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Intern  Joined: 11 Sep 2011
Posts: 14
If A, B and C are digits and AB#0, what is the value of B?  [#permalink]

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23 00:00

Difficulty:   75% (hard)

Question Stats: 54% (01:53) correct 46% (02:03) wrong based on 325 sessions

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If A, B and C are digits and AB#0, what is the value of B?

(1)
AB
+BA
________
AAC

(2) A=1

I am confused on the OA. Consider following situations -
82 91
+28 +19
____ _____
110 110

Hence, B can be 2 or 1. So (1) is not sufficient.

Originally posted by babusona on 08 Apr 2012, 13:19.
Last edited by Bunuel on 10 Dec 2012, 01:53, edited 2 times in total.
Edited the question.
Math Expert V
Joined: 02 Sep 2009
Posts: 64318
Re: If A B C are digits and AB not equals to 0, what is the val  [#permalink]

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2
5
babusona wrote:
If A B C are digits and AB not equals to 0, what is the value of B?
(1) AB
+BA
_______________
AAC

(2) A=1

I am confused on the OA. Consider following situations -
82 91
+28 +19
____ _____
110 110

Hence, B can be 2 or 1. So (1) is not sufficient.

In your first example A has different values, which cannot happen.

If A, B and C are digits and AB#0, what is the value of B?

(1) AB + BA = AAC --> A=1 (A can not be more than 1, as the sum of 2 two-digit numbers is always less than 200) --> 1B+B1=11C --> B=9 (B can not be less than 8 as 18+81=99, not a three digit number) --> 19+91=110. Sufficient.

(2) A = 1. Not sufficient.

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##### General Discussion
Intern  B
Joined: 04 Jan 2012
Posts: 17
Re: If A B C are digits and AB not equals to 0, what is the val  [#permalink]

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1
Bunuel wrote:
babusona wrote:
If A B C are digits and AB not equals to 0, what is the value of B?
(1) AB
+BA
_______________
AAC

(2) A=1

I am confused on the OA. Consider following situations -
82 91
+28 +19
____ _____
110 110

Hence, B can be 2 or 1. So (1) is not sufficient.

In your first example A has different values, which cannot happen.

If A, B and C are digits and AB#0, what is the value of B?

(1) AB + BA = AAC --> A=1 (A can not be more than 1, as the sum of 2 two-digit numbers is always less than 200) --> 1B+B1=11C --> B=9 (B can not be less than 8 as 18+81=99, not a three digit number) --> 19+91=110. Sufficient.

(2) A = 1. Not sufficient.

Hi what does AB#0 mean? what is the approach to solve such question in Data Sufficiency?
Math Expert V
Joined: 02 Sep 2009
Posts: 64318
Re: If A B C are digits and AB not equals to 0, what is the val  [#permalink]

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ps25 wrote:
Hi what does AB#0 mean? what is the approach to solve such question in Data Sufficiency?

AB#0 means $$AB\neq{0}$$, the product of A and B does not equal to zero. This way we are told that neither A nor B equals to zero.

As for the solution it's given in above post. Please ask if anything remains unclear.
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Posts: 12
Location: United States
Concentration: Entrepreneurship, Marketing
WE: Research (Energy and Utilities)
If A,B and C are digits and AB is not 0, what is the value  [#permalink]

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amitdgr wrote:
If A,B and C are digits and AB is not 0, what is the value of B ?

(1) AB + BA = AAC

(2) A = 1

I think the answer is D.

Statement 1: this statement has already been established as sufficient in the previous posts.

Statement2: A=1

AB
+BA
-------
AAC

In the above addition, observe the units place: (digit) B + (digit) A = (digit) C
Now observe the tens place: (digit) A + (digit) B = (digit) A? -----> this means that a digit has carried over from the addition of the units digits. Now, because a digit has carried over, this implies that the digit A+B is a two digit number----> Now, the only way A+B or (1+B) will be a two digit number is if B = 9.

therefore statement B is sufficient as well.
Math Expert V
Joined: 02 Sep 2009
Posts: 64318
Re: If A,B and C are digits and AB is not 0, what is the value  [#permalink]

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geezer0305 wrote:
amitdgr wrote:
If A,B and C are digits and AB is not 0, what is the value of B ?

