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Each entry in the multiplication table above is an integer that is eit

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Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 21 Sep 2019, 18:09
2
1
23
00:00
A
B
C
D
E

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  95% (hard)

Question Stats:

43% (02:02) correct 57% (01:50) wrong based on 405 sessions

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Each entry in the multiplication table above is an integer that is either positive, negative, or zero. What is the value of a ?

(1) h ≠ 0
(2) c = f


DS95850.01


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2019-09-22_0607.png
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Re: Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 21 Sep 2019, 18:19
5
2
h= b*c
h is not equal to zero so neither b nor c is zero.
but this doesn't tell about a.
not sufficient.

Statement-2
c=f
a*c= f
this expression can hold if c=f=0
a can have any value.
and If C=F= any value, a is always 1.
not sufficient

Statement 1+2
value of c is except zero.
and for these value, a is always 1.

C is correct answer.
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Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 07 Nov 2019, 14:37
2
1
1
gmatt1476 wrote:
Image
Each entry in the multiplication table above is an integer that is either positive, negative, or zero. What is the value of a ?

(1) h ≠ 0
(2) c = f


DS95850.01


Attachment:
2019-09-22_0607.png


First, the significance of multiplication table needs to be understood.
This is like a 3*3 matrix and results in the following products ,
a^2 = d
a*b = e
a*c = f
a*b = e
b^2 = g
b*c = h
c*a = f
c*b = h
c^2 = j

Now statement 1 says ,
h is not equal to 0.
That means neither b nor c equals zero as b*c = h;
But we cant tell anything about a.

Statement 2 says , c =f
a*c = f
a*c = c
c*(a-1) = 0
Now a can be equal to 1 or c can be equal to 0 .
So a can be equal to 1 or a may not be equal to 1 .
Not sufficient.

Together ,
c *(a-1) = 0
From statement h not equal to zero means c is not equal to zero.
If c is not equal to zero then (a-1) = 0 ( As we can divide the zero by c which is a non zero quantity )
Hence , a = 1
So option C is the answer.

Please give me KUDO s if you liked my explanation.
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Re: Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 19 Nov 2019, 17:47
Bunuel

Can you help me with this question?

1. I got confused by what the table is. The "x" on the top left corner: I read it as x and not multiplication.

2. Even if I go past point 1, I am still not sure on how to approach this question.
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Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 28 Nov 2019, 09:14
TheNightKing wrote:
Bunuel

Can you help me with this question?

1. I got confused by what the table is. The "x" on the top left corner: I read it as x and not multiplication.

2. Even if I go past point 1, I am still not sure on how to approach this question.


Hey TheNightKing ,
Please refer to my explanation above. Please let me know if you have any doubt.
Also, please give me kudos if you find it helpful.
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Re: Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 28 Nov 2019, 09:29
Quote:
Hey TheNightKing ,
Please refer to my explanation above. Please let me know if you have any doubt.
Also, please give me kudos if you find it helpful.



Thank you Sir. Since you wrote each of the multiplications explicitly it became easier to see what's happening.
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Re: Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 01 Jan 2020, 22:39
Hey sayan
I am not able to understand the login behind the multiplication results explanations
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Re: Each entry in the multiplication table above is an integer that is eit  [#permalink]

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New post 09 Jun 2020, 06:24
1
gmatt1476 wrote:
Image
Each entry in the multiplication table above is an integer that is either positive, negative, or zero. What is the value of a ?

(1) h ≠ 0
(2) c = f
DS95850.01


any letter is an integer positive, negative or zero

(1) insufic
bc=h≠0, so (b,c,h) are not 0
no info about a or d

(2) insufic
c=f, ac=f, ac=c, ac=c
c=0, then, a=anything
a=1, then, c=anything

(1/2) sufic
c≠0, thus,
a=1, then, c=anything≠0

Ans (C)
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Re: Each entry in the multiplication table above is an integer that is eit   [#permalink] 09 Jun 2020, 06:24

Each entry in the multiplication table above is an integer that is eit

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