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GMAT Club Around The World!!! In the expression above, if a ≠ b, and a

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Bunuel
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GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   31 Dec 2020, 18:00
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E

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25% (medium)

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73% (01:02) correct 27% (00:55) wrong based on 48 sessions
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\(\frac{a^2 + b}{b-a}\)

In the expression above, if a ≠ b, and a is replaced with -b, the reciprocal of the resulting expression is equal to:


A. \(\frac{1+b}{2}\)

B. \(\frac{2}{1+b}\)

C. \(\frac{1-b}{2}\)

D. \(\frac{2}{1-b}\)

E. \(\frac{2}{b-1}\)




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B
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   31 Dec 2020, 18:23
The answer is (A).

Replace a with (-b), and we get

(b^2 + b) / (b + b)
= (b + 1) / 2
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   31 Dec 2020, 20:17
B. 2/1+b

answer is b ) 2/(1+b)
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   31 Dec 2020, 22:41
IMO B

We need to find the reciprocal of the resulting expression after replacing a with -b in the given expression.

>>>> 1/((b^2 + b) /b+b)

factoring out b, we get

>>1/(b(b+1)/2b)
>> 2b/b+1
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   01 Jan 2021, 00:17
IMO B

\(\frac{a^2+b}{b−a}\)
replace a with -b

\(\frac{b-a}{a^2+b }\) = ??

= \(\frac{b-(-b)}{(-b)^2+b }\)

= \(\frac{b+b}{b(b+1)}\)

= \(\frac{2}{b+1}\)
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   01 Jan 2021, 02:38
Replacing a with -b

\(a^2\) + b = \(b^2\)+b
b-a = b-(-b) = b+b = 2b

New eq = (\(b^2\)+b)/2b = (b+1)/2

Reciprocal = 2/(b+1)

IMO Option B
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   02 Jan 2021, 09:00
Correct Answer B

(a^2+b)/(b−a)

In the expression above, if a ≠ b, and a is replaced with -b, the reciprocal of the resulting expression is equal to:

(a^2+b)/(b−a)
a= -b
(b^2+b)/(b+b) =b(b+1)/2b

Reciprocal
=2/(b+1)
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GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   Updated on: 07 Jan 2021, 20:16
(a^2+b)/(b−a) replacing a with -b

= (b^2 +b)/2b= (1+b)/2.

Question is asking reciprocal, so, 2/(1+b)

So, Ans. B. :)

Originally posted by TarunKumar1234 on 02 Jan 2021, 10:45.
Last edited by TarunKumar1234 on 07 Jan 2021, 20:16, edited 1 time in total.
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   02 Jan 2021, 22:32
(a^2 + b)/(b-a)
replace a with -b
(b^2 +b)/(b+b) = b(b+1)/2b = (b+1)/2
The reciprocal of the result will be 2/(1+b)

Correct answer will be B
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink] New post   03 Jan 2021, 14:08
Bunuel wrote:
\(\frac{a^2 + b}{b-a}\)

In the expression above, if a ≠ b, and a is replaced with -b, the reciprocal of the resulting expression is equal to:


A. \(\frac{1+b}{2}\)

B. \(\frac{2}{1+b}\)

C. \(\frac{1-b}{2}\)

D. \(\frac{2}{1-b}\)

E. \(\frac{2}{b-1}\)




Happy New Year Cape Verde, Greenland/Ittoqqortoormiit, and Portugal/Azores islands!

Dec 31 Event: GMAT Club Around The World!
(38 new questions posted every hour time zone on Dec 31!)



when a is replaced with -b, the reciprocal of expression:

[(b+1)/2]^(-1)

=2/(b+1)

IMO option B is the answer.
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Re: GMAT Club Around The World!!! In the expression above, if a ≠ b, and a [#permalink]
03 Jan 2021, 14:08
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