(1) AB + BA = AAC

(2) A = 1

I think the answer is D.

Statement 1: this statement has already been established as sufficient in the previous posts.

Statement2: A=1

AB
+BA
-------
AAC

In the above addition, observe the units place: (digit) B + (digit) A = (digit) C
Now observe the tens place: (digit) A + (digit) B = (digit) A? -----> this means that a digit has carried over from the addition of the units digits. Now, because a digit has carried over, this implies that the digit A+B is a two digit number----> Now, the only way A+B or (1+B) will be a two digit number is if B = 9.

therefore statement B is sufficient as well.

You cannot use information given in the first statement (AB + BA = AAC) for the second.

Check complete solution here: if-a-b-and-c-are-digits-and-ab-0-what-is-the-value-of-b-130419.html#p1071580

Hope it helps.
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Intern  Joined: 24 Apr 2012
Posts: 44
Re: If A, B and C are digits and AB#0, what is the value of B?  [#permalink]

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Ans: The only possibility of getting AA after adding A and B is if A=1 (adding two digits cannot give a number greater than 20). Since the addition of two numbers gives a three-digit number, therefore A+B>equal to 10 , that leaves B to be only 9. Therefore the answer is (D).
Math Expert V
Joined: 02 Sep 2009
Posts: 64318
Re: If A, B and C are digits and AB#0, what is the value of B?  [#permalink]

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priyamne wrote:
Ans: The only possibility of getting AA after adding A and B is if A=1 (adding two digits cannot give a number greater than 20). Since the addition of two numbers gives a three-digit number, therefore A+B>equal to 10 , that leaves B to be only 9. Therefore the answer is (D).

Correct answer is A, not D. Check here: if-a-b-and-c-are-digits-and-ab-0-what-is-the-value-of-b-130419.html#p1071586
_________________
Manager  Joined: 09 Nov 2014
Posts: 52
Concentration: Finance
GMAT 1: 760 Q51 V41
Re: If A, B and C are digits and AB#0, what is the value of B?  [#permalink]

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If A, B and C are digits and AB#0, what is the value of B?

(1)
AB
+BA
________
AAC

Important takeaway here is that for the tens digits: A+B results in AA. This means that:

1. A+B is at least 10

Therefore the B+A in the units place is at least 10 and we have to carry a 1 over to the tens digits (cannot be 2 since A+B is at most 9+9=18)

2. A+B in the tens places has a units digit of A

This means that A+B+1 (carried over from B+A in the units places) has a units digit of A. To get a units digit of A, B+1 must be 10.

Therefore B=9

SUFFICIENT

(2) A=1

We know A is 1 but we have no idea what B is

INSUFFICIENT

Manager  Joined: 13 Sep 2015
Posts: 82
Location: United States
GMAT 1: 770 Q50 V45
GPA: 3.84
Re: If A, B and C are digits and AB#0, what is the value of B?  [#permalink]

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Algebraic really works fast for this kind of question:

A=x, B=y

it means

y+y=10x+x, 2y=11x

since 1<=x<=9, 0<=y<=9

so this possibility can't rise. there must be one from z+x=c

so 2y+1=11x

so x=1, y=5

sufficient
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Joined: 29 Dec 2017
Posts: 363
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Concentration: Marketing, Technology
GMAT 1: 630 Q44 V33 GMAT 2: 690 Q47 V37 GMAT 3: 710 Q50 V37 GPA: 3.25
WE: Marketing (Telecommunications)
If A, B and C are digits and AB#0, what is the value of B?  [#permalink]

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1
1. AB +BA = AAC

10A+B+10B+A=100A+10A+C
11(A+B)-100A+10A=C
11(A+B)-110A=C
11(A+B-10A)=C
11(B-9A)=C

Since C is a digit, it can not be 11, so the only one option is when (B-9A)=0, so C=0. In this case the only way is B=9 and A=1. Sufficient.

2. A=1

Not Sufficient

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Re: If A, B and C are digits and AB#0, what is the value of B?  [#permalink]

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_________________ Re: If A, B and C are digits and AB#0, what is the value of B?   [#permalink] 11 Sep 2019, 00:15

# If A, B and C are digits and AB#0, what is the value of B?  