal weighting as the weight loss on Client 2.: Yes
The median final score for all fitness trainers was 27.40: Yes
In the data set for "Client 1" clients who worked with a fitness trainer having four years of experience, the range was 8.: No
17 Mar 2020, 06:58
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a)Let the weights for Client1 -x,Client 2-y,Client3-z,
Now per the option it is asking whether y=z
So let's take y=z and then recheck it with the data in the table
So let's form two equations from the table
25X+105Y=41.5-Tom
X= x/(x+2y),Y=y/(x+2y)
25X+95Y= 38.5-Melissa
So solving for X&Y, so we get Y=0.3, so it's 30%,X=0.4-> 40%
So now let's check these value for let's suppose Megan so = 14*.4 + 67*
.3= 25.7, so our calculation is right. And hence answer is Yes
b)Yes the median is 27.40(since it's the 5th value among the 9 values)
c)No,the range comes around 5(25-20)
Posted from my mobile device
Now per the option it is asking whether y=z
So let's take y=z and then recheck it with the data in the table
So let's form two equations from the table
25X+105Y=41.5-Tom
X= x/(x+2y),Y=y/(x+2y)
25X+95Y= 38.5-Melissa
So solving for X&Y, so we get Y=0.3, so it's 30%,X=0.4-> 40%
So now let's check these value for let's suppose Megan so = 14*.4 + 67*
.3= 25.7, so our calculation is right. And hence answer is Yes
b)Yes the median is 27.40(since it's the 5th value among the 9 values)
c)No,the range comes around 5(25-20)
Posted from my mobile device
General Discussion
03 Mar 2025, 10:15
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what is this formula X= x/(x+2y),Y=y/(x+2y)?
And Why the mean is varying all over the table? (It's not following the formula: \(\frac{(x+y+z)}{3}\) for some reason)
And Why the mean is varying all over the table? (It's not following the formula: \(\frac{(x+y+z)}{3}\) for some reason)
Apt0810
