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If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)

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Joined: 30 Mar 2006
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If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)  [#permalink]

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New post 07 Apr 2006, 11:10
2
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

50% (00:53) correct 50% (00:52) wrong based on 464 sessions

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If \(k\neq{0}\) and \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\), then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-k-0-and-k-3-2k-2-k-x-k-then-x-167913.html

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Andre Crompton
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)  [#permalink]

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New post 07 Apr 2006, 11:20
2
(C) :wink:

k - ( 3 - 2K^2)/k = x/k

k^2 - ( 3 - 2k^2) = x

k^2 - 3 + 2k^2 = x

x = (3k^2) - 3
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)  [#permalink]

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New post 07 Apr 2006, 13:23
I dont understand how the -2k^2 became +2k^2

k^2 - ( 3 - 2k^2) = x

k^2 - 3 + 2k^2 = x
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Andre Crompton
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)  [#permalink]

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New post 07 Apr 2006, 15:10
andrecrompton wrote:
I dont understand how the -2k^2 became +2k^2

k^2 - ( 3 - 2k^2) = x

k^2 - 3 + 2k^2 = x


The brackets open and negative negative make a positive
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)  [#permalink]

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New post 24 Oct 2014, 02:34
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)  [#permalink]

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New post 04 Sep 2018, 02:33
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)   [#permalink] 04 Sep 2018, 02:33
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