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If A, B and C are digits and AB#0, what is the value of B?
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Updated on: 10 Dec 2012, 02:53
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54% (01:51) correct 46% (02:05) wrong based on 325 sessions
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If A, B and C are digits and AB#0, what is the value of B? (1) AB +BA ________ AAC (2) A=1 I am confused on the OA. Consider following situations  82 91 +28 +19 ____ _____ 110 110
Hence, B can be 2 or 1. So (1) is not sufficient.
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Originally posted by babusona on 08 Apr 2012, 14:19.
Last edited by Bunuel on 10 Dec 2012, 02:53, edited 2 times in total.
Edited the question.




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Re: If A B C are digits and AB not equals to 0, what is the val
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08 Apr 2012, 14:32
babusona wrote: If A B C are digits and AB not equals to 0, what is the value of B? (1) AB +BA _______________ AAC
(2) A=1
I am confused on the OA. Consider following situations  82 91 +28 +19 ____ _____ 110 110
Hence, B can be 2 or 1. So (1) is not sufficient. In your first example A has different values, which cannot happen. If A, B and C are digits and AB#0, what is the value of B?(1) AB + BA = AAC > A=1 (A can not be more than 1, as the sum of 2 twodigit numbers is always less than 200) > 1B+B1=11C > B=9 (B can not be less than 8 as 18+81=99, not a three digit number) > 19+91=110. Sufficient. (2) A = 1. Not sufficient. Answer: A.
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Re: If A B C are digits and AB not equals to 0, what is the val
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13 Apr 2012, 22:58
Bunuel wrote: babusona wrote: If A B C are digits and AB not equals to 0, what is the value of B? (1) AB +BA _______________ AAC
(2) A=1
I am confused on the OA. Consider following situations  82 91 +28 +19 ____ _____ 110 110
Hence, B can be 2 or 1. So (1) is not sufficient. In your first example A has different values, which cannot happen. If A, B and C are digits and AB#0, what is the value of B?(1) AB + BA = AAC > A=1 (A can not be more than 1, as the sum of 2 twodigit numbers is always less than 200) > 1B+B1=11C > B=9 (B can not be less than 8 as 18+81=99, not a three digit number) > 19+91=110. Sufficient. (2) A = 1. Not sufficient. Answer: A. Hi what does AB#0 mean? what is the approach to solve such question in Data Sufficiency?



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Re: If A B C are digits and AB not equals to 0, what is the val
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14 Apr 2012, 01:49
ps25 wrote: Hi what does AB#0 mean? what is the approach to solve such question in Data Sufficiency? AB#0 means \(AB\neq{0}\), the product of A and B does not equal to zero. This way we are told that neither A nor B equals to zero. As for the solution it's given in above post. Please ask if anything remains unclear.
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If A,B and C are digits and AB is not 0, what is the value
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10 Dec 2012, 02:51
amitdgr wrote: If A,B and C are digits and AB is not 0, what is the value of B ?
(1) AB + BA = AAC
(2) A = 1 I think the answer is D. Statement 1: this statement has already been established as sufficient in the previous posts. Statement2: A=1 AB +BA  AAC In the above addition, observe the units place: (digit) B + (digit) A = (digit) C Now observe the tens place: (digit) A + (digit) B = (digit) A? > this means that a digit has carried over from the addition of the units digits. Now, because a digit has carried over, this implies that the digit A+B is a two digit number> Now, the only way A+B or (1+B) will be a two digit number is if B = 9. therefore statement B is sufficient as well.



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Re: If A,B and C are digits and AB is not 0, what is the value
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10 Dec 2012, 02:58
geezer0305 wrote: amitdgr wrote: If A,B and C are digits and AB is not 0, what is the value of B ?
(1) AB + BA = AAC
(2) A = 1 I think the answer is D. Statement 1: this statement has already been established as sufficient in the previous posts. Statement2: A=1 AB +BA  AAC In the above addition, observe the units place: (digit) B + (digit) A = (digit) C Now observe the tens place: (digit) A + (digit) B = (digit) A? > this means that a digit has carried over from the addition of the units digits. Now, because a digit has carried over, this implies that the digit A+B is a two digit number> Now, the only way A+B or (1+B) will be a two digit number is if B = 9. therefore statement B is sufficient as well. You cannot use information given in the first statement (AB + BA = AAC) for the second. Check complete solution here: ifabandcaredigitsandab0whatisthevalueofb130419.html#p1071580Hope it helps.
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Re: If A, B and C are digits and AB#0, what is the value of B?
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10 Dec 2012, 04:42
Ans: The only possibility of getting AA after adding A and B is if A=1 (adding two digits cannot give a number greater than 20). Since the addition of two numbers gives a threedigit number, therefore A+B>equal to 10 , that leaves B to be only 9. Therefore the answer is (D).
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Re: If A, B and C are digits and AB#0, what is the value of B?
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10 Dec 2012, 04:45
priyamne wrote: Ans: The only possibility of getting AA after adding A and B is if A=1 (adding two digits cannot give a number greater than 20). Since the addition of two numbers gives a threedigit number, therefore A+B>equal to 10 , that leaves B to be only 9. Therefore the answer is (D). Correct answer is A, not D. Check here: ifabandcaredigitsandab0whatisthevalueofb130419.html#p1071586
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Re: If A, B and C are digits and AB#0, what is the value of B?
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05 Nov 2015, 04:45
If A, B and C are digits and AB#0, what is the value of B?
(1) AB +BA ________ AAC
Important takeaway here is that for the tens digits: A+B results in AA. This means that:
1. A+B is at least 10
Therefore the B+A in the units place is at least 10 and we have to carry a 1 over to the tens digits (cannot be 2 since A+B is at most 9+9=18)
2. A+B in the tens places has a units digit of A
This means that A+B+1 (carried over from B+A in the units places) has a units digit of A. To get a units digit of A, B+1 must be 10.
Therefore B=9
SUFFICIENT
(2) A=1
We know A is 1 but we have no idea what B is
INSUFFICIENT
Answer is A



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Re: If A, B and C are digits and AB#0, what is the value of B?
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06 Nov 2015, 14:30
Algebraic really works fast for this kind of question:
A=x, B=y
it means
y+y=10x+x, 2y=11x
since 1<=x<=9, 0<=y<=9
so this possibility can't rise. there must be one from z+x=c
so 2y+1=11x
so x=1, y=5
sufficient



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If A, B and C are digits and AB#0, what is the value of B?
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21 Aug 2018, 13:06
1. AB +BA = AAC
10A+B+10B+A=100A+10A+C 11(A+B)100A+10A=C 11(A+B)110A=C 11(A+B10A)=C 11(B9A)=C
Since C is a digit, it can not be 11, so the only one option is when (B9A)=0, so C=0. In this case the only way is B=9 and A=1. Sufficient.
2. A=1
Not Sufficient
Answer A.




If A, B and C are digits and AB#0, what is the value of B?
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21 Aug 2018, 13:06